Morphocompletion for #3957 ⟨a, b | aaabaaaab=ba⟩

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#	Rule
1.	aaabaaaab ⇒ ba
2.	aaababa ⇒ baaaaab
3.	baaaaabaabaaaab ⇒ aaababba
4.	aaabaaaaaaababba ⇒ baaaaaabaabaaaab
5.	baaaaabaababa ⇒ aaababbaaaaab
6.	baaaaaabaabaaaabaabaaaab ⇒ aaabaaaaaaababbba
7.	aaabaaaaaaabaaaaaaababbba ⇒ baaaaaaabaabaaaabaabaaaab
8.	baaaaabaabaaaaaaababba ⇒ aaababbaaaaaabaabaaaab
9.	baaaaaabaabaaaabaababa ⇒ aaabaaaaaaababbbaaaaab
10.	baaaaaaabaabaaaabaabaaaabaabaaaab ⇒ aaabaaaaaaabaaaaaaababbbba
11.	aaabaaaaaaabaaaaaaabaaaaaaababbbba ⇒ baaaaaaaabaabaaaabaabaaaabaabaaaab
12.	baaaaabaabaaaaaaabaaaaaaababbba ⇒ aaababbaaaaaaabaabaaaabaabaaaab
13.	baaaaaabaabaaaabaabaaaaaaababba ⇒ aaabaaaaaaababbbaaaaaabaabaaaab
14.	baaaaaaabaabaaaabaabaaaabaababa ⇒ aaabaaaaaaabaaaaaaababbbbaaaaab
15.	baaaaaaaabaabaaaabaabaaaabaabaaaabaabaaaab ⇒ aaabaaaaaaabaaaaaaabaaaaaaababbbbba
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:	[3/0] aaa, [3/1] baa, [3/2] aab, [3/3] aba, [3/4] bba, [3/5] bab, [3/6] abb
Length 4:	[4/0] aaaa, [4/1] aaba, [4/2] aaab, [4/3] baaa, [4/4] abaa, [4/5] baab, [4/6] abab
Length 5:	[5/0] aaaaa, [5/1] baaaa, [5/2] aabaa, [5/3] aaaba, [5/4] aaaab, [5/5] abaaa, [5/6] baaba
Length 6:	[6/0] aaabaa, [6/1] baaaaa, [6/2] aaaaba, [6/3] aaaaaa, [6/4] abaaaa, [6/5] aabaaa, [6/6] abaaba
Length 7:	[7/0] aabaaaa, [7/1] aaaabaa, [7/2] baaaaaa, [7/3] aabaaba, [7/4] abaaaab, [7/5] aaabaab, [7/6] aaaaaba

Considering [length 3 / frequency 1] baa=c.

Reduction order:
- Right-to-left recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1
Auxiliary generators:
1. baa=c

Rewriting system is complete. See ⟨a, b | aaabaaaab=ba⟩.