Morphocompletion for #3977 ⟨a, b | aaabaabba=ba⟩

Back:⟨a, b | aaabaabba=ba⟩

Solved by morph:4/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aaabaabba ⇒ ba
2. aaabaabbba ⇒ bba
3. aaabaabbbba ⇒ bbba
4. aaabaabbbbba ⇒ bbbba
5. aaabaabbbbbba ⇒ bbbbba
6. aaabaabbbbbbba ⇒ bbbbbba
7. aaabaabbbbbbbba ⇒ bbbbbbba
8. aaabaabbbbbbbbba ⇒ bbbbbbbba
9. aaabaabbbbbbbbbba ⇒ bbbbbbbbba
10. aaabaabbbbbbbbbbba ⇒ bbbbbbbbbba
11. aaabaabbbbbbbbbbbba ⇒ bbbbbbbbbbba
12. aaabaabbbbbbbbbbbbba ⇒ bbbbbbbbbbbba
13. aaabaabbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbba
14. aaabaabbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbba
15. aaabaabbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbba
16. aaabaabbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbba
17. aaabaabbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbba
18. aaabaabbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbba
19. aaabaabbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbba
20. aaabaabbbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb210lf:210,rf:190,rp:19
[2/1]aa80lf:60,lp:20
[2/2]ba60lf:40,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20
[2/3]ab40lf:40
[3/0]bbb190lf:190,rf:171,rp:18,a:1
[3/1]bba40lf:20,ls:20,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19
[3/2]aab40lf:40
[3/3]aaa40lf:20,lp:20
[3/4]abb20lf:20
[3/5]aba20lf:20
[3/6]baa20lf:20
[4/0]bbbb171lf:171,rf:153,rp:17,a:2
[4/1]aaab40lf:20,lp:20
[4/2]bbba38lf:19,ls:19,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18,a:1
[4/3]aabb20lf:20
[4/4]baab20lf:20
[4/5]aaba20lf:20
[4/6]abaa20lf:20
[5/0]bbbbb153lf:153,rf:136,rp:16,a:3
[5/1]aaaba40lf:20,lp:20
[5/2]bbbba36lf:18,ls:18,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17,a:2
[5/3]baabb20lf:20
[5/4]abaab20lf:20
[5/5]aabaa20lf:20
[5/6]aabbb19lf:19,a:1
[6/0]bbbbbb136lf:136,rf:120,rp:15,a:4
[6/1]aaabaa40lf:20,lp:20
[6/2]bbbbba34lf:17,ls:17,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:3
[6/3]abaabb20lf:20
[6/4]aabaab20lf:20
[6/5]baabbb19lf:19,a:1
[6/6]aabbbb18lf:18,a:2
[7/0]bbbbbbb120lf:120,rf:105,rp:14,a:5
[7/1]aaabaab40lf:20,lp:20
[7/2]bbbbbba32lf:16,ls:16,rf:15,rp:1,rs:15,re:1,lsrp:1,lsrs:15,a:4
[7/3]aabaabb20lf:20
[7/4]abaabbb19lf:19,a:1
[7/5]baabbbb18lf:18,a:2
[7/6]aabbbbb17lf:17,a:3

Considering [length 4 / frequency 2] bbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabaabba=ba⟩.