| Back: | ⟨a, b | aabaabbba=ab⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabaabbba ⇒ ab |
| 2. | abbaabbba ⇒ aabaabbbb |
| 3. | ababaabbba ⇒ abb |
| 4. | abbbaabbba ⇒ ababaabbbb |
| 5. | abbabaabbba ⇒ abbb |
| 6. | abbbbaabbba ⇒ abbabaabbbb |
| 7. | abbbabaabbba ⇒ abbbb |
| 8. | abbbbbaabbba ⇒ abbbabaabbbb |
| 9. | abbbbabaabbba ⇒ abbbbb |
| 10. | abbbbbbaabbba ⇒ abbbbabaabbbb |
| 11. | aabaababaabbbb ⇒ ababbba |
| 12. | abbbbbabaabbba ⇒ abbbbbb |
| 13. | ababaababaabbbb ⇒ abbabbba |
| 14. | abbbbbbabaabbba ⇒ abbbbbbb |
| 15. | abbabaababaabbbb ⇒ abbbabbba |
| 16. | abbbbbbbabaabbba ⇒ abbbbbbbb |
| 17. | abbbabaababaabbbb ⇒ abbbbabbba |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] bbb, [3/1] abb, [3/2] bba, [3/3] aab, [3/4] aba, [3/5] baa, [3/6] bab |
| Length 4: | [4/0] abbb, [4/1] bbba, [4/2] bbbb, [4/3] baab, [4/4] aabb, [4/5] abaa, [4/6] baba |
| Length 5: | [5/0] abbba, [5/1] abbbb, [5/2] baabb, [5/3] aabbb, [5/4] abaab, [5/5] babaa, [5/6] bbbbb |
| Length 6: | [6/0] aabbba, [6/1] baabbb, [6/2] babaab, [6/3] abaabb, [6/4] abbbbb, [6/5] bbabaa, [6/6] ababaa |
| Length 7: | [7/0] baabbba, [7/1] abaabbb, [7/2] babaabb, [7/3] bbabaab, [7/4] baabbbb, [7/5] ababaab, [7/6] bbbabaa |
Considering [length 4 / frequency 0] abbb=c.
Rewriting system is complete. See ⟨a, b | aabaabbba=ab⟩.