Morphocompletion for #4108 ⟨a, b | aababaaab=aa⟩

Back:⟨a, b | aababaaab=aa⟩

Solved by morph:5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aaaaabb ⇒ aababaa
2. aaabaaab ⇒ aababaaa
3. aababaaab ⇒ aa
4. aaaaabaabba ⇒ aababaaaaab
5. aaabaababaaa ⇒ aababaaaaaab
6. aaaaabaaaabb ⇒ aaaaabababaa
7. aababaababaaa ⇒ aaaaab
8. aaaaabaabaaab ⇒ aaaaabababaaa
9. aaaaabababaaab ⇒ aaaaaba
10. aaaaabaabaabba ⇒ aababaaaaabaab
11. aababaababaababaa ⇒ aaaaabaabb
12. aaaaabaabababaaab ⇒ aaaaabaaba
13. aaaaabababaababaaa ⇒ aaaaabaaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] aba, [3/3] baa, [3/4] bab, [3/5] abb, [3/6] bba
Length 4:[4/0] aaaa, [4/1] aaab, [4/2] aaba, [4/3] abaa, [4/4] abab, [4/5] baba, [4/6] baaa
Length 5:[5/0] aaaaa, [5/1] aabab, [5/2] ababa, [5/3] abaaa, [5/4] babaa, [5/5] aaaba, [5/6] abaab
Length 6:[6/0] aaaaab, [6/1] aababa, [6/2] ababaa, [6/3] abaaab, [6/4] aaabaa, [6/5] babaaa, [6/6] abaaba
Length 7:[7/0] aaaaaba, [7/1] aababaa, [7/2] ababaaa, [7/3] aaabaab, [7/4] abaabab, [7/5] baababa, [7/6] babaaab

Considering [length 5 / frequency 1] aabab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aababaaab=aa⟩.