Morphocompletion for #3929 ⟨a, b | aaaabbaaa=ba⟩

Back:⟨a, b | aaaabbaaa=ba⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbaaa ⇒ ba
2. aaaabbaaba ⇒ bba
3. baabbaaa ⇒ aaaabbba
4. baaabbaaa ⇒ aaaabbaba
5. aaaabaaaabbba ⇒ bbbaaa
6. aaaabbaabba ⇒ bbba
7. aaaabaaaabbaba ⇒ babbaaa
8. baabbaaba ⇒ aaaabbbba
9. baaabbaaba ⇒ aaaabbabba
10. aaaabbaabbba ⇒ bbbba
11. baabbaabba ⇒ aaaabbbbba
12. aaaabbaabbbba ⇒ bbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aaa, [3/1] baa, [3/2] bba, [3/3] aab, [3/4] abb, [3/5] aba, [3/6] bbb
Length 4:[4/0] aabb, [4/1] aaaa, [4/2] abba, [4/3] baab, [4/4] baaa, [4/5] aaab, [4/6] bbaa
Length 5:[5/0] aaaab, [5/1] aabba, [5/2] baabb, [5/3] abbaa, [5/4] aaabb, [5/5] bbaab, [5/6] bbaaa
Length 6:[6/0] aaaabb, [6/1] baabba, [6/2] aabbaa, [6/3] aaabba, [6/4] abbaab, [6/5] bbaaba, [6/6] abbaaa
Length 7:[7/0] aaaabba, [7/1] aabbaab, [7/2] aaabbaa, [7/3] baabbaa, [7/4] abbaaba, [7/5] aabbaaa, [7/6] bbaabba

Considering [length 4 / frequency 0] aabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaabbaaa=ba⟩.