| Back: | ⟨a, b | aaabbabaa=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | aaabbabaa ⇒ ab |
| 2. | abaabbabaa ⇒ abb |
| 3. | aaabbabb ⇒ abbbabaa |
| 4. | aaabbabab ⇒ ababbabaa |
| 5. | abbaabbabaa ⇒ abbb |
| 6. | abaabbabb ⇒ abbbbabaa |
| 7. | abaabbabab ⇒ abbabbabaa |
| 8. | abbbaabbabaa ⇒ abbbb |
| 9. | abbaabbabb ⇒ abbbbbabaa |
| 10. | abbaabbabab ⇒ abbbabbabaa |
| 11. | abbbbaabbabaa ⇒ abbbbb |
| 12. | abbbaabbabb ⇒ abbbbbbabaa |
| 13. | abbbaabbabab ⇒ abbbbabbabaa |
| 14. | abbbbbaabbabaa ⇒ abbbbbb |
| 15. | abbbbaabbabb ⇒ abbbbbbbabaa |
| 16. | abbbbaabbabab ⇒ abbbbbabbabaa |
| 17. | abbbbbbaabbabaa ⇒ abbbbbbb |
| 18. | abbbbbaabbabb ⇒ abbbbbbbbabaa |
| 19. | abbbbbbbaabbabaa ⇒ abbbbbbbb |
| 20. | abbbbbbbbaabbabaa ⇒ abbbbbbbbb |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] abb, [3/1] baa, [3/2] bba, [3/3] bbb, [3/4] bab, [3/5] aab, [3/6] aba |
| Length 4: | [4/0] abba, [4/1] abaa, [4/2] abbb, [4/3] bbab, [4/4] aabb, [4/5] bbbb, [4/6] baab |
| Length 5: | [5/0] abbab, [5/1] aabba, [5/2] babaa, [5/3] baabb, [5/4] abbbb, [5/5] bbaab, [5/6] bbaba |
| Length 6: | [6/0] aabbab, [6/1] bbabaa, [6/2] baabba, [6/3] bbaabb, [6/4] abbaba, [6/5] abbabb, [6/6] bbbaab |
| Length 7: | [7/0] abbabaa, [7/1] baabbab, [7/2] bbaabba, [7/3] aabbaba, [7/4] aabbabb, [7/5] bbbaabb, [7/6] abbabab |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aaabbabaa=ab⟩.