| Back: | ⟨a, b | aaababbba=ab⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaababbba ⇒ ab |
| 2. | abababbba ⇒ aaababbbb |
| 3. | abaababbba ⇒ abb |
| 4. | abbababbba ⇒ abaababbbb |
| 5. | abbaababbba ⇒ abbb |
| 6. | abbbababbba ⇒ abbaababbbb |
| 7. | abbbaababbba ⇒ abbbb |
| 8. | aaababbaababbbb ⇒ abbabbba |
| 9. | abbbbababbba ⇒ abbbaababbbb |
| 10. | abbbbaababbba ⇒ abbbbb |
| 11. | abaababbaababbbb ⇒ abbbabbba |
| 12. | abbbbbababbba ⇒ abbbbaababbbb |
| 13. | abbbbbaababbba ⇒ abbbbbb |
| 14. | abbaababbaababbbb ⇒ abbbbabbba |
| 15. | abbbbbbababbba ⇒ abbbbbaababbbb |
| 16. | abbbbbbaababbba ⇒ abbbbbbb |
| 17. | abbbbbbbaababbba ⇒ abbbbbbbb |
| 18. | abbbbbbbbaababbba ⇒ abbbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 89 | lf:86,ls:3,rf:76,rs:14 |
|---|---|---|---|
| [2/1] | ab | 74 | lf:58,lp:16,rf:32,rp:17,rs:1,re:1,lprp:15 |
| [2/2] | ba | 70 | lf:55,ls:15,rf:17,rs:3 |
| [2/3] | aa | 19 | lf:17,lp:2,rf:7,rp:1 |
| [3/0] | bbb | 55 | lf:52,ls:3,rf:52,rs:13 |
| [3/1] | abb | 47 | lf:34,lp:13,rf:24,rp:15,rs:1,re:1,lprp:12 |
| [3/2] | bba | 46 | lf:31,ls:15,rf:10,rs:3 |
| [3/3] | bab | 27 | lf:27,rf:9 |
| [3/4] | aba | 27 | lf:24,lp:3,rf:7,rp:1 |
| [3/5] | aab | 15 | lf:15,rf:6 |
| [3/6] | baa | 13 | lf:13,rf:5,a:1 |
| [4/0] | bbba | 40 | lf:25,ls:15,rf:8,rs:3 |
| [4/1] | abbb | 38 | lf:28,lp:10,rf:21,rp:12,rs:1,re:1,lprp:9 |
| [4/2] | bbbb | 27 | lf:24,ls:3,rf:31,rs:12,a:3 |
| [4/3] | abab | 23 | lf:22,lp:1,rf:6 |
| [4/4] | babb | 21 | lf:21,rf:9 |
| [4/5] | aaba | 15 | lf:15,rf:6 |
| [4/6] | baab | 13 | lf:13,rf:5,a:1 |
| [5/0] | abbba | 34 | lf:17,lp:2,ls:15,rf:5,rp:2,rs:3,lsrp:1 |
| [5/1] | abbbb | 22 | lf:11,lp:8,ls:3,rf:15,rp:9,rs:7,re:1,lprp:7,lsrp:1,lprs:3,a:3 |
| [5/2] | ababb | 21 | lf:21,rf:6 |
| [5/3] | babbb | 18 | lf:18,rf:9 |
| [5/4] | aabab | 15 | lf:15,rf:6 |
| [5/5] | bbbbb | 13 | lf:13,rf:16,rs:5,a:4 |
| [5/6] | baaba | 13 | lf:13,rf:5,a:1 |
| [6/0] | babbba | 30 | lf:15,ls:15,rf:3,rs:3 |
| [6/1] | ababbb | 18 | lf:18,rf:6 |
| [6/2] | aababb | 15 | lf:15,rf:6 |
| [6/3] | baabab | 13 | lf:13,rf:5,a:1 |
| [6/4] | abbbbb | 12 | lf:6,lp:6,rf:6,rp:6,rs:1,re:1,lprp:5,a:4 |
| [6/5] | bbaaba | 11 | lf:11,rf:4,a:2 |
| [6/6] | bbbbbb | 7 | lf:7,rf:10,rs:4,a:5 |
| [7/0] | ababbba | 30 | lf:15,ls:15 |
| [7/1] | baababb | 13 | lf:13,rf:5,a:1 |
| [7/2] | aababbb | 12 | lf:12,rf:6 |
| [7/3] | bbaabab | 11 | lf:11,rf:4,a:2 |
| [7/4] | abbbbbb | 8 | lf:4,lp:4,rf:4,rp:4,rs:1,re:1,lprp:3,a:5 |
| [7/5] | abbaaba | 7 | lf:5,lp:2,rf:1,rp:1,a:2 |
| [7/6] | bababbb | 6 | lf:6,a:6 |
Considering [length 4 / frequency 0] bbba=c.
Rewriting system is complete. See ⟨a, b | aaababbba=ab⟩.