Morphocompletion for #4050 ⟨a, b | aaabbbbaa=ab⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	aaabbbbaa ⇒ ab
2.	abaabbbbaa ⇒ abb
3.	aaabbbbb ⇒ abbbbbaa
4.	aaabbbbab ⇒ ababbbbaa
5.	abbaabbbbaa ⇒ abbb
6.	abaabbbbb ⇒ abbbbbbaa
7.	abaabbbbab ⇒ abbabbbbaa
8.	abbbaabbbbaa ⇒ abbbb
9.	abbaabbbbb ⇒ abbbbbbbaa
10.	abbaabbbbab ⇒ abbbabbbbaa
11.	abbbbaabbbbaa ⇒ abbbbb
12.	abbbaabbbbb ⇒ abbbbbbbbaa
13.	abbbaabbbbab ⇒ abbbbabbbbaa
14.	abbbbbaabbbbaa ⇒ abbbbbb
15.	abbbbaabbbbb ⇒ abbbbbbbbbaa
16.	abbbbaabbbbab ⇒ abbbbbabbbbaa
17.	abbbbbbaabbbbaa ⇒ abbbbbbb
18.	abbbbbaabbbbb ⇒ abbbbbbbbbbaa
19.	abbbbbbbaabbbbaa ⇒ abbbbbbbb
20.	abbbbbbbbaabbbbaa ⇒ abbbbbbbbb
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:	[3/0] bbb, [3/1] abb, [3/2] baa, [3/3] bba, [3/4] aab, [3/5] bab, [3/6] aba
Length 4:	[4/0] bbbb, [4/1] abbb, [4/2] bbaa, [4/3] bbba, [4/4] aabb, [4/5] baab, [4/6] bbab
Length 5:	[5/0] abbbb, [5/1] bbbaa, [5/2] bbbbb, [5/3] bbbba, [5/4] aabbb, [5/5] baabb, [5/6] bbaab
Length 6:	[6/0] bbbbaa, [6/1] abbbbb, [6/2] aabbbb, [6/3] abbbba, [6/4] baabbb, [6/5] bbaabb, [6/6] bbbaab
Length 7:	[7/0] abbbbaa, [7/1] baabbbb, [7/2] bbaabbb, [7/3] aabbbba, [7/4] aabbbbb, [7/5] bbbaabb, [7/6] abbbbab

Considering [length 5 / frequency 0] abbbb=c.

Reduction order:
- Left-to-right recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1
Auxiliary generators:
1. abbbb=c

Rewriting system is complete. See ⟨a, b | aaabbbbaa=ab⟩.