Morphocompletion for #3952 ⟨a, b | aaaabbbba=ab⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbbba ⇒ ab
2. abaabbbba ⇒ aaaabbbbb
3. abaaabbbba ⇒ abb
4. abbaabbbba ⇒ abaaabbbbb
5. abbaaabbbba ⇒ abbb
6. abbbaabbbba ⇒ abbaaabbbbb
7. abbbaaabbbba ⇒ abbbb
8. aaaabbbaaabbbbb ⇒ ababbbba
9. abbbbaabbbba ⇒ abbbaaabbbbb
10. abbbbaaabbbba ⇒ abbbbb
11. abaaabbbaaabbbbb ⇒ abbabbbba
12. abbbbbaabbbba ⇒ abbbbaaabbbbb
13. abbbbbaaabbbba ⇒ abbbbbb
14. abbaaabbbaaabbbbb ⇒ abbbabbbba
15. abbbbbbaabbbba ⇒ abbbbbaaabbbbb
16. abbbbbbaaabbbba ⇒ abbbbbbb
17. abbbbbbbaaabbbba ⇒ abbbbbbbb
18. abbbbbbbbaaabbbba ⇒ abbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb110lf:107,ls:3,rf:82,rs:14
[2/1]ab53lf:37,lp:16,rf:26,rp:17,rs:1,re:1,lprp:15
[2/2]ba49lf:34,ls:15,rf:11,rs:3
[2/3]aa40lf:38,lp:2,rf:13,rp:1
[3/0]bbb76lf:73,ls:3,rf:59,rs:13
[3/1]abb47lf:34,lp:13,rf:23,rp:14,rs:1,re:1,lprp:12
[3/2]bba46lf:31,ls:15,rf:9,rs:3
[3/3]aab21lf:21,rf:6
[3/4]baa19lf:19,rf:5,a:1
[3/5]aaa19lf:17,lp:2,rf:7,rp:1
[3/6]aba6lf:3,lp:3,rf:2,rp:2,a:1
[4/0]bbbb45lf:42,ls:3,rf:39,rs:12
[4/1]bbba43lf:28,ls:15,rf:7,rs:3
[4/2]abbb41lf:31,lp:10,rf:20,rp:11,rs:1,re:1,lprp:9
[4/3]aabb21lf:21,rf:6
[4/4]bbaa16lf:16,rf:4,a:2
[4/5]aaab15lf:15,rf:6
[4/6]baaa13lf:13,rf:5,a:1
[5/0]bbbba38lf:23,ls:15,rf:5,rs:3
[5/1]abbbb34lf:26,lp:8,rf:17,rp:8,rs:1,re:1,lprp:7
[5/2]aabbb21lf:21,rf:6
[5/3]bbbbb19lf:16,ls:3,rf:22,rs:11,a:4
[5/4]aaabb15lf:15,rf:6
[5/5]bbbaa13lf:13,rf:3,a:3
[5/6]baaab13lf:13,rf:5,a:1
[6/0]abbbba34lf:17,lp:2,ls:15,rf:4,rp:1,rs:3,lsrp:1
[6/1]abbbbb18lf:9,lp:6,ls:3,rf:12,rp:6,rs:7,re:1,lprp:5,lprs:2,a:4
[6/2]aabbbb18lf:18,rf:6
[6/3]aaabbb15lf:15,rf:6
[6/4]baaabb13lf:13,rf:5,a:1
[6/5]bbaaab11lf:11,rf:4,a:2
[6/6]bbbaaa9lf:9,rf:3,a:3
[7/0]aabbbba30lf:15,ls:15
[7/1]baaabbb13lf:13,rf:5,a:1
[7/2]aaabbbb12lf:12,rf:6
[7/3]bbaaabb11lf:11,rf:4,a:2
[7/4]bbbaaab9lf:9,rf:3,a:3
[7/5]abbbbbb8lf:4,lp:4,rf:4,rp:4,rs:1,re:1,lprp:3,a:5
[7/6]bbbbbaa6lf:6,rf:1,a:5

Considering [length 5 / frequency 0] bbbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaabbbba=ab⟩.