Morphocompletion for #4035 ⟨a, b | aaabbbaaa=ab

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbaaa ⇒ ab
2. abaabbbaaa ⇒ abb
3. aaabbbab ⇒ abbbbaaa
4. aaabbbaab ⇒ ababbbaaa
5. abbaabbbaaa ⇒ abbb
6. abaabbbab ⇒ abbbbbaaa
7. abaabbbaab ⇒ abbabbbaaa
8. abbbaabbbaaa ⇒ abbbb
9. abbaabbbab ⇒ abbbbbbaaa
10. abbaabbbaab ⇒ abbbabbbaaa
11. ababbbaaabbaaa ⇒ aaabbbb
12. abbbbaabbbaaa ⇒ abbbbb
13. abbbaabbbab ⇒ abbbbbbbaaa
14. abbabbbaaabbaaa ⇒ abaabbbb
15. abbbbbaabbbaaa ⇒ abbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] bb, [2/3] ba
Length 3:[3/0] abb, [3/1] bba, [3/2] aaa, [3/3] baa, [3/4] bbb, [3/5] aab, [3/6] bab
Length 4:[4/0] abbb, [4/1] bbaa, [4/2] bbba, [4/3] baaa, [4/4] baab, [4/5] aabb, [4/6] abba
Length 5:[5/0] abbba, [5/1] bbaaa, [5/2] bbbaa, [5/3] aabbb, [5/4] bbaab, [5/5] baabb, [5/6] bbbab
Length 6:[6/0] abbbaa, [6/1] bbbaaa, [6/2] aabbba, [6/3] baabbb, [6/4] bbbaab, [6/5] abbbab, [6/6] bbaabb
Length 7:[7/0] abbbaaa, [7/1] abbbaab, [7/2] baabbba, [7/3] aabbbaa, [7/4] aabbbab, [7/5] bbaabbb, [7/6] abaabbb

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See a, b | aaabbbaaa=ab.