Morphocompletion for #4058 ⟨a, b | aaabbbbba=ab⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbbba ⇒ ab
2. ababbbbba ⇒ aaabbbbbb
3. abaabbbbba ⇒ abb
4. abbabbbbba ⇒ abaabbbbbb
5. abbaabbbbba ⇒ abbb
6. abbbabbbbba ⇒ abbaabbbbbb
7. abbbaabbbbba ⇒ abbbb
8. abbbbabbbbba ⇒ abbbaabbbbbb
9. abbbbaabbbbba ⇒ abbbbb
10. aaabbbbaabbbbbb ⇒ abbbbbba
11. abbbbbabbbbba ⇒ abbbbaabbbbbb
12. abbbbbaabbbbba ⇒ abbbbbb
13. abaabbbbaabbbbbb ⇒ abbbbbbba
14. abbbbbbabbbbba ⇒ abbbbbaabbbbbb
15. abbbbbbaabbbbba ⇒ abbbbbbb
16. abbaabbbbaabbbbbb ⇒ abbbbbbbba
17. abbbbbbbaabbbbba ⇒ abbbbbbbb
18. abbbbbbbbaabbbbba ⇒ abbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb131lf:128,ls:3,rf:94,rs:14
[2/1]ab53lf:37,lp:16,rf:23,rp:17,rs:1,re:1,lprp:15
[2/2]ba49lf:34,ls:15,rf:8,rs:3
[2/3]aa19lf:17,lp:2,rf:7,rp:1
[3/0]bbb97lf:94,ls:3,rf:73,rs:13
[3/1]abb47lf:34,lp:13,rf:21,rp:15,rs:1,re:1,lprp:12
[3/2]bba46lf:31,ls:15,rf:7,rs:3
[3/3]aab15lf:15,rf:6
[3/4]baa13lf:13,rf:5,a:1
[3/5]bab6lf:6,a:10
[3/6]aba6lf:3,lp:3,rf:1,rp:1,a:1
[4/0]bbbb66lf:63,ls:3,rf:54,rs:12
[4/1]bbba43lf:28,ls:15,rf:6,rs:3
[4/2]abbb41lf:31,lp:10,rf:19,rp:13,rs:1,re:1,lprp:9
[4/3]aabb15lf:15,rf:6
[4/4]baab13lf:13,rf:5,a:1
[4/5]bbaa11lf:11,rf:4,a:2
[4/6]babb6lf:6,a:10
[5/0]bbbba41lf:26,ls:15,rf:5,rs:3
[5/1]bbbbb37lf:34,ls:3,rf:37,rs:11
[5/2]abbbb37lf:29,lp:8,rf:17,rp:11,rs:1,re:1,lprp:7
[5/3]aabbb15lf:15,rf:6
[5/4]baabb13lf:13,rf:5,a:1
[5/5]bbaab11lf:11,rf:4,a:2
[5/6]bbbaa9lf:9,rf:3,a:3
[6/0]bbbbba36lf:21,ls:15,rf:4,rs:3
[6/1]abbbbb30lf:24,lp:6,rf:15,rp:9,rs:1,re:1,lprp:5
[6/2]aabbbb15lf:15,rf:6
[6/3]bbbbbb13lf:10,ls:3,rf:22,rs:10,a:5
[6/4]baabbb13lf:13,rf:5,a:1
[6/5]bbaabb11lf:11,rf:4,a:2
[6/6]bbbaab9lf:9,rf:3,a:3
[7/0]abbbbba34lf:17,lp:2,ls:15,rf:1,rp:1,lsrp:1
[7/1]abbbbbb14lf:7,lp:4,ls:3,rf:13,rp:7,rs:7,re:1,lprp:3,lsrp:3,lprs:1,a:5
[7/2]baabbbb13lf:13,rf:5,a:1
[7/3]aabbbbb12lf:12,rf:6
[7/4]bbaabbb11lf:11,rf:4,a:2
[7/5]bbbaabb9lf:9,rf:3,a:3
[7/6]bbbbaab8lf:8,rf:2,a:4

Considering [length 6 / frequency 0] bbbbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbbbba=ab⟩.