Morphocompletion for #4035 ⟨a, b | aaabbbaaa=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbaaa ⇒ ab
2. abaabbbaaa ⇒ abb
3. aaabbbab ⇒ abbbbaaa
4. aaabbbaab ⇒ ababbbaaa
5. abbaabbbaaa ⇒ abbb
6. abaabbbab ⇒ abbbbbaaa
7. abaabbbaab ⇒ abbabbbaaa
8. abbbaabbbaaa ⇒ abbbb
9. abbaabbbab ⇒ abbbbbbaaa
10. abbaabbbaab ⇒ abbbabbbaaa
11. ababbbaaabbaaa ⇒ aaabbbb
12. abbbbaabbbaaa ⇒ abbbbb
13. abbbaabbbab ⇒ abbbbbbbaaa
14. abbabbbaaabbaaa ⇒ abaabbbb
15. abbbbbaabbbaaa ⇒ abbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab55lf:36,lp:12,ls:7,rf:19,rp:14,rs:1,re:1,lprp:11,lsrp:7
[2/1]aa50lf:39,lp:3,ls:8,rf:17,rp:1,rs:7,lsrp:1,lprs:2
[2/2]bb47lf:47,rf:48,rs:7
[2/3]ba29lf:29,rf:11
[3/0]abb33lf:25,lp:8,rf:16,rp:11,rs:1,re:1,lprp:7
[3/1]bba25lf:25,rf:9
[3/2]aaa24lf:13,lp:3,ls:8,rf:8,rp:1,rs:7,lsrp:1,lprs:2
[3/3]baa23lf:23,rf:8
[3/4]bbb22lf:22,rf:32,rs:6
[3/5]aab21lf:18,ls:3,rf:2
[3/6]bab10lf:6,ls:4,rf:3,a:1
[4/0]abbb23lf:19,lp:4,rf:14,rp:9,rs:1,re:1,lprp:4
[4/1]bbaa20lf:20,rf:7
[4/2]bbba19lf:19,rf:8
[4/3]baaa18lf:10,ls:8,rf:7,rs:7
[4/4]baab16lf:13,ls:3,rf:1,a:2
[4/5]aabb15lf:15,rf:2
[4/6]abba10lf:6,lp:4,rf:1,rp:1,a:4
[5/0]abbba19lf:17,lp:2,rf:4,rp:1
[5/1]bbaaa18lf:10,ls:8,rf:7,rs:7
[5/2]bbbaa15lf:15,rf:7
[5/3]aabbb13lf:13,rf:2
[5/4]bbaab13lf:10,ls:3,a:2
[5/5]baabb10lf:10,rf:1,a:3
[5/6]bbbab8lf:4,ls:4,rf:1,a:1
[6/0]abbbaa15lf:13,lp:2,rf:3
[6/1]bbbaaa14lf:8,ls:6,rf:7,rs:7
[6/2]aabbba13lf:13
[6/3]baabbb10lf:10,rf:1,a:3
[6/4]bbbaab10lf:7,ls:3,a:2
[6/5]abbbab8lf:4,ls:4,rf:1,rp:1,a:1
[6/6]bbaabb7lf:7,a:4
[7/0]abbbaaa14lf:8,ls:6,rf:3,rs:3
[7/1]abbbaab10lf:5,lp:2,ls:3,a:2
[7/2]baabbba10lf:10,a:3
[7/3]aabbbaa9lf:9
[7/4]aabbbab8lf:4,ls:4,a:1
[7/5]bbaabbb7lf:7,a:4
[7/6]abaabbb6lf:3,lp:3,rf:1,rp:1,a:3

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbbaaa=ab⟩.