| Back: | ⟨a, b | aaababbaa=ba⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaababbaa ⇒ ba |
| 2. | aaababbaba ⇒ bba |
| 3. | baababbaa ⇒ aaababbba |
| 4. | aaababbabba ⇒ bbba |
| 5. | baababbaba ⇒ aaababbbba |
| 6. | aaababbabbba ⇒ bbbba |
| 7. | aaababaaababbba ⇒ bababbaa |
| 8. | baababbabba ⇒ aaababbbbba |
| 9. | aaababbabbbba ⇒ bbbbba |
| 10. | aaababaaababbbba ⇒ bababbaba |
| 11. | baababbabbba ⇒ aaababbbbbba |
| 12. | aaababbabbbbba ⇒ bbbbbba |
| 13. | aaababaaababbbbba ⇒ bababbabba |
| 14. | baababbabbbba ⇒ aaababbbbbbba |
| 15. | aaababbabbbbbba ⇒ bbbbbbba |
| 16. | aaababbabbbbbbba ⇒ bbbbbbbba |
| 17. | aaababbabbbbbbbba ⇒ bbbbbbbbba |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ba | 77 | lf:57,lp:5,ls:15,rf:30,rp:4,rs:16,re:1,lsrp:3,lprs:5,lsrs:14 |
|---|---|---|---|
| [2/1] | bb | 57 | lf:57,rf:60,rp:8 |
| [2/2] | ab | 52 | lf:52,rf:18 |
| [2/3] | aa | 51 | lf:37,lp:12,ls:2,rf:11,rp:5,rs:1,lsrp:1,lprs:1 |
| [3/0] | bba | 40 | lf:27,ls:13,rf:17,rp:1,rs:14,re:1,lsrs:11 |
| [3/1] | bab | 32 | lf:32,rf:13,rp:3 |
| [3/2] | bbb | 30 | lf:30,rf:43,rp:7,a:1 |
| [3/3] | abb | 27 | lf:27,rf:9 |
| [3/4] | aba | 27 | lf:25,ls:2,rf:9,rs:1 |
| [3/5] | aaa | 27 | lf:15,lp:12,rf:5,rp:5 |
| [3/6] | aab | 20 | lf:20,rf:5 |
| [4/0] | babb | 27 | lf:27,rf:9 |
| [4/1] | aaab | 27 | lf:15,lp:12,rf:5,rp:5 |
| [4/2] | bbba | 22 | lf:11,ls:11,rf:12,rp:1,rs:12,re:1,lsrs:8,a:1 |
| [4/3] | abab | 20 | lf:20,rf:8 |
| [4/4] | aaba | 20 | lf:20,rf:5 |
| [4/5] | bbbb | 19 | lf:19,rf:31,rp:6,a:3 |
| [4/6] | abba | 18 | lf:16,ls:2,rf:4,rs:1 |
| [5/0] | aaaba | 27 | lf:15,lp:12,rf:5,rp:5 |
| [5/1] | aabab | 20 | lf:20,rf:5 |
| [5/2] | babba | 18 | lf:16,ls:2,rf:4,rs:1 |
| [5/3] | ababb | 17 | lf:17,rf:8 |
| [5/4] | bbbba | 16 | lf:8,ls:8,rf:10,rp:1,rs:10,re:1,lsrs:6,a:3 |
| [5/5] | abbab | 12 | lf:12,rf:2,a:2 |
| [5/6] | bbbbb | 11 | lf:11,rf:21,rp:5,a:6 |
| [6/0] | aaabab | 27 | lf:15,lp:12,rf:5,rp:5 |
| [6/1] | aababb | 17 | lf:17,rf:5 |
| [6/2] | ababba | 14 | lf:14,rf:3 |
| [6/3] | babbab | 12 | lf:12,rf:2,a:2 |
| [6/4] | bbbbba | 10 | lf:5,ls:5,rf:8,rp:1,rs:8,re:1,lsrs:4,a:6 |
| [6/5] | abbabb | 10 | lf:10,rf:1,a:4 |
| [6/6] | baabab | 10 | lf:5,lp:5,a:1 |
| [7/0] | aaababb | 21 | lf:12,lp:9,rf:5,rp:5 |
| [7/1] | aababba | 14 | lf:14 |
| [7/2] | ababbab | 12 | lf:12,rf:2,a:2 |
| [7/3] | babbabb | 10 | lf:10,rf:1,a:4 |
| [7/4] | baababb | 10 | lf:5,lp:5,a:1 |
| [7/5] | abbabbb | 8 | lf:8,a:5 |
| [7/6] | bbbbbba | 6 | lf:3,ls:3,rf:6,rp:1,rs:6,re:1,lsrs:3,a:8 |
Considering [length 3 / frequency 0] bba=c.
Rewriting system is complete. See ⟨a, b | aaababbaa=ba⟩.