Morphocompletion for #4051 ⟨a, b | aaabbbbaa=ba⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbbaa ⇒ ba
2. aaabbbbaba ⇒ bba
3. baabbbbaa ⇒ aaabbbbba
4. aaabbbbabba ⇒ bbba
5. baabbbbaba ⇒ aaabbbbbba
6. aaabbbbabbba ⇒ bbbba
7. baabbbbabba ⇒ aaabbbbbbba
8. aaabbbaaabbbbba ⇒ babbbbaa
9. aaabbbbabbbba ⇒ bbbbba
10. baabbbbabbba ⇒ aaabbbbbbbba
11. aaabbbaaabbbbbba ⇒ babbbbaba
12. aaabbbbabbbbba ⇒ bbbbbba
13. baabbbbabbbba ⇒ aaabbbbbbbbba
14. aaabbbaaabbbbbbba ⇒ babbbbabba
15. aaabbbbabbbbbba ⇒ bbbbbbba
16. aaabbbbabbbbbbba ⇒ bbbbbbbba
17. aaabbbbabbbbbbbba ⇒ bbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb97lf:97,rf:76,rp:8
[2/1]ba57lf:37,lp:5,ls:15,rf:22,rp:4,rs:16,re:1,lsrp:3,lprs:5,lsrs:14
[2/2]aa51lf:37,lp:12,ls:2,rf:11,rp:5,rs:1,lsrp:1,lprs:1
[2/3]ab32lf:32,rf:10
[3/0]bbb67lf:67,rf:59,rp:7
[3/1]bba43lf:30,ls:13,rf:17,rp:1,rs:14,re:1,lsrs:11
[3/2]abb30lf:30,rf:9
[3/3]aaa27lf:15,lp:12,rf:5,rp:5
[3/4]aab20lf:20,rf:5
[3/5]baa17lf:10,lp:5,ls:2,rf:1,rs:1
[3/6]bab12lf:12,rf:5,rp:3,a:2
[4/0]bbbb39lf:39,rf:44,rp:6
[4/1]bbba39lf:28,ls:11,rf:15,rp:1,rs:12,re:1,lsrs:8
[4/2]abbb28lf:28,rf:8
[4/3]aaab27lf:15,lp:12,rf:5,rp:5
[4/4]aabb20lf:20,rf:5
[4/5]bbab12lf:12,rf:2,a:2
[4/6]babb10lf:10,rf:4,rp:3,a:4
[5/0]bbbba32lf:23,ls:9,rf:14,rp:1,rs:11,re:1,lsrs:6
[5/1]aaabb27lf:15,lp:12,rf:5,rp:5
[5/2]abbbb23lf:23,rf:8
[5/3]aabbb20lf:20,rf:5
[5/4]bbbbb16lf:16,rf:30,rp:5,a:1
[5/5]bbbab12lf:12,rf:2,a:2
[5/6]bbabb10lf:10,rf:1,a:4
[6/0]aaabbb27lf:15,lp:12,rf:5,rp:5
[6/1]abbbba18lf:16,ls:2,rf:3
[6/2]aabbbb17lf:17,rf:5
[6/3]bbbbba14lf:7,ls:7,rf:10,rp:1,rs:10,re:1,lsrs:4,a:1
[6/4]bbbbab12lf:12,rf:2,a:2
[6/5]bbbabb10lf:10,rf:1,a:4
[6/6]baabbb10lf:5,lp:5,a:1
[7/0]aaabbbb21lf:12,lp:9,rf:5,rp:5
[7/1]aabbbba14lf:14
[7/2]abbbbab12lf:12,rf:2,a:2
[7/3]bbbbbba10lf:5,ls:5,rf:8,rp:1,rs:8,re:1,lsrs:3,a:3
[7/4]bbbbabb10lf:10,rf:1,a:4
[7/5]baabbbb10lf:5,lp:5,a:1
[7/6]bbbabbb8lf:8,a:5

Considering [length 5 / frequency 0] bbbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbbbaa=ba⟩.