Morphocompletion for #4043 ⟨a, b | aaabbbaba=ba⟩

Back:⟨a, b | aaabbbaba=ba⟩

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aaabbbaba ⇒ ba
2. aaabbbabba ⇒ bba
3. aaabbbabbba ⇒ bbba
4. aaabbbabbbba ⇒ bbbba
5. aaabbbabbbbba ⇒ bbbbba
6. aaabbbabbbbbba ⇒ bbbbbba
7. aaabbbabbbbbbba ⇒ bbbbbbba
8. aaabbbabbbbbbbba ⇒ bbbbbbbba
9. aaabbbabbbbbbbbba ⇒ bbbbbbbbba
10. aaabbbabbbbbbbbbba ⇒ bbbbbbbbbba
11. aaabbbabbbbbbbbbbba ⇒ bbbbbbbbbbba
12. aaabbbabbbbbbbbbbbba ⇒ bbbbbbbbbbbba
13. aaabbbabbbbbbbbbbbbba ⇒ bbbbbbbbbbbbba
14. aaabbbabbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbba
15. aaabbbabbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbba
16. aaabbbabbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbba
17. aaabbbabbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbba
18. aaabbbabbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbba
19. aaabbbabbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbba
20. aaabbbabbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb230lf:230,rf:190,rp:19
[2/1]ba60lf:40,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20
[2/2]aa60lf:40,lp:20
[2/3]ab40lf:40
[3/0]bbb191lf:191,rf:171,rp:18
[3/1]bba58lf:39,ls:19,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19
[3/2]aaa40lf:20,lp:20
[3/3]abb39lf:39
[3/4]bab20lf:20
[3/5]aab20lf:20
[3/6]aba2lf:1,ls:1
[4/0]bbbb153lf:153,rf:153,rp:17,a:3
[4/1]bbba56lf:38,ls:18,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18
[4/2]aaab40lf:20,lp:20
[4/3]abbb38lf:38
[4/4]bbab20lf:20
[4/5]aabb20lf:20
[4/6]babb19lf:19,a:1
[5/0]bbbbb136lf:136,rf:136,rp:16,a:4
[5/1]aaabb40lf:20,lp:20
[5/2]bbbba34lf:17,ls:17,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17,a:3
[5/3]abbba22lf:21,ls:1
[5/4]bbbab20lf:20
[5/5]aabbb20lf:20
[5/6]bbabb19lf:19,a:1
[6/0]bbbbbb120lf:120,rf:120,rp:15,a:5
[6/1]aaabbb40lf:20,lp:20
[6/2]bbbbba32lf:16,ls:16,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:4
[6/3]abbbab20lf:20
[6/4]aabbba20lf:20
[6/5]bbbabb19lf:19,a:1
[6/6]bbabbb18lf:18,a:2
[7/0]bbbbbbb105lf:105,rf:105,rp:14,a:6
[7/1]aaabbba40lf:20,lp:20
[7/2]bbbbbba30lf:15,ls:15,rf:15,rp:1,rs:15,re:1,lsrp:1,lsrs:15,a:5
[7/3]aabbbab20lf:20
[7/4]abbbabb19lf:19,a:1
[7/5]bbbabbb18lf:18,a:2
[7/6]bbabbbb17lf:17,a:3

Considering [length 3 / frequency 1] bba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbbaba=ba⟩.