Morphocompletion for #4081 ⟨a, b | aabaaabba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaaabba ⇒ ab
2. abbaaabba ⇒ aabaaabbb
3. ababaaabba ⇒ abb
4. aabaaaabaaabbb ⇒ abaabba
5. abbbaaabba ⇒ ababaaabbb
6. abbabaaabba ⇒ abbb
7. ababaaaabaaabbb ⇒ abbaabba
8. abbbbaaabba ⇒ abbabaaabbb
9. abbbabaaabba ⇒ abbbb
10. abbabaaaabaaabbb ⇒ abbbaabba
11. abbbbbaaabba ⇒ abbbabaaabbb
12. abbbbabaaabba ⇒ abbbbb
13. abbbbbabaaabba ⇒ abbbbbb
14. abbbbbbabaaabba ⇒ abbbbbbb
15. abbbbbbbabaaabba ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab55lf:42,lp:13,rf:25,rp:14,rs:1,re:1,lprp:12
[2/1]bb53lf:50,ls:3,rf:45,rs:11
[2/2]ba51lf:39,ls:12,rf:13,rs:3
[2/3]aa43lf:41,lp:2,rf:12,rp:1
[3/0]abb37lf:26,lp:11,rf:18,rp:11,rs:1,re:1,lprp:9
[3/1]bba35lf:23,ls:12,rf:7,rs:3
[3/2]bbb27lf:24,ls:3,rf:27,rs:10,a:2
[3/3]aab22lf:20,lp:2,rf:8,rp:1
[3/4]aaa21lf:21,rf:4
[3/5]baa18lf:18,rf:7
[3/6]aba18lf:16,lp:2,rf:6,rp:2
[4/0]abba30lf:15,lp:3,ls:12,rf:5,rp:2,rs:3,lsrp:1,lprs:1
[4/1]abbb22lf:11,lp:8,ls:3,rf:12,rp:8,rs:5,re:1,lprp:6,lsrp:1,lprs:3,a:2
[4/2]baaa18lf:18,rf:4
[4/3]aaab18lf:18,rf:4
[4/4]aabb15lf:15,rf:7
[4/5]abaa14lf:14,rf:5,rp:1
[4/6]bbbb13lf:13,rf:15,rs:5,a:3
[5/0]aabba24lf:12,ls:12,rf:3,rs:3
[5/1]baaab15lf:15,rf:4
[5/2]aaabb15lf:15,rf:4
[5/3]abaaa14lf:14,rf:4
[5/4]abbbb12lf:6,lp:6,rf:5,rp:5,rs:1,re:1,lprp:4,a:3
[5/5]babaa9lf:9,rf:3,a:1
[5/6]bbbbb7lf:7,rf:10,rs:4,a:6
[6/0]aaabba24lf:12,ls:12
[6/1]baaabb15lf:15,rf:4
[6/2]abaaab11lf:11,rf:4
[6/3]babaaa9lf:9,rf:3,a:1
[6/4]abbbbb8lf:4,lp:4,rf:4,rp:4,rs:1,re:1,lprp:3,a:6
[6/5]bbabaa7lf:7,rf:2,a:2
[6/6]aabaaa7lf:5,lp:2,rf:1,rp:1
[7/0]baaabba24lf:12,ls:12
[7/1]abaaabb11lf:11,rf:4
[7/2]bbabaaa7lf:7,rf:2,a:2
[7/3]babaaab7lf:7,rf:3,a:1
[7/4]baaabbb6lf:3,ls:3,rf:4,rs:4,a:4
[7/5]bbbabaa5lf:5,rf:1,a:3
[7/6]aabaaab5lf:4,lp:1,rf:1,rp:1

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabaaabba=ab⟩.