Morphocompletion for #4097 ⟨a, b | aabaabbaa=ab⟩

Back:⟨a, b | aabaabbaa=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaabbaa ⇒ ab
2. abbaabbaa ⇒ aabaabbab
3. ababaabbaa ⇒ abb
4. aabaaabaabbab ⇒ abbbaa
5. abbbaabbaa ⇒ ababaabbab
6. abbabaabbaa ⇒ abbb
7. abbbaaaabbaa ⇒ aabaaabaabbb
8. ababaaabaabbab ⇒ abbbbaa
9. abbbbaabbaa ⇒ abbabaabbab
10. abbbabaabbaa ⇒ abbbb
11. abbabaaabaabbab ⇒ abbbbbaa
12. abbbbabaabbaa ⇒ abbbbb
13. abbbbbabaabbaa ⇒ abbbbbb
14. abbbbbbabaabbaa ⇒ abbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb
Length 3:[3/0] baa, [3/1] abb, [3/2] bba, [3/3] aab, [3/4] aba, [3/5] bbb, [3/6] bab
Length 4:[4/0] bbaa, [4/1] abba, [4/2] abbb, [4/3] aabb, [4/4] baab, [4/5] abaa, [4/6] bbab
Length 5:[5/0] abbaa, [5/1] aabba, [5/2] baabb, [5/3] abbab, [5/4] abaab, [5/5] abbbb, [5/6] babaa
Length 6:[6/0] aabbaa, [6/1] baabba, [6/2] abaabb, [6/3] bbabaa, [6/4] babaab, [6/5] aabbab, [6/6] aabaab
Length 7:[7/0] baabbaa, [7/1] abaabba, [7/2] baabbab, [7/3] babaabb, [7/4] bbabaab, [7/5] aabaabb, [7/6] bbbabaa

Considering [length 4 / frequency 0] bbaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabaabbaa=ab⟩.