| Back: | ⟨a, b | aaabaabba=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaabaabba ⇒ ab |
| 2. | ababaabba ⇒ aaabaabbb |
| 3. | abaabaabba ⇒ abb |
| 4. | abbabaabba ⇒ abaabaabbb |
| 5. | abbaabaabba ⇒ abbb |
| 6. | aaabaabaabaabbb ⇒ abbaabba |
| 7. | abbbabaabba ⇒ abbaabaabbb |
| 8. | abbbaabaabba ⇒ abbbb |
| 9. | abaabaabaabaabbb ⇒ abbbaabba |
| 10. | abbbbabaabba ⇒ abbbaabaabbb |
| 11. | abbbbaabaabba ⇒ abbbbb |
| 12. | abbaabaabaabaabbb ⇒ abbbbaabba |
| 13. | abbbbbabaabba ⇒ abbbbaabaabbb |
| 14. | abbbbbaabaabba ⇒ abbbbbb |
| 15. | abbbbbbaabaabba ⇒ abbbbbbb |
| 16. | abbbbbbbaabaabba ⇒ abbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 66 | lf:52,lp:14,rf:28,rp:15,rs:1,re:1,lprp:13 |
|---|---|---|---|
| [2/1] | ba | 62 | lf:49,ls:13,rf:15,rs:3 |
| [2/2] | bb | 54 | lf:51,ls:3,rf:53,rs:12 |
| [2/3] | aa | 37 | lf:35,lp:2,rf:14,rp:1 |
| [3/0] | abb | 38 | lf:27,lp:11,rf:21,rp:13,rs:1,re:1,lprp:10 |
| [3/1] | bba | 37 | lf:24,ls:13,rf:9,rs:3 |
| [3/2] | aab | 33 | lf:33,rf:13 |
| [3/3] | baa | 31 | lf:31,rf:12 |
| [3/4] | aba | 28 | lf:25,lp:3,rf:6,rp:1 |
| [3/5] | bbb | 27 | lf:24,ls:3,rf:32,rs:11,a:2 |
| [3/6] | bab | 5 | lf:5,a:4 |
| [4/0] | abba | 32 | lf:16,lp:3,ls:13,rf:5,rp:2,rs:3,lsrp:1,lprs:1 |
| [4/1] | baab | 31 | lf:31,rf:12 |
| [4/2] | abaa | 26 | lf:24,lp:2,rf:6,rp:1 |
| [4/3] | abbb | 22 | lf:11,lp:8,ls:3,rf:15,rp:10,rs:6,re:1,lprp:7,lsrp:2,lprs:3,a:2 |
| [4/4] | aaba | 17 | lf:17,rf:5 |
| [4/5] | aabb | 16 | lf:16,rf:8 |
| [4/6] | bbbb | 13 | lf:13,rf:17,rs:5,a:3 |
| [5/0] | aabba | 26 | lf:13,ls:13,rf:3,rs:3 |
| [5/1] | abaab | 26 | lf:24,lp:2,rf:6,rp:1 |
| [5/2] | aabaa | 17 | lf:17,rf:5 |
| [5/3] | baabb | 16 | lf:16,rf:8 |
| [5/4] | baaba | 15 | lf:15,rf:4,a:1 |
| [5/5] | abbbb | 12 | lf:6,lp:6,rf:7,rp:7,rs:1,re:1,lprp:5,a:3 |
| [5/6] | bbbbb | 7 | lf:7,rf:10,rs:4,a:6 |
| [6/0] | baabba | 26 | lf:13,ls:13,rf:3,rs:3 |
| [6/1] | aabaab | 17 | lf:17,rf:5 |
| [6/2] | abaabb | 16 | lf:16,rf:5 |
| [6/3] | baabaa | 15 | lf:15,rf:4,a:1 |
| [6/4] | abaaba | 10 | lf:8,lp:2,rf:1,rp:1,a:1 |
| [6/5] | abbbbb | 8 | lf:4,lp:4,rf:4,rp:4,rs:1,re:1,lprp:3,a:6 |
| [6/6] | bbaaba | 7 | lf:7,rf:3,a:2 |
| [7/0] | abaabba | 26 | lf:13,ls:13 |
| [7/1] | baabaab | 15 | lf:15,rf:4,a:1 |
| [7/2] | aabaabb | 11 | lf:11,rf:5 |
| [7/3] | abaabaa | 10 | lf:8,lp:2,rf:1,rp:1,a:1 |
| [7/4] | bbaabaa | 7 | lf:7,rf:3,a:2 |
| [7/5] | abaabbb | 6 | lf:3,ls:3,rf:5,rs:5,a:4 |
| [7/6] | aabaaba | 6 | lf:6,a:16 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aaabaabba=ab⟩.