| Back: | ⟨a, b | aaabbabba=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaabbabba ⇒ ab |
| 2. | ababbabba ⇒ aaabbabbb |
| 3. | abaabbabba ⇒ abb |
| 4. | aaabaabbabbb ⇒ abbba |
| 5. | abbabbabba ⇒ abaabbabbb |
| 6. | abbaabbabba ⇒ abbb |
| 7. | abaabaabbabbb ⇒ abbbba |
| 8. | aaabbabbbbba ⇒ ababaabbabbb |
| 9. | abbbabbabba ⇒ abbaabbabbb |
| 10. | abbbaabbabba ⇒ abbbb |
| 11. | abbaabaabbabbb ⇒ abbbbba |
| 12. | abbbbabbabba ⇒ abbbaabbabbb |
| 13. | abbbbaabbabba ⇒ abbbbb |
| 14. | abbbaabaabbabbb ⇒ abbbbbba |
| 15. | abbbbbaabbabba ⇒ abbbbbb |
| 16. | abbbbaabaabbabbb ⇒ abbbbbbba |
| 17. | abbbbbbaabbabba ⇒ abbbbbbb |
| 18. | abbbbbbbaabbabba ⇒ abbbbbbbb |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] abb, [3/1] bba, [3/2] bbb, [3/3] bab, [3/4] aab, [3/5] baa, [3/6] aba |
| Length 4: | [4/0] abba, [4/1] abbb, [4/2] babb, [4/3] bbab, [4/4] baab, [4/5] bbbb, [4/6] aabb |
| Length 5: | [5/0] babba, [5/1] bbabb, [5/2] abbab, [5/3] aabba, [5/4] abbbb, [5/5] baabb, [5/6] babbb |
| Length 6: | [6/0] bbabba, [6/1] abbabb, [6/2] aabbab, [6/3] baabba, [6/4] bbabbb, [6/5] abbbbb, [6/6] bbbaab |
| Length 7: | [7/0] abbabba, [7/1] aabbabb, [7/2] baabbab, [7/3] abbabbb, [7/4] abaabba, [7/5] bbaabba, [7/6] bbbbaab |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aaabbabba=ab⟩.