Morphocompletion for #3976 ⟨a, b | aaabaabba=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabaabba ⇒ ab
2. ababaabba ⇒ aaabaabbb
3. abaabaabba ⇒ abb
4. abbabaabba ⇒ abaabaabbb
5. abbaabaabba ⇒ abbb
6. aaabaabaabaabbb ⇒ abbaabba
7. abbbabaabba ⇒ abbaabaabbb
8. abbbaabaabba ⇒ abbbb
9. abaabaabaabaabbb ⇒ abbbaabba
10. abbbbabaabba ⇒ abbbaabaabbb
11. abbbbaabaabba ⇒ abbbbb
12. abbaabaabaabaabbb ⇒ abbbbaabba
13. abbbbbabaabba ⇒ abbbbaabaabbb
14. abbbbbaabaabba ⇒ abbbbbb
15. abbbbbbaabaabba ⇒ abbbbbbb
16. abbbbbbbaabaabba ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] abb, [3/1] bba, [3/2] aab, [3/3] baa, [3/4] aba, [3/5] bbb, [3/6] bab
Length 4:[4/0] abba, [4/1] baab, [4/2] abaa, [4/3] abbb, [4/4] aaba, [4/5] aabb, [4/6] bbbb
Length 5:[5/0] aabba, [5/1] abaab, [5/2] aabaa, [5/3] baabb, [5/4] baaba, [5/5] abbbb, [5/6] bbbbb
Length 6:[6/0] baabba, [6/1] aabaab, [6/2] abaabb, [6/3] baabaa, [6/4] abaaba, [6/5] abbbbb, [6/6] bbaaba
Length 7:[7/0] abaabba, [7/1] baabaab, [7/2] aabaabb, [7/3] abaabaa, [7/4] bbaabaa, [7/5] abaabbb, [7/6] aabaaba

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aaabaabba=ab.