Morphocompletion for #3999 ⟨a, b | aaababbaa=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	aaababbaa ⇒ ab
2.	abaababbaa ⇒ abb
3.	aaababbb ⇒ abbabbaa
4.	aaababbab ⇒ abababbaa
5.	abbaababbaa ⇒ abbb
6.	abaababbb ⇒ abbbabbaa
7.	abaababbab ⇒ abbababbaa
8.	abbbaababbaa ⇒ abbbb
9.	abbaababbb ⇒ abbbbabbaa
10.	abbaababbab ⇒ abbbababbaa
11.	abbbbaababbaa ⇒ abbbbb
12.	abbbaababbb ⇒ abbbbbabbaa
13.	abbbaababbab ⇒ abbbbababbaa
14.	abbbbbaababbaa ⇒ abbbbbb
15.	abbbbaababbb ⇒ abbbbbbabbaa
16.	abbbbaababbab ⇒ abbbbbababbaa
17.	abbbbbbaababbaa ⇒ abbbbbbb
18.	abbbbbaababbb ⇒ abbbbbbbabbaa
19.	abbbbbbbaababbaa ⇒ abbbbbbbb
20.	abbbbbbbbaababbaa ⇒ abbbbbbbbb
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa
Length 3:	[3/0] abb, [3/1] bbb, [3/2] baa, [3/3] bab, [3/4] bba, [3/5] aba, [3/6] aab
Length 4:	[4/0] abbb, [4/1] bbaa, [4/2] babb, [4/3] abab, [4/4] abba, [4/5] aaba, [4/6] bbbb
Length 5:	[5/0] abbaa, [5/1] ababb, [5/2] aabab, [5/3] baaba, [5/4] abbbb, [5/5] babba, [5/6] bbaab
Length 6:	[6/0] aababb, [6/1] babbaa, [6/2] baabab, [6/3] ababba, [6/4] bbaaba, [6/5] ababbb, [6/6] bbbaab
Length 7:	[7/0] ababbaa, [7/1] baababb, [7/2] bbaabab, [7/3] aababba, [7/4] aababbb, [7/5] bbbaaba, [7/6] ababbab

Considering [length 3 / frequency 0] abb=c.

Reduction order:
- Left-to-right recursive path with deg(a) = 0; deg(c) = 1; deg(b) = 2
Auxiliary generators:
1. abb=c

Rewriting system is complete. See ⟨a, b | aaababbaa=ab⟩.