Morphocompletion for #4012 ⟨a, b | aaabbaaab=ba

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aaabbaaab ⇒ ba
2. aaabbba ⇒ babaaab
3. babaaabaabbaaab ⇒ aaabbbba
4. aaabbaaaaaabbbba ⇒ baabaaabaabbaaab
5. babaaabaabbba ⇒ aaabbbbabaaab
6. baabaaabaabbaaabaabbaaab ⇒ aaabbaaaaaabbbbba
7. aaabbaaaaaabbaaaaaabbbbba ⇒ baaabaaabaabbaaabaabbaaab
8. babaaabaabbaaaaaabbbba ⇒ aaabbbbaabaaabaabbaaab
9. baabaaabaabbaaabaabbba ⇒ aaabbaaaaaabbbbbabaaab
10. aaabaaabbaaaaaabbaaaaaabbbbbba ⇒ baaaabaabbaaabaabbaaabaabbaaab
11. baaabaaabaabbaaabaabbaaabaabbaaab ⇒ aaabbaaaaaabbaaaaaabbbbbba
12. aaabbaaaaaabbaaaaaabbaaaaaabbbbbba ⇒ baaaabaaabaabbaaabaabbaaabaabbaaab
13. babaaabaabbaaaaaabbaaaaaabbbbba ⇒ aaabbbbaaabaaabaabbaaabaabbaaab
14. baabaaabaabbaaabaabbaaaaaabbbba ⇒ aaabbaaaaaabbbbbaabaaabaabbaaab
15. baaabaaabaabbaaabaabbaaabaabbba ⇒ aaabbaaaaaabbaaaaaabbbbbbabaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] baa, [3/3] bba, [3/4] abb, [3/5] aba, [3/6] bbb
Length 4:[4/0] aaab, [4/1] baaa, [4/2] aaaa, [4/3] aabb, [4/4] abaa, [4/5] bbaa, [4/6] abba
Length 5:[5/0] baaab, [5/1] aaaaa, [5/2] bbaaa, [5/3] abbaa, [5/4] aabba, [5/5] aaabb, [5/6] aabaa
Length 6:[6/0] abbaaa, [6/1] aabbaa, [6/2] baaaba, [6/3] aaabaa, [6/4] abaabb, [6/5] aabaab, [6/6] bbaaab
Length 7:[7/0] aabbaaa, [7/1] baaabaa, [7/2] aabaabb, [7/3] aaabaab, [7/4] abbaaab, [7/5] aaabbaa, [7/6] baabbaa

Considering [length 5 / frequency 0] baaab=c.

Step 2

Rewriting system is complete. See a, b | aaabbaaab=ba.