Morphocompletion for #402 ⟨a, b | ababaab=b⟩

Back:⟨a, b | ababaab=b⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aabb ⇒ baab
2. ababb ⇒ babab
3. ababab ⇒ babaab
4. ababaab ⇒ b
5. aababb ⇒ babaab
6. babaabaab ⇒ abb
7. abbabb ⇒ babbab
8. abbabab ⇒ babbaab
9. abbabaab ⇒ babaabab
10. ababbb ⇒ bbabab
11. ababbab ⇒ bbabaab
12. ababbaab ⇒ bb
13. babbaabaab ⇒ abbb
14. abbbabb ⇒ babbbab
15. abbbabab ⇒ babbbaab
16. abbbabaab ⇒ babbaabab
17. ababbbaab ⇒ bbb
18. babbbaabaab ⇒ abbbb
19. abbbbabb ⇒ babbbbab
20. abbbbabab ⇒ babbbbaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] abb, [3/1] bab, [3/2] aba, [3/3] aab, [3/4] bba, [3/5] bbb, [3/6] baa
Length 4:[4/0] abab, [4/1] baab, [4/2] babb, [4/3] abbb, [4/4] bbab, [4/5] abba, [4/6] baba
Length 5:[5/0] abaab, [5/1] ababb, [5/2] abbab, [5/3] abbba, [5/4] babab, [5/5] bbabb, [5/6] bbaab
Length 6:[6/0] babaab, [6/1] abbbab, [6/2] bbabab, [6/3] aabaab, [6/4] bbbabb, [6/5] abbbba, [6/6] ababba
Length 7:[7/0] baabaab, [7/1] abbbbab, [7/2] bbbabab, [7/3] abbbaba, [7/4] babbaab, [7/5] bbabaab, [7/6] abbbaab

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababaab=b⟩.