| Back: | ⟨a, b | aaababbba=ab⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaababbba ⇒ ab |
| 2. | abababbba ⇒ aaababbbb |
| 3. | abaababbba ⇒ abb |
| 4. | abbababbba ⇒ abaababbbb |
| 5. | abbaababbba ⇒ abbb |
| 6. | abbbababbba ⇒ abbaababbbb |
| 7. | abbbaababbba ⇒ abbbb |
| 8. | aaababbaababbbb ⇒ abbabbba |
| 9. | abbbbababbba ⇒ abbbaababbbb |
| 10. | abbbbaababbba ⇒ abbbbb |
| 11. | abaababbaababbbb ⇒ abbbabbba |
| 12. | abbbbbababbba ⇒ abbbbaababbbb |
| 13. | abbbbbaababbba ⇒ abbbbbb |
| 14. | abbaababbaababbbb ⇒ abbbbabbba |
| 15. | abbbbbbababbba ⇒ abbbbbaababbbb |
| 16. | abbbbbbaababbba ⇒ abbbbbbb |
| 17. | abbbbbbbaababbba ⇒ abbbbbbbb |
| 18. | abbbbbbbbaababbba ⇒ abbbbbbbbb |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] bbb, [3/1] abb, [3/2] bba, [3/3] bab, [3/4] aba, [3/5] aab, [3/6] baa |
| Length 4: | [4/0] bbba, [4/1] abbb, [4/2] bbbb, [4/3] abab, [4/4] babb, [4/5] aaba, [4/6] baab |
| Length 5: | [5/0] abbba, [5/1] abbbb, [5/2] ababb, [5/3] babbb, [5/4] aabab, [5/5] bbbbb, [5/6] baaba |
| Length 6: | [6/0] babbba, [6/1] ababbb, [6/2] aababb, [6/3] baabab, [6/4] abbbbb, [6/5] bbaaba, [6/6] bbbbbb |
| Length 7: | [7/0] ababbba, [7/1] baababb, [7/2] aababbb, [7/3] bbaabab, [7/4] abbbbbb, [7/5] abbaaba, [7/6] bababbb |
Considering [length 4 / frequency 0] bbba=c.
Rewriting system is complete. See ⟨a, b | aaababbba=ab⟩.