Morphocompletion for #4031 ⟨a, b | aaabbabba=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbabba ⇒ ab
2. ababbabba ⇒ aaabbabbb
3. abaabbabba ⇒ abb
4. aaabaabbabbb ⇒ abbba
5. abbabbabba ⇒ abaabbabbb
6. abbaabbabba ⇒ abbb
7. abaabaabbabbb ⇒ abbbba
8. aaabbabbbbba ⇒ ababaabbabbb
9. abbbabbabba ⇒ abbaabbabbb
10. abbbaabbabba ⇒ abbbb
11. abbaabaabbabbb ⇒ abbbbba
12. abbbbabbabba ⇒ abbbaabbabbb
13. abbbbaabbabba ⇒ abbbbb
14. abbbaabaabbabbb ⇒ abbbbbba
15. abbbbbaabbabba ⇒ abbbbbb
16. abbbbaabaabbabbb ⇒ abbbbbbba
17. abbbbbbaabbabba ⇒ abbbbbbb
18. abbbbbbbaabbabba ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] abb, [3/1] bba, [3/2] bbb, [3/3] bab, [3/4] aab, [3/5] baa, [3/6] aba
Length 4:[4/0] abba, [4/1] abbb, [4/2] babb, [4/3] bbab, [4/4] baab, [4/5] bbbb, [4/6] aabb
Length 5:[5/0] babba, [5/1] bbabb, [5/2] abbab, [5/3] aabba, [5/4] abbbb, [5/5] baabb, [5/6] babbb
Length 6:[6/0] bbabba, [6/1] abbabb, [6/2] aabbab, [6/3] baabba, [6/4] bbabbb, [6/5] abbbbb, [6/6] bbbaab
Length 7:[7/0] abbabba, [7/1] aabbabb, [7/2] baabbab, [7/3] abbabbb, [7/4] abaabba, [7/5] bbaabba, [7/6] bbbbaab

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aaabbabba=ab.