Morphocompletion for #4042 ⟨a, b | aaabbbaba=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	aaabbbaba ⇒ ab
2.	abaabbbaba ⇒ abb
3.	aaabbbabb ⇒ ababbbaba
4.	abbaabbbaba ⇒ abbb
5.	abaabbbabb ⇒ abbabbbaba
6.	abbbaabbbaba ⇒ abbbb
7.	abbaabbbabb ⇒ abbbabbbaba
8.	abbbbaabbbaba ⇒ abbbbb
9.	abbbaabbbabb ⇒ abbbbabbbaba
10.	abbbbbaabbbaba ⇒ abbbbbb
11.	abbbbaabbbabb ⇒ abbbbbabbbaba
12.	abbbbbbaabbbaba ⇒ abbbbbbb
13.	abbbbbaabbbabb ⇒ abbbbbbabbbaba
14.	abbbbbbbaabbbaba ⇒ abbbbbbbb
15.	abbbbbbaabbbabb ⇒ abbbbbbbabbbaba
16.	abbbbbbbbaabbbaba ⇒ abbbbbbbbb
17.	abbbbbbbaabbbabb ⇒ abbbbbbbbabbbaba
18.	abbbbbbbbbaabbbaba ⇒ abbbbbbbbbb
19.	abbbbbbbbbbaabbbaba ⇒ abbbbbbbbbbb
20.	abbbbbbbbbbbaabbbaba ⇒ abbbbbbbbbbbb
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:	[3/0] bbb, [3/1] abb, [3/2] bba, [3/3] aba, [3/4] bab, [3/5] aab, [3/6] baa
Length 4:	[4/0] abbb, [4/1] bbbb, [4/2] bbba, [4/3] baba, [4/4] bbab, [4/5] aabb, [4/6] baab
Length 5:	[5/0] bbbbb, [5/1] abbbb, [5/2] abbba, [5/3] bbaba, [5/4] bbbab, [5/5] aabbb, [5/6] baabb
Length 6:	[6/0] bbbbbb, [6/1] bbbaba, [6/2] abbbbb, [6/3] abbbab, [6/4] aabbba, [6/5] baabbb, [6/6] bbbabb
Length 7:	[7/0] abbbaba, [7/1] aabbbab, [7/2] baabbba, [7/3] bbbbbbb, [7/4] abbbbbb, [7/5] abbbabb, [7/6] bbaabbb

Considering [length 4 / frequency 0] abbb=c.

Reduction order:
- Left-to-right recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1
Auxiliary generators:
1. abbb=c

Rewriting system is complete. See ⟨a, b | aaabbbaba=ab⟩.