Morphocompletion for #4010 ⟨a, b | aaabbaaab=aa⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaaab ⇒ aaabbaa
2. aaaaababb ⇒ aa
3. aaabbaaa ⇒ aaaaabab
4. aabaaaaabab ⇒ aaabbaabaaa
5. aabaaaabbaa ⇒ aaaaababaab
6. aaaaababaaab ⇒ aaaaabaabbaa
7. aaaaababaabab ⇒ aabaaa
8. aaaaabababbaa ⇒ aaaaab
9. aabaaaaaabab ⇒ aaaaababaaba
10. aaaaabaaaababb ⇒ aaaaaba
11. aaaaabaabbaaa ⇒ aaaaabaaaabab
12. aaaaababaaaababb ⇒ aaaaababa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa80lf:64,lp:12,ls:4,rf:51,rp:12,rs:5,re:1,lprp:12,lsrp:4,lprs:5,a:1
[2/1]ab37lf:32,ls:5,rf:21,rs:4,a:1
[2/2]ba24lf:24,rf:17,rs:3,a:1
[2/3]bb10lf:7,ls:3,rf:3,a:1
[3/0]aaa49lf:39,lp:8,ls:2,rf:30,rp:10,rs:2,lprp:6,lsrp:2,lprs:1,a:1
[3/1]aab27lf:21,lp:4,ls:2,rf:16,rp:1,rs:2,lprs:1,a:1
[3/2]aba20lf:20,rf:14,rs:3,a:1
[3/3]baa15lf:13,ls:2,rf:9,rs:2,a:1
[3/4]bab14lf:11,ls:3,rf:5,rs:2,a:3
[3/5]abb10lf:7,ls:3,rf:3,a:1
[3/6]bba4lf:4,rf:3,a:1
[4/0]aaaa29lf:22,lp:7,rf:17,rp:8,lprp:5,a:3
[4/1]aaba20lf:16,lp:4,rf:11,rp:1,rs:2,lprs:1,a:1
[4/2]aaab18lf:15,lp:1,ls:2,rf:11,rp:2,rs:1,lsrp:1,a:1
[4/3]abab14lf:11,ls:3,rf:5,rs:2,a:3
[4/4]baaa11lf:9,ls:2,rf:3,rs:2,a:1
[4/5]abaa9lf:9,rf:6,a:1
[4/6]babb7lf:4,ls:3,a:7
[5/0]aaaaa17lf:10,lp:7,rf:8,rp:8,lprp:5,a:3
[5/1]aabab13lf:10,ls:3,rf:5,rs:2,a:3
[5/2]aaaab12lf:12,rf:9,rs:1,a:3
[5/3]aaaba11lf:11,rf:8,rs:1,a:3
[5/4]aabaa10lf:6,lp:4,rf:4,rp:1,a:1
[5/5]abaaa7lf:7,rf:3,rs:2,a:1
[5/6]ababb7lf:4,ls:3,a:7
[6/0]aaaaab16lf:9,lp:7,rf:8,rp:8,rs:1,re:1,lprp:5,lprs:1,a:3
[6/1]aaaaba11lf:11,rf:8,rs:1,a:3
[6/2]aaabab11lf:9,ls:2,rf:5,rs:2,a:3
[6/3]aabaaa9lf:5,lp:4,rf:3,rp:1,rs:2,re:1,lprs:1,a:1
[6/4]aababb6lf:3,ls:3,a:7
[6/5]abaaaa5lf:5,rf:1,a:3
[6/6]abbaaa4lf:2,ls:2,a:4
[7/0]aaaaaba16lf:9,lp:7,rf:7,rp:7,rs:1,re:1,lprp:4,lprs:1,a:3
[7/1]aaaabab11lf:9,ls:2,rf:5,rs:2,a:3
[7/2]aabaaaa7lf:4,lp:3,rf:1,a:3
[7/3]aaababb6lf:3,ls:3,a:7
[7/4]aabbaaa4lf:2,ls:2,a:4
[7/5]aaabbaa4lf:2,lp:1,ls:1,rf:2,rp:2,rs:1,re:1,a:1
[7/6]aaababa4lf:4,rf:3,rs:1,a:3

Considering [length 3 / frequency 0] aaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbaaab=aa⟩.