Morphocompletion for #4098 ⟨a, b | aabaabbaa=ba⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	aabaabbaa ⇒ ba
2.	aabaabbba ⇒ babaabbaa
3.	aabaabbaba ⇒ bba
4.	aabaabbbba ⇒ babaabbaba
5.	aabaabbabba ⇒ bbba
6.	aabaabbbbba ⇒ babaabbabba
7.	aabaabbabbba ⇒ bbbba
8.	aabaabbbbbba ⇒ babaabbabbba
9.	aabaabbabbbba ⇒ bbbbba
10.	aabaabbbbbbba ⇒ babaabbabbbba
11.	aabaabbabbbbba ⇒ bbbbbba
12.	aabaabbbbbbbba ⇒ babaabbabbbbba
13.	aabaabbabbbbbba ⇒ bbbbbbba
14.	aabaabbbbbbbbba ⇒ babaabbabbbbbba
15.	aabaabbabbbbbbba ⇒ bbbbbbbba
16.	aabaabbbbbbbbbba ⇒ babaabbabbbbbbba
17.	aabaabbabbbbbbbba ⇒ bbbbbbbbba
18.	aabaabbabbbbbbbbba ⇒ bbbbbbbbbba
19.	aabaabbabbbbbbbbbba ⇒ bbbbbbbbbbba
20.	aabaabbabbbbbbbbbbba ⇒ bbbbbbbbbbbba
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] bb, [2/1] ba, [2/2] aa, [2/3] ab
Length 3:	[3/0] bbb, [3/1] aab, [3/2] bba, [3/3] abb, [3/4] aba, [3/5] baa, [3/6] bab
Length 4:	[4/0] bbbb, [4/1] aaba, [4/2] bbba, [4/3] aabb, [4/4] baab, [4/5] abaa, [4/6] abbb
Length 5:	[5/0] bbbbb, [5/1] aabaa, [5/2] bbbba, [5/3] baabb, [5/4] abaab, [5/5] abbbb, [5/6] aabba
Length 6:	[6/0] aabaab, [6/1] bbbbbb, [6/2] bbbbba, [6/3] abaabb, [6/4] abbbbb, [6/5] baabba, [6/6] aabbab
Length 7:	[7/0] aabaabb, [7/1] bbbbbbb, [7/2] bbbbbba, [7/3] abaabba, [7/4] abbbbbb, [7/5] baabbab, [7/6] aabbabb

Considering [length 7 / frequency 0] aabaabb=c.

Reduction order:
- Left-to-right recursive path with deg(a) = 0; deg(c) = deg(b) = 1, c < b
Auxiliary generators:
1. aabaabb=c

Rewriting system is complete. See ⟨a, b | aabaabbaa=ba⟩.