Morphocompletion for #4042 ⟨a, b | aaabbbaba=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaabbbaba ⇒ ab
2. abaabbbaba ⇒ abb
3. aaabbbabb ⇒ ababbbaba
4. abbaabbbaba ⇒ abbb
5. abaabbbabb ⇒ abbabbbaba
6. abbbaabbbaba ⇒ abbbb
7. abbaabbbabb ⇒ abbbabbbaba
8. abbbbaabbbaba ⇒ abbbbb
9. abbbaabbbabb ⇒ abbbbabbbaba
10. abbbbbaabbbaba ⇒ abbbbbb
11. abbbbaabbbabb ⇒ abbbbbabbbaba
12. abbbbbbaabbbaba ⇒ abbbbbbb
13. abbbbbaabbbabb ⇒ abbbbbbabbbaba
14. abbbbbbbaabbbaba ⇒ abbbbbbbb
15. abbbbbbaabbbabb ⇒ abbbbbbbabbbaba
16. abbbbbbbbaabbbaba ⇒ abbbbbbbbb
17. abbbbbbbaabbbabb ⇒ abbbbbbbbabbbaba
18. abbbbbbbbbaabbbaba ⇒ abbbbbbbbbb
19. abbbbbbbbbbaabbbaba ⇒ abbbbbbbbbbb
20. abbbbbbbbbbbaabbbaba ⇒ abbbbbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb132lf:124,ls:8,rf:110,rs:11
[2/1]ab76lf:58,lp:18,rf:36,rp:20,rs:1,re:1,lprp:18
[2/2]ba62lf:50,ls:12,rf:24,rs:8
[2/3]aa24lf:22,lp:2
[3/0]bbb80lf:80,rf:84,rs:10
[3/1]abb68lf:44,lp:16,ls:8,rf:26,rp:18,rs:1,re:1,lprp:16,lsrp:7
[3/2]bba36lf:36,rf:15
[3/3]aba28lf:14,lp:2,ls:12,rf:9,rp:1,rs:8,lprs:1
[3/4]bab20lf:20,rf:16
[3/5]aab20lf:20
[3/6]baa18lf:18,a:1
[4/0]abbb48lf:34,lp:14,rf:24,rp:16,rs:1,re:1,lprp:14
[4/1]bbbb46lf:46,rf:60,rs:9,a:5
[4/2]bbba34lf:34,rf:14
[4/3]baba24lf:12,ls:12,rf:8,rs:8
[4/4]bbab20lf:20,rf:15
[4/5]aabb20lf:20
[4/6]baab18lf:18,a:1
[5/0]bbbbb34lf:34,rf:46,rs:8,a:6
[5/1]abbbb24lf:12,lp:12,rf:14,rp:14,rs:1,re:1,lprp:12,a:5
[5/2]abbba24lf:22,lp:2,rf:9,rp:1
[5/3]bbaba24lf:12,ls:12,rf:8,rs:8
[5/4]bbbab20lf:20,rf:14
[5/5]aabbb20lf:20
[5/6]baabb18lf:18,a:1
[6/0]bbbbbb24lf:24,rf:34,rs:7,a:8
[6/1]bbbaba24lf:12,ls:12,rf:8,rs:8
[6/2]abbbbb20lf:10,lp:10,rf:12,rp:12,rs:1,re:1,lprp:10,a:6
[6/3]abbbab20lf:20,rf:9,rp:1
[6/4]aabbba20lf:20
[6/5]baabbb18lf:18,a:1
[6/6]bbbabb16lf:8,ls:8,rf:6,a:2
[7/0]abbbaba24lf:12,ls:12,rf:8,rs:8
[7/1]aabbbab20lf:20
[7/2]baabbba18lf:18,a:1
[7/3]bbbbbbb16lf:16,rf:24,rs:6,a:9
[7/4]abbbbbb16lf:8,lp:8,rf:10,rp:10,rs:1,re:1,lprp:8,a:8
[7/5]abbbabb16lf:8,ls:8,rf:1,rp:1,lsrp:1,a:2
[7/6]bbaabbb16lf:16,a:3

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbbaba=ab⟩.