Morphocompletion for #4051 ⟨a, b | aaabbbbaa=ba

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbbaa ⇒ ba
2. aaabbbbaba ⇒ bba
3. baabbbbaa ⇒ aaabbbbba
4. aaabbbbabba ⇒ bbba
5. baabbbbaba ⇒ aaabbbbbba
6. aaabbbbabbba ⇒ bbbba
7. baabbbbabba ⇒ aaabbbbbbba
8. aaabbbaaabbbbba ⇒ babbbbaa
9. aaabbbbabbbba ⇒ bbbbba
10. baabbbbabbba ⇒ aaabbbbbbbba
11. aaabbbaaabbbbbba ⇒ babbbbaba
12. aaabbbbabbbbba ⇒ bbbbbba
13. baabbbbabbbba ⇒ aaabbbbbbbbba
14. aaabbbaaabbbbbbba ⇒ babbbbabba
15. aaabbbbabbbbbba ⇒ bbbbbbba
16. aaabbbbabbbbbbba ⇒ bbbbbbbba
17. aaabbbbabbbbbbbba ⇒ bbbbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] aa, [2/3] ab
Length 3:[3/0] bbb, [3/1] bba, [3/2] abb, [3/3] aaa, [3/4] aab, [3/5] baa, [3/6] bab
Length 4:[4/0] bbbb, [4/1] bbba, [4/2] abbb, [4/3] aaab, [4/4] aabb, [4/5] bbab, [4/6] babb
Length 5:[5/0] bbbba, [5/1] aaabb, [5/2] abbbb, [5/3] aabbb, [5/4] bbbbb, [5/5] bbbab, [5/6] bbabb
Length 6:[6/0] aaabbb, [6/1] abbbba, [6/2] aabbbb, [6/3] bbbbba, [6/4] bbbbab, [6/5] bbbabb, [6/6] baabbb
Length 7:[7/0] aaabbbb, [7/1] aabbbba, [7/2] abbbbab, [7/3] bbbbbba, [7/4] bbbbabb, [7/5] baabbbb, [7/6] bbbabbb

Considering [length 5 / frequency 0] bbbba=c.

Step 2

Rewriting system is complete. See a, b | aaabbbbaa=ba.