Morphocompletion for #4016 ⟨a, b | aaabbaaba=ba⟩

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#	Rule
1.	aaabbaaba ⇒ ba
2.	aaabbaabba ⇒ bba
3.	aaabbaabbba ⇒ bbba
4.	aaabbaabbbba ⇒ bbbba
5.	aaabbaabbbbba ⇒ bbbbba
6.	aaabbaabbbbbba ⇒ bbbbbba
7.	aaabbaabbbbbbba ⇒ bbbbbbba
8.	aaabbaabbbbbbbba ⇒ bbbbbbbba
9.	aaabbaabbbbbbbbba ⇒ bbbbbbbbba
10.	aaabbaabbbbbbbbbba ⇒ bbbbbbbbbba
11.	aaabbaabbbbbbbbbbba ⇒ bbbbbbbbbbba
12.	aaabbaabbbbbbbbbbbba ⇒ bbbbbbbbbbbba
13.	aaabbaabbbbbbbbbbbbba ⇒ bbbbbbbbbbbbba
14.	aaabbaabbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbba
15.	aaabbaabbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbba
16.	aaabbaabbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbba
17.	aaabbaabbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbba
18.	aaabbaabbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbba
19.	aaabbaabbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbba
20.	aaabbaabbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbbba
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] bb, [2/1] aa, [2/2] ba, [2/3] ab
Length 3:	[3/0] bbb, [3/1] bba, [3/2] aab, [3/3] aaa, [3/4] abb, [3/5] baa, [3/6] aba
Length 4:	[4/0] bbbb, [4/1] aaab, [4/2] aabb, [4/3] bbba, [4/4] abba, [4/5] bbaa, [4/6] baab
Length 5:	[5/0] bbbbb, [5/1] aaabb, [5/2] bbbba, [5/3] aabba, [5/4] bbaab, [5/5] abbaa, [5/6] baabb
Length 6:	[6/0] bbbbbb, [6/1] aaabba, [6/2] bbbbba, [6/3] abbaab, [6/4] aabbaa, [6/5] bbaabb, [6/6] baabbb
Length 7:	[7/0] bbbbbbb, [7/1] aaabbaa, [7/2] bbbbbba, [7/3] aabbaab, [7/4] abbaabb, [7/5] bbaabbb, [7/6] baabbbb

Considering [length 3 / frequency 1] bba=c.

Reduction order:
- Right-to-left recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1
Auxiliary generators:
1. bba=c

Rewriting system is complete. See ⟨a, b | aaabbaaba=ba⟩.