Morphocompletion for #4098 ⟨a, b | aabaabbaa=ba⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aabaabbaa ⇒ ba
2. aabaabbba ⇒ babaabbaa
3. aabaabbaba ⇒ bba
4. aabaabbbba ⇒ babaabbaba
5. aabaabbabba ⇒ bbba
6. aabaabbbbba ⇒ babaabbabba
7. aabaabbabbba ⇒ bbbba
8. aabaabbbbbba ⇒ babaabbabbba
9. aabaabbabbbba ⇒ bbbbba
10. aabaabbbbbbba ⇒ babaabbabbbba
11. aabaabbabbbbba ⇒ bbbbbba
12. aabaabbbbbbbba ⇒ babaabbabbbbba
13. aabaabbabbbbbba ⇒ bbbbbbba
14. aabaabbbbbbbbba ⇒ babaabbabbbbbba
15. aabaabbabbbbbbba ⇒ bbbbbbbba
16. aabaabbbbbbbbbba ⇒ babaabbabbbbbbba
17. aabaabbabbbbbbbba ⇒ bbbbbbbbba
18. aabaabbabbbbbbbbba ⇒ bbbbbbbbbba
19. aabaabbabbbbbbbbbba ⇒ bbbbbbbbbbba
20. aabaabbabbbbbbbbbbba ⇒ bbbbbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb111lf:111,rf:95,rp:11
[2/1]ba70lf:51,ls:19,rf:43,rp:9,rs:19,re:1,lsrp:8,lsrs:18
[2/2]aa62lf:41,lp:20,ls:1,rf:9,rs:1,lprs:1
[2/3]ab51lf:51,rf:23
[3/0]bbb81lf:81,rf:70,rp:10,a:1
[3/1]aab60lf:40,lp:20,rf:8
[3/2]bba48lf:30,ls:18,rf:25,rp:1,rs:17,re:1,lsrs:16
[3/3]abb30lf:30,rf:14
[3/4]aba22lf:21,ls:1,rf:9,rs:1
[3/5]baa22lf:21,ls:1,rf:9,rs:1
[3/6]bab11lf:11,rf:15,rp:8,a:1
[4/0]bbbb64lf:64,rf:55,rp:9,a:3
[4/1]aaba40lf:20,lp:20
[4/2]bbba34lf:17,ls:17,rf:15,rp:1,rs:15,re:1,lsrs:14,a:1
[4/3]aabb20lf:20,rf:8
[4/4]baab20lf:20,rf:8
[4/5]abaa20lf:20,rf:8
[4/6]abbb17lf:17,rf:5,a:1
[5/0]bbbbb49lf:49,rf:42,rp:8,a:6
[5/1]aabaa40lf:20,lp:20
[5/2]bbbba30lf:15,ls:15,rf:13,rp:1,rs:13,re:1,lsrs:12,a:3
[5/3]baabb20lf:20,rf:8
[5/4]abaab20lf:20,rf:8
[5/5]abbbb15lf:15,rf:4,a:3
[5/6]aabba12lf:12,rf:8
[6/0]aabaab40lf:20,lp:20
[6/1]bbbbbb36lf:36,rf:31,rp:7,a:8
[6/2]bbbbba26lf:13,ls:13,rf:11,rp:1,rs:11,re:1,lsrs:10,a:6
[6/3]abaabb20lf:20,rf:8
[6/4]abbbbb13lf:13,rf:3,a:6
[6/5]baabba12lf:12,rf:8
[6/6]aabbab11lf:11,rf:7,a:2
[7/0]aabaabb40lf:20,lp:20
[7/1]bbbbbbb25lf:25,rf:22,rp:6,a:10
[7/2]bbbbbba22lf:11,ls:11,rf:9,rp:1,rs:9,re:1,lsrs:8,a:8
[7/3]abaabba12lf:12,rf:8
[7/4]abbbbbb11lf:11,rf:2,a:9
[7/5]baabbab11lf:11,rf:7,a:2
[7/6]aabbabb10lf:10,rf:6,a:4

Considering [length 7 / frequency 0] aabaabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabaabbaa=ba⟩.