Morphocompletion for #401 ⟨a, b | ababaab=a⟩

Back:⟨a, b | ababaab=a⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabb ⇒ ababa
2. aabaab ⇒ ababaa
3. ababaab ⇒ a
4. ababaaab ⇒ aaababba
5. aaababbab ⇒ ababababa
6. abaaababb ⇒ aaababbba
7. ababababaa ⇒ aaab
8. ababaaaab ⇒ aabababaa
9. aaababbaab ⇒ aaabababba
10. aaababbbaab ⇒ abababababa
11. aaababbaabb ⇒ aaababbbaba
12. aaababbbabaa ⇒ aaabab
13. ababababababa ⇒ aaababb
14. aaababbaaab ⇒ aabaa
15. aaababbbababaa ⇒ abaaabab
16. aaababbbaaaab ⇒ abaabaa
17. aaabababbaaab ⇒ ababaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] aaa, [3/3] bab, [3/4] baa, [3/5] abb, [3/6] bba
Length 4:[4/0] aaab, [4/1] abab, [4/2] baba, [4/3] aaba, [4/4] abaa, [4/5] babb, [4/6] baab
Length 5:[5/0] aaaba, [5/1] ababa, [5/2] ababb, [5/3] aabab, [5/4] babaa, [5/5] babab, [5/6] baaab
Length 6:[6/0] aaabab, [6/1] ababaa, [6/2] aababb, [6/3] ababab, [6/4] bababa, [6/5] ababba, [6/6] abaaab
Length 7:[7/0] aaababb, [7/1] abababa, [7/2] ababaaa, [7/3] abbaaab, [7/4] aababba, [7/5] ababbaa, [7/6] bababaa

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababaab=a⟩.