Morphocompletion for #4023 ⟨a, b | aaabbabaa=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaabbabaa ⇒ ab
2. abaabbabaa ⇒ abb
3. aaabbabb ⇒ abbbabaa
4. aaabbabab ⇒ ababbabaa
5. abbaabbabaa ⇒ abbb
6. abaabbabb ⇒ abbbbabaa
7. abaabbabab ⇒ abbabbabaa
8. abbbaabbabaa ⇒ abbbb
9. abbaabbabb ⇒ abbbbbabaa
10. abbaabbabab ⇒ abbbabbabaa
11. abbbbaabbabaa ⇒ abbbbb
12. abbbaabbabb ⇒ abbbbbbabaa
13. abbbaabbabab ⇒ abbbbabbabaa
14. abbbbbaabbabaa ⇒ abbbbbb
15. abbbbaabbabb ⇒ abbbbbbbabaa
16. abbbbaabbabab ⇒ abbbbbabbabaa
17. abbbbbbaabbabaa ⇒ abbbbbbb
18. abbbbbaabbabb ⇒ abbbbbbbbabaa
19. abbbbbbbaabbabaa ⇒ abbbbbbbb
20. abbbbbbbbaabbabaa ⇒ abbbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa
Length 3:[3/0] abb, [3/1] baa, [3/2] bba, [3/3] bbb, [3/4] bab, [3/5] aab, [3/6] aba
Length 4:[4/0] abba, [4/1] abaa, [4/2] abbb, [4/3] bbab, [4/4] aabb, [4/5] bbbb, [4/6] baab
Length 5:[5/0] abbab, [5/1] aabba, [5/2] babaa, [5/3] baabb, [5/4] abbbb, [5/5] bbaab, [5/6] bbaba
Length 6:[6/0] aabbab, [6/1] bbabaa, [6/2] baabba, [6/3] bbaabb, [6/4] abbaba, [6/5] abbabb, [6/6] bbbaab
Length 7:[7/0] abbabaa, [7/1] baabbab, [7/2] bbaabba, [7/3] aabbaba, [7/4] aabbabb, [7/5] bbbaabb, [7/6] abbabab

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aaabbabaa=ab.