Morphocompletion for #4106 ⟨a, b | aabaabbba=ba⟩

Solved by morph:5/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#	Rule
1.	aabaabbba ⇒ ba
2.	aabaabbbba ⇒ bba
3.	aabaabbbbba ⇒ bbba
4.	aabaabbbbbba ⇒ bbbba
5.	aabaabbbbbbba ⇒ bbbbba
6.	aabaabbbbbbbba ⇒ bbbbbba
7.	aabaabbbbbbbbba ⇒ bbbbbbba
8.	aabaabbbbbbbbbba ⇒ bbbbbbbba
9.	aabaabbbbbbbbbbba ⇒ bbbbbbbbba
10.	aabaabbbbbbbbbbbba ⇒ bbbbbbbbbba
11.	aabaabbbbbbbbbbbbba ⇒ bbbbbbbbbbba
12.	aabaabbbbbbbbbbbbbba ⇒ bbbbbbbbbbbba
13.	aabaabbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbba
14.	aabaabbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbba
15.	aabaabbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbba
16.	aabaabbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbba
17.	aabaabbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbba
18.	aabaabbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbba
19.	aabaabbbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbba
20.	aabaabbbbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbbba
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] bb, [2/1] ba, [2/2] aa, [2/3] ab
Length 3:	[3/0] bbb, [3/1] aab, [3/2] bba, [3/3] abb, [3/4] aba, [3/5] baa
Length 4:	[4/0] bbbb, [4/1] bbba, [4/2] aaba, [4/3] abbb, [4/4] aabb, [4/5] baab, [4/6] abaa
Length 5:	[5/0] bbbbb, [5/1] aabaa, [5/2] bbbba, [5/3] aabbb, [5/4] baabb, [5/5] abaab, [5/6] abbbb
Length 6:	[6/0] bbbbbb, [6/1] aabaab, [6/2] bbbbba, [6/3] baabbb, [6/4] abaabb, [6/5] aabbbb, [6/6] abbbbb
Length 7:	[7/0] bbbbbbb, [7/1] aabaabb, [7/2] bbbbbba, [7/3] abaabbb, [7/4] baabbbb, [7/5] aabbbbb, [7/6] abbbbbb

Considering [length 5 / frequency 2] bbbba=c.

Reduction order:
- Left-to-right recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1
Auxiliary generators:
1. bbbba=c

Rewriting system is complete. See ⟨a, b | aabaabbba=ba⟩.