| Back: | ⟨a, b | aaabbabaa=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | aaabbabaa ⇒ ab |
| 2. | abaabbabaa ⇒ abb |
| 3. | aaabbabb ⇒ abbbabaa |
| 4. | aaabbabab ⇒ ababbabaa |
| 5. | abbaabbabaa ⇒ abbb |
| 6. | abaabbabb ⇒ abbbbabaa |
| 7. | abaabbabab ⇒ abbabbabaa |
| 8. | abbbaabbabaa ⇒ abbbb |
| 9. | abbaabbabb ⇒ abbbbbabaa |
| 10. | abbaabbabab ⇒ abbbabbabaa |
| 11. | abbbbaabbabaa ⇒ abbbbb |
| 12. | abbbaabbabb ⇒ abbbbbbabaa |
| 13. | abbbaabbabab ⇒ abbbbabbabaa |
| 14. | abbbbbaabbabaa ⇒ abbbbbb |
| 15. | abbbbaabbabb ⇒ abbbbbbbabaa |
| 16. | abbbbaabbabab ⇒ abbbbbabbabaa |
| 17. | abbbbbbaabbabaa ⇒ abbbbbbb |
| 18. | abbbbbaabbabb ⇒ abbbbbbbbabaa |
| 19. | abbbbbbbaabbabaa ⇒ abbbbbbbb |
| 20. | abbbbbbbbaabbabaa ⇒ abbbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 84 | lf:62,lp:17,ls:5,rf:36,rp:20,rs:1,re:1,lprp:17,lsrp:5 |
|---|---|---|---|
| [2/1] | bb | 76 | lf:70,ls:6,rf:78,rs:8 |
| [2/2] | ba | 51 | lf:51,rf:27 |
| [2/3] | aa | 44 | lf:32,lp:3,ls:9,rf:11,rs:11,lprs:2 |
| [3/0] | abb | 60 | lf:40,lp:14,ls:6,rf:23,rp:18,rs:1,re:1,lprp:14,lsrp:6 |
| [3/1] | baa | 35 | lf:26,ls:9,rf:11,rs:11 |
| [3/2] | bba | 34 | lf:34,rf:15 |
| [3/3] | bbb | 30 | lf:30,rf:55,rs:7,a:3 |
| [3/4] | bab | 30 | lf:25,ls:5,rf:16 |
| [3/5] | aab | 20 | lf:20 |
| [3/6] | aba | 20 | lf:17,lp:3,rf:12,rp:1 |
| [4/0] | abba | 26 | lf:23,lp:3,rf:6,rp:1 |
| [4/1] | abaa | 24 | lf:12,lp:3,ls:9,rf:11,rs:11,lprs:2 |
| [4/2] | abbb | 22 | lf:11,lp:11,rf:16,rp:16,rs:1,re:1,lprp:11,a:3 |
| [4/3] | bbab | 20 | lf:20,rf:15 |
| [4/4] | aabb | 20 | lf:20 |
| [4/5] | bbbb | 19 | lf:19,rf:39,rs:6,a:6 |
| [4/6] | baab | 17 | lf:17,a:2 |
| [5/0] | abbab | 20 | lf:20,rf:6,rp:1 |
| [5/1] | aabba | 20 | lf:20 |
| [5/2] | babaa | 18 | lf:9,ls:9,rf:11,rs:11 |
| [5/3] | baabb | 17 | lf:17,a:2 |
| [5/4] | abbbb | 16 | lf:8,lp:8,rf:13,rp:13,rs:1,re:1,lprp:8,a:6 |
| [5/5] | bbaab | 14 | lf:14,a:4 |
| [5/6] | bbaba | 14 | lf:14,rf:11 |
| [6/0] | aabbab | 20 | lf:20 |
| [6/1] | bbabaa | 18 | lf:9,ls:9,rf:11,rs:11 |
| [6/2] | baabba | 17 | lf:17,a:2 |
| [6/3] | bbaabb | 14 | lf:14,a:4 |
| [6/4] | abbaba | 14 | lf:14,rf:5 |
| [6/5] | abbabb | 12 | lf:6,ls:6,rf:1,rp:1,a:3 |
| [6/6] | bbbaab | 11 | lf:11,a:7 |
| [7/0] | abbabaa | 18 | lf:9,ls:9,rf:5,rs:5 |
| [7/1] | baabbab | 17 | lf:17,a:2 |
| [7/2] | bbaabba | 14 | lf:14,a:4 |
| [7/3] | aabbaba | 14 | lf:14 |
| [7/4] | aabbabb | 12 | lf:6,ls:6,a:3 |
| [7/5] | bbbaabb | 11 | lf:11,a:7 |
| [7/6] | abbabab | 10 | lf:5,ls:5,a:1 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aaabbabaa=ab⟩.