Morphocompletion for #3944 ⟨a, b | aaaabbbaa=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaabbbaa ⇒ ab
2. abaaabbbaa ⇒ abb
3. aaaabbbb ⇒ ababbbaa
4. aaaabbbab ⇒ abaabbbaa
5. abbaaabbbaa ⇒ abbb
6. abaaabbbb ⇒ abbabbbaa
7. abaaabbbab ⇒ abbaabbbaa
8. abbbaaabbbaa ⇒ abbbb
9. abbaaabbbb ⇒ abbbabbbaa
10. abbaaabbbab ⇒ abbbaabbbaa
11. abbbbaaabbbaa ⇒ abbbbb
12. abbbaaabbbb ⇒ abbbbabbbaa
13. abbbaaabbbab ⇒ abbbbaabbbaa
14. abbbbbaaabbbaa ⇒ abbbbbb
15. abbbbaaabbbb ⇒ abbbbbabbbaa
16. abbbbaaabbbab ⇒ abbbbbaabbbaa
17. abbbbbbaaabbbaa ⇒ abbbbbbb
18. abbbbbaaabbbb ⇒ abbbbbbabbbaa
19. abbbbbbbaaabbbaa ⇒ abbbbbbbb
20. abbbbbbbbaaabbbaa ⇒ abbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb96lf:90,ls:6,rf:83,rs:8
[2/1]ab64lf:42,lp:17,ls:5,rf:31,rp:20,rs:1,re:1,lprp:17,lsrp:5
[2/2]aa64lf:52,lp:3,ls:9,rf:16,rs:11,lprs:2
[2/3]ba31lf:31,rf:22
[3/0]bbb62lf:56,ls:6,rf:55,rs:7
[3/1]abb48lf:34,lp:14,rf:28,rp:17,rs:1,re:1,lprp:14
[3/2]baa35lf:26,ls:9,rf:16,rs:11
[3/3]bba28lf:28,rf:20
[3/4]aaa26lf:23,lp:3
[3/5]aab20lf:20,rf:5
[3/6]bab10lf:5,ls:5,rf:6,a:1
[4/0]abbb42lf:31,lp:11,rf:25,rp:14,rs:1,re:1,lprp:11
[4/1]bbaa32lf:23,ls:9,rf:15,rs:11
[4/2]bbbb31lf:25,ls:6,rf:30,rs:6,a:5
[4/3]bbba25lf:25,rf:18
[4/4]aabb20lf:20,rf:5
[4/5]aaab20lf:20
[4/6]baaa17lf:17,a:2
[5/0]bbbaa29lf:20,ls:9,rf:14,rs:11
[5/1]abbbb28lf:14,lp:8,ls:6,rf:11,rp:11,rs:1,re:1,lprp:8,lsrp:3,a:5
[5/2]aabbb20lf:20,rf:5
[5/3]abbba20lf:17,lp:3,rf:13,rp:2
[5/4]aaabb20lf:20
[5/5]baaab17lf:17,a:2
[5/6]bbaaa14lf:14,a:3
[6/0]abbbaa24lf:12,lp:3,ls:9,rf:12,rp:1,rs:11,lprs:2
[6/1]aaabbb20lf:20
[6/2]baaabb17lf:17,a:2
[6/3]aabbba14lf:14,rf:5
[6/4]bbaaab14lf:14,a:3
[6/5]aabbbb12lf:6,ls:6,a:9
[6/6]bbbaaa11lf:11,a:5
[7/0]aabbbaa18lf:9,ls:9,rf:5,rs:5
[7/1]baaabbb17lf:17,a:2
[7/2]bbaaabb14lf:14,a:3
[7/3]aaabbba14lf:14
[7/4]aaabbbb12lf:6,ls:6,a:9
[7/5]bbbaaab11lf:11,a:5
[7/6]aabbbab10lf:5,ls:5,a:1

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaabbbaa=ab⟩.