Morphocompletion for #4082 ⟨a, b | aabaaabba=ba⟩

Back:⟨a, b | aabaaabba=ba⟩

Solved by morph:4/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aabaaabba ⇒ ba
2. aabaaabbba ⇒ bba
3. aabaaabbbba ⇒ bbba
4. aabaaabbbbba ⇒ bbbba
5. aabaaabbbbbba ⇒ bbbbba
6. aabaaabbbbbbba ⇒ bbbbbba
7. aabaaabbbbbbbba ⇒ bbbbbbba
8. aabaaabbbbbbbbba ⇒ bbbbbbbba
9. aabaaabbbbbbbbbba ⇒ bbbbbbbbba
10. aabaaabbbbbbbbbbba ⇒ bbbbbbbbbba
11. aabaaabbbbbbbbbbbba ⇒ bbbbbbbbbbba
12. aabaaabbbbbbbbbbbbba ⇒ bbbbbbbbbbbba
13. aabaaabbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbba
14. aabaaabbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbba
15. aabaaabbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbba
16. aabaaabbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbba
17. aabaaabbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbba
18. aabaaabbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbba
19. aabaaabbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbba
20. aabaaabbbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb210lf:210,rf:190,rp:19
[2/1]aa80lf:60,lp:20
[2/2]ba60lf:40,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20
[2/3]ab40lf:40
[3/0]bbb190lf:190,rf:171,rp:18,a:1
[3/1]aab60lf:40,lp:20
[3/2]bba40lf:20,ls:20,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19
[3/3]abb20lf:20
[3/4]aba20lf:20
[3/5]baa20lf:20
[3/6]aaa20lf:20
[4/0]bbbb171lf:171,rf:153,rp:17,a:2
[4/1]aaba40lf:20,lp:20
[4/2]bbba38lf:19,ls:19,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18,a:1
[4/3]aabb20lf:20
[4/4]aaab20lf:20
[4/5]abaa20lf:20
[4/6]baaa20lf:20
[5/0]bbbbb153lf:153,rf:136,rp:16,a:3
[5/1]aabaa40lf:20,lp:20
[5/2]bbbba36lf:18,ls:18,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17,a:2
[5/3]aaabb20lf:20
[5/4]baaab20lf:20
[5/5]abaaa20lf:20
[5/6]aabbb19lf:19,a:1
[6/0]bbbbbb136lf:136,rf:120,rp:15,a:4
[6/1]aabaaa40lf:20,lp:20
[6/2]bbbbba34lf:17,ls:17,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:3
[6/3]baaabb20lf:20
[6/4]abaaab20lf:20
[6/5]aaabbb19lf:19,a:1
[6/6]aabbbb18lf:18,a:2
[7/0]bbbbbbb120lf:120,rf:105,rp:14,a:5
[7/1]aabaaab40lf:20,lp:20
[7/2]bbbbbba32lf:16,ls:16,rf:15,rp:1,rs:15,re:1,lsrp:1,lsrs:15,a:4
[7/3]abaaabb20lf:20
[7/4]baaabbb19lf:19,a:1
[7/5]aaabbbb18lf:18,a:2
[7/6]aabbbbb17lf:17,a:3

Considering [length 4 / frequency 2] bbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabaaabba=ba⟩.