| Back: | ⟨a, b | aaababbaa=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | aaababbaa ⇒ ab |
| 2. | abaababbaa ⇒ abb |
| 3. | aaababbb ⇒ abbabbaa |
| 4. | aaababbab ⇒ abababbaa |
| 5. | abbaababbaa ⇒ abbb |
| 6. | abaababbb ⇒ abbbabbaa |
| 7. | abaababbab ⇒ abbababbaa |
| 8. | abbbaababbaa ⇒ abbbb |
| 9. | abbaababbb ⇒ abbbbabbaa |
| 10. | abbaababbab ⇒ abbbababbaa |
| 11. | abbbbaababbaa ⇒ abbbbb |
| 12. | abbbaababbb ⇒ abbbbbabbaa |
| 13. | abbbaababbab ⇒ abbbbababbaa |
| 14. | abbbbbaababbaa ⇒ abbbbbb |
| 15. | abbbbaababbb ⇒ abbbbbbabbaa |
| 16. | abbbbaababbab ⇒ abbbbbababbaa |
| 17. | abbbbbbaababbaa ⇒ abbbbbbb |
| 18. | abbbbbaababbb ⇒ abbbbbbbabbaa |
| 19. | abbbbbbbaababbaa ⇒ abbbbbbbb |
| 20. | abbbbbbbbaababbaa ⇒ abbbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 84 | lf:62,lp:17,ls:5,rf:36,rp:20,rs:1,re:1,lprp:17,lsrp:5 |
|---|---|---|---|
| [2/1] | bb | 76 | lf:70,ls:6,rf:78,rs:8 |
| [2/2] | ba | 51 | lf:51,rf:27 |
| [2/3] | aa | 44 | lf:32,lp:3,ls:9,rf:11,rs:11,lprs:2 |
| [3/0] | abb | 48 | lf:34,lp:14,rf:29,rp:18,rs:1,re:1,lprp:14 |
| [3/1] | bbb | 42 | lf:36,ls:6,rf:49,rs:7,a:3 |
| [3/2] | baa | 35 | lf:26,ls:9,rf:11,rs:11 |
| [3/3] | bab | 30 | lf:25,ls:5,rf:16 |
| [3/4] | bba | 28 | lf:28,rf:21 |
| [3/5] | aba | 26 | lf:23,lp:3,rf:6,rp:1 |
| [3/6] | aab | 20 | lf:20 |
| [4/0] | abbb | 34 | lf:17,lp:11,ls:6,rf:15,rp:15,rs:1,re:1,lprp:11,lsrp:5,a:3 |
| [4/1] | bbaa | 32 | lf:23,ls:9,rf:11,rs:11 |
| [4/2] | babb | 20 | lf:20,rf:11 |
| [4/3] | abab | 20 | lf:20,rf:6,rp:1 |
| [4/4] | abba | 20 | lf:17,lp:3,rf:13,rp:2 |
| [4/5] | aaba | 20 | lf:20 |
| [4/6] | bbbb | 19 | lf:19,rf:34,rs:6,a:5 |
| [5/0] | abbaa | 24 | lf:12,lp:3,ls:9,rf:11,rs:11,lprs:2 |
| [5/1] | ababb | 20 | lf:20,rf:5 |
| [5/2] | aabab | 20 | lf:20 |
| [5/3] | baaba | 17 | lf:17,a:2 |
| [5/4] | abbbb | 16 | lf:8,lp:8,rf:12,rp:12,rs:1,re:1,lprp:8,a:5 |
| [5/5] | babba | 14 | lf:14,rf:11 |
| [5/6] | bbaab | 14 | lf:14,a:3 |
| [6/0] | aababb | 20 | lf:20 |
| [6/1] | babbaa | 18 | lf:9,ls:9,rf:11,rs:11 |
| [6/2] | baabab | 17 | lf:17,a:2 |
| [6/3] | ababba | 14 | lf:14,rf:5 |
| [6/4] | bbaaba | 14 | lf:14,a:3 |
| [6/5] | ababbb | 12 | lf:6,ls:6,a:6 |
| [6/6] | bbbaab | 11 | lf:11,a:5 |
| [7/0] | ababbaa | 18 | lf:9,ls:9,rf:5,rs:5 |
| [7/1] | baababb | 17 | lf:17,a:2 |
| [7/2] | bbaabab | 14 | lf:14,a:3 |
| [7/3] | aababba | 14 | lf:14 |
| [7/4] | aababbb | 12 | lf:6,ls:6,a:6 |
| [7/5] | bbbaaba | 11 | lf:11,a:5 |
| [7/6] | ababbab | 10 | lf:5,ls:5,a:1 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aaababbaa=ab⟩.