Morphocompletion for #4050 ⟨a, b | aaabbbbaa=ab⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaabbbbaa ⇒ ab
2. abaabbbbaa ⇒ abb
3. aaabbbbb ⇒ abbbbbaa
4. aaabbbbab ⇒ ababbbbaa
5. abbaabbbbaa ⇒ abbb
6. abaabbbbb ⇒ abbbbbbaa
7. abaabbbbab ⇒ abbabbbbaa
8. abbbaabbbbaa ⇒ abbbb
9. abbaabbbbb ⇒ abbbbbbbaa
10. abbaabbbbab ⇒ abbbabbbbaa
11. abbbbaabbbbaa ⇒ abbbbb
12. abbbaabbbbb ⇒ abbbbbbbbaa
13. abbbaabbbbab ⇒ abbbbabbbbaa
14. abbbbbaabbbbaa ⇒ abbbbbb
15. abbbbaabbbbb ⇒ abbbbbbbbbaa
16. abbbbaabbbbab ⇒ abbbbbabbbbaa
17. abbbbbbaabbbbaa ⇒ abbbbbbb
18. abbbbbaabbbbb ⇒ abbbbbbbbbbaa
19. abbbbbbbaabbbbaa ⇒ abbbbbbbb
20. abbbbbbbbaabbbbaa ⇒ abbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb116lf:110,ls:6,rf:100,rs:8
[2/1]ab64lf:42,lp:17,ls:5,rf:25,rp:20,rs:1,re:1,lprp:17,lsrp:5
[2/2]aa44lf:32,lp:3,ls:9,rf:11,rs:11,lprs:2
[2/3]ba31lf:31,rf:16
[3/0]bbb82lf:76,ls:6,rf:77,rs:7
[3/1]abb48lf:34,lp:14,rf:23,rp:18,rs:1,re:1,lprp:14
[3/2]baa35lf:26,ls:9,rf:11,rs:11
[3/3]bba28lf:28,rf:15
[3/4]aab20lf:20
[3/5]bab10lf:5,ls:5,rf:5,a:1
[3/6]aba6lf:3,lp:3,rf:1,rp:1,a:1
[4/0]bbbb51lf:45,ls:6,rf:56,rs:6
[4/1]abbb42lf:31,lp:11,rf:21,rp:16,rs:1,re:1,lprp:11
[4/2]bbaa32lf:23,ls:9,rf:11,rs:11
[4/3]bbba25lf:25,rf:14
[4/4]aabb20lf:20
[4/5]baab17lf:17,a:2
[4/6]bbab10lf:5,ls:5,rf:4,a:1
[5/0]abbbb36lf:28,lp:8,rf:19,rp:14,rs:1,re:1,lprp:8
[5/1]bbbaa29lf:20,ls:9,rf:11,rs:11
[5/2]bbbbb23lf:17,ls:6,rf:37,rs:5,a:6
[5/3]bbbba22lf:22,rf:13
[5/4]aabbb20lf:20
[5/5]baabb17lf:17,a:2
[5/6]bbaab14lf:14,a:3
[6/0]bbbbaa26lf:17,ls:9,rf:11,rs:11
[6/1]abbbbb22lf:11,lp:5,ls:6,rf:12,rp:12,rs:1,re:1,lprp:5,lsrp:6,a:6
[6/2]aabbbb20lf:20
[6/3]abbbba20lf:17,lp:3,rf:6,rp:1
[6/4]baabbb17lf:17,a:2
[6/5]bbaabb14lf:14,a:3
[6/6]bbbaab11lf:11,a:5
[7/0]abbbbaa24lf:12,lp:3,ls:9,rf:5,rs:5,lprs:1
[7/1]baabbbb17lf:17,a:2
[7/2]bbaabbb14lf:14,a:3
[7/3]aabbbba14lf:14
[7/4]aabbbbb12lf:6,ls:6,a:13
[7/5]bbbaabb11lf:11,a:5
[7/6]abbbbab10lf:5,ls:5,rf:1,rp:1,lsrp:1,a:1

Considering [length 5 / frequency 0] abbbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbbbaa=ab⟩.