Morphocompletion for #4010 ⟨a, b | aaabbaaab=aa

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaaab ⇒ aaabbaa
2. aaaaababb ⇒ aa
3. aaabbaaa ⇒ aaaaabab
4. aabaaaaabab ⇒ aaabbaabaaa
5. aabaaaabbaa ⇒ aaaaababaab
6. aaaaababaaab ⇒ aaaaabaabbaa
7. aaaaababaabab ⇒ aabaaa
8. aaaaabababbaa ⇒ aaaaab
9. aabaaaaaabab ⇒ aaaaababaaba
10. aaaaabaaaababb ⇒ aaaaaba
11. aaaaabaabbaaa ⇒ aaaaabaaaabab
12. aaaaababaaaababb ⇒ aaaaababa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] aba, [3/3] baa, [3/4] bab, [3/5] abb, [3/6] bba
Length 4:[4/0] aaaa, [4/1] aaba, [4/2] aaab, [4/3] abab, [4/4] baaa, [4/5] abaa, [4/6] babb
Length 5:[5/0] aaaaa, [5/1] aabab, [5/2] aaaab, [5/3] aaaba, [5/4] aabaa, [5/5] abaaa, [5/6] ababb
Length 6:[6/0] aaaaab, [6/1] aaaaba, [6/2] aaabab, [6/3] aabaaa, [6/4] aababb, [6/5] abaaaa, [6/6] abbaaa
Length 7:[7/0] aaaaaba, [7/1] aaaabab, [7/2] aabaaaa, [7/3] aaababb, [7/4] aabbaaa, [7/5] aaabbaa, [7/6] aaababa

Considering [length 3 / frequency 0] aaa=c.

Step 2

Rewriting system is complete. See a, b | aaabbaaab=aa.