Morphocompletion for #4063 ⟨a, b | aabaaaaab=ba⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aabaaaaab ⇒ ba
2. aabaaaba ⇒ baaaaaab
3. baaaaaabaaaab ⇒ aababa
4. aabaaaaaaababa ⇒ baaaaaaabaaaab
5. baaaaaabaaba ⇒ aababaaaaaab
6. baaaaaababaaaaab ⇒ aabaaabba
7. aabaaaaaaabaaabba ⇒ baaaaaaababaaaaab
8. baaaaaabaaaaaababa ⇒ aababaaaaaaabaaaab
9. baaaaaababaaaba ⇒ aabaaabbaaaaaab
10. aababaaaaaaabaaaabaaaab ⇒ baaaaaaaabaaabba
11. baaaaaaabaaaababaaaaab ⇒ aabaaaaaaababba
12. aabaaaaaaabaaaaaaababba ⇒ baaaaaaaabaaaababaaaaab
13. baaaaaabaaaaaabaaabba ⇒ aababaaaaaaababaaaaab
14. baaaaaababaaaaaaababa ⇒ aabaaabbaaaaaaabaaaab
15. aababaaaaaaabaaaabaaba ⇒ baaaaaaaabaaabbaaaaaab
16. baaaaaaabaaaababaaaba ⇒ aabaaaaaaababbaaaaaab
17. baaaaaaababaaaaababaaaaab ⇒ aabaaaaaaabaaabbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa169lf:162,lp:7,rf:140,rp:10
[2/1]ba82lf:61,lp:10,ls:11,rf:44,rp:7,rs:6,re:1,lsrp:5,lprs:4
[2/2]ab63lf:57,ls:6,rf:48,rs:11
[2/3]bb3lf:3,rf:9,a:3
[3/0]aaa118lf:118,rf:101
[3/1]aab57lf:44,lp:7,ls:6,rf:39,rp:10,rs:11,lsrp:4,lprs:5
[3/2]aba56lf:48,ls:8,rf:29,rs:1
[3/3]baa47lf:37,lp:10,rf:29,rp:6
[3/4]bab13lf:13,rf:9,a:2
[3/5]bba6lf:3,ls:3,rf:8,rs:4,a:3
[3/6]abb3lf:3,rf:8,a:3
[4/0]aaaa83lf:83,rf:72
[4/1]aaba48lf:36,lp:7,ls:5,rf:22,rp:10,lsrp:3
[4/2]baaa45lf:35,lp:10,rf:29,rp:6
[4/3]aaab41lf:35,ls:6,rf:29,rs:11
[4/4]abaa27lf:27,rf:19
[4/5]baba15lf:12,ls:3,rf:7,rs:1,a:2
[4/6]abab13lf:13,rf:9,a:2
[5/0]aaaaa53lf:53,rf:49
[5/1]baaaa40lf:30,lp:10,rf:23,rp:6
[5/2]aaaab36lf:30,ls:6,rf:23,rs:11
[5/3]aaaba30lf:27,ls:3,rf:12,a:1
[5/4]abaaa25lf:25,rf:19
[5/5]aabaa23lf:18,lp:5,rf:13,rp:6
[5/6]ababa15lf:12,ls:3,rf:7,rs:1,a:2
[6/0]baaaaa34lf:24,lp:10,rf:19,rp:6
[6/1]aaaaaa29lf:29,rf:30,a:1
[6/2]aaaaab28lf:24,ls:4,rf:19,rs:8
[6/3]aaaaba24lf:24,rf:12,a:2
[6/4]aabaaa21lf:16,lp:5,rf:13,rp:6
[6/5]abaaaa20lf:20,rf:13
[6/6]aababa17lf:12,lp:2,ls:3,rf:7,rp:4,rs:1,re:1,lsrp:1,a:2
[7/0]baaaaaa29lf:19,lp:10,rf:16,rp:6,a:1
[7/1]aaaaaba20lf:20,rf:11,a:2
[7/2]aaaaaab19lf:19,rf:16,rs:5,a:1
[7/3]aabaaaa17lf:13,lp:4,rf:7,rp:3
[7/4]abaaaaa14lf:14,rf:9
[7/5]aaababa13lf:10,ls:3,rf:3,a:3
[7/6]aaaabaa13lf:13,rf:7,a:2

Considering [length 6 / frequency 0] baaaaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabaaaaab=ba⟩.