Morphocompletion for #402 ⟨a, b | ababaab=b⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aabb ⇒ baab
2. ababb ⇒ babab
3. ababab ⇒ babaab
4. ababaab ⇒ b
5. aababb ⇒ babaab
6. babaabaab ⇒ abb
7. abbabb ⇒ babbab
8. abbabab ⇒ babbaab
9. abbabaab ⇒ babaabab
10. ababbb ⇒ bbabab
11. ababbab ⇒ bbabaab
12. ababbaab ⇒ bb
13. babbaabaab ⇒ abbb
14. abbbabb ⇒ babbbab
15. abbbabab ⇒ babbbaab
16. abbbabaab ⇒ babbaabab
17. ababbbaab ⇒ bbb
18. babbbaabaab ⇒ abbbb
19. abbbbabb ⇒ babbbbab
20. abbbbabab ⇒ babbbbaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab80lf:52,lp:15,ls:13,rf:32,rp:3,rs:14,lsrp:3,lprs:12,lsrs:7
[2/1]ba38lf:35,lp:3,rf:29,rp:12
[2/2]bb37lf:30,ls:7,rf:24,rp:4,rs:5,re:1,lsrp:1,a:2
[2/3]aa15lf:13,lp:2,rf:9
[3/0]abb34lf:20,lp:8,ls:6,rf:10,rp:3,rs:1,re:1,a:2
[3/1]bab32lf:24,lp:3,ls:5,rf:20,rp:11,rs:7,lsrp:4
[3/2]aba26lf:19,lp:7,rf:8
[3/3]aab23lf:13,lp:2,ls:8,rf:9,rs:7,lprs:11
[3/4]bba13lf:13,rf:9,rp:2,a:3
[3/5]bbb11lf:10,ls:1,rf:10,rp:1,rs:3,re:1,a:7
[3/6]baa11lf:11,rf:9,rp:1
[4/0]abab23lf:12,lp:7,ls:4,rf:4,rs:4,lprs:11
[4/1]baab19lf:11,ls:8,rf:9,rp:1,rs:7,re:1
[4/2]babb18lf:11,lp:2,ls:5,rf:7,rp:7,lsrp:3,a:5
[4/3]abbb14lf:8,lp:5,ls:1,rf:6,rp:2,rs:1,re:1,a:7
[4/4]bbab10lf:9,ls:1,rf:5,rp:2,rs:3,lsrp:1,a:3
[4/5]abba9lf:6,lp:3,rf:3,a:3
[4/6]baba9lf:8,lp:1,rf:6,rp:4
[5/0]abaab13lf:7,ls:6,rf:4,rs:3
[5/1]ababb10lf:5,lp:4,ls:1,a:6
[5/2]abbab8lf:4,lp:3,ls:1,rf:1,rs:1,lprs:10,a:3
[5/3]abbba8lf:5,lp:3,rf:2,a:11
[5/4]babab8lf:4,ls:4,rf:2,rp:1,rs:2,re:1,a:1
[5/5]bbabb6lf:3,ls:3,a:12
[5/6]bbaab6lf:4,ls:2,rf:4,rs:3,a:5
[6/0]babaab8lf:4,lp:1,ls:3,rf:4,rp:3,rs:3,re:2,lsrp:1
[6/1]abbbab6lf:3,lp:3,rf:1,rs:1,lprs:10,a:20
[6/2]bbabab6lf:3,ls:3,rf:1,rp:1,rs:1,re:1,a:5
[6/3]aabaab6lf:3,ls:3,a:2
[6/4]bbbabb4lf:2,ls:2,a:26
[6/5]abbbba4lf:2,lp:2,rf:2,a:28
[6/6]ababba4lf:2,lp:2,a:6
[7/0]baabaab6lf:3,ls:3,a:2
[7/1]abbbbab4lf:2,lp:2,rf:1,rs:1,lprs:10,a:28
[7/2]bbbabab4lf:2,ls:2,a:25
[7/3]abbbaba4lf:2,lp:2,a:20
[7/4]babbaab4lf:2,lp:1,ls:1,rf:2,rp:2,rs:1,re:1,a:5
[7/5]bbabaab4lf:2,ls:2,rf:1,rp:1,rs:1,re:1,a:3
[7/6]abbbaab3lf:2,ls:1,rf:1,rs:1,a:11

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababaab=b⟩.