Morphocompletion for #4015 ⟨a, b | aaabbaaba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbaaba ⇒ ab
2. abaabbaaba ⇒ abb
3. aaabbaabb ⇒ ababbaaba
4. abbaabbaaba ⇒ abbb
5. ababbaabaaaba ⇒ aaabbb
6. abaabbaabb ⇒ abbabbaaba
7. aaabbaaaabbb ⇒ abbbaabaaaba
8. abbbaabbaaba ⇒ abbbb
9. abbabbaabaaaba ⇒ abaabbb
10. abbaabbaabb ⇒ abbbabbaaba
11. abbbbaabbaaba ⇒ abbbbb
12. abbbabbaabaaaba ⇒ abbaabbb
13. abbbbbaabbaaba ⇒ abbbbbb
14. abbbbbbaabbaaba ⇒ abbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab53lf:42,lp:11,rf:24,rp:13,rs:1,re:1,lprp:10
[2/1]ba48lf:38,ls:10,rf:14,rs:4
[2/2]bb42lf:38,ls:4,rf:36,rs:9
[2/3]aa39lf:36,lp:3,rf:10,rp:1
[3/0]abb37lf:26,lp:8,ls:3,rf:16,rp:10,rs:1,re:1,lprp:7,lsrp:2
[3/1]aba29lf:16,lp:3,ls:10,rf:7,rp:2,rs:4,lsrp:1,lprs:1
[3/2]aab28lf:28,rf:8
[3/3]baa25lf:25,rf:7
[3/4]bba22lf:22,rf:7
[3/5]bbb13lf:12,ls:1,rf:20,rs:8,a:3
[3/6]aaa11lf:8,lp:3,rf:2,rp:1
[4/0]aaba23lf:13,ls:10,rf:5,rs:4
[4/1]baab21lf:21,rf:6
[4/2]abba20lf:17,lp:3,rf:5,rp:2
[4/3]bbaa20lf:20,rf:5
[4/4]aabb18lf:15,ls:3,rf:3
[4/5]abbb12lf:6,lp:5,ls:1,rf:10,rp:7,rs:4,re:1,lprp:4,lsrp:1,lprs:1,a:3
[4/6]aaab10lf:7,lp:3,rf:2,rp:1
[5/0]bbaab19lf:19,rf:5
[5/1]abbaa18lf:16,lp:2,rf:4,rp:1
[5/2]baaba17lf:10,ls:7,rf:4,rs:3
[5/3]baabb14lf:11,ls:3,rf:2,a:1
[5/4]aabba11lf:11
[5/5]aaabb7lf:4,lp:3,rf:1,rp:1
[5/6]abbbb6lf:3,lp:3,rf:4,rp:4,rs:1,re:1,lprp:3,a:5
[6/0]abbaab17lf:15,lp:2,rf:4,rp:1
[6/1]bbaaba17lf:10,ls:7,rf:4,rs:3
[6/2]bbaabb12lf:9,ls:3,rf:1,a:2
[6/3]aabbaa11lf:11
[6/4]baabba8lf:8,a:1
[6/5]aaabba6lf:3,lp:3
[6/6]baaaba6lf:3,ls:3,rf:1,rs:1,a:12
[7/0]abbaaba17lf:10,ls:7,rf:3,rs:3
[7/1]abbaabb10lf:5,lp:2,ls:3,rf:1,rp:1,a:2
[7/2]aabbaab10lf:10
[7/3]baabbaa8lf:8,a:1
[7/4]bbaabba6lf:6,a:3
[7/5]aaabbaa6lf:3,lp:3
[7/6]abaaaba6lf:3,ls:3,rf:1,rs:1,a:12

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbaaba=ab⟩.