Morphocompletion for #3929 ⟨a, b | aaaabbaaa=ba⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbaaa ⇒ ba
2. aaaabbaaba ⇒ bba
3. baabbaaa ⇒ aaaabbba
4. baaabbaaa ⇒ aaaabbaba
5. aaaabaaaabbba ⇒ bbbaaa
6. aaaabbaabba ⇒ bbba
7. aaaabaaaabbaba ⇒ babbaaa
8. baabbaaba ⇒ aaaabbbba
9. baaabbaaba ⇒ aaaabbabba
10. aaaabbaabbba ⇒ bbbba
11. baabbaabba ⇒ aaaabbbbba
12. aaaabbaabbbba ⇒ bbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa57lf:47,lp:7,ls:3,rf:19,rp:5,rs:2,lsrp:2,lprs:2
[2/1]ba41lf:27,lp:5,ls:9,rf:15,rp:2,rs:10,re:1,lsrp:1,lprs:5,lsrs:7
[2/2]ab22lf:22,rf:8
[2/3]bb20lf:20,rf:25,rp:5
[3/0]aaa33lf:23,lp:7,ls:3,rf:12,rp:5,rs:2,lsrp:2,lprs:2
[3/1]baa22lf:17,lp:5,rf:2
[3/2]bba21lf:16,ls:5,rf:12,rp:1,rs:8,re:1,lsrs:4
[3/3]aab21lf:21,rf:5
[3/4]abb16lf:16,rf:7
[3/5]aba10lf:6,ls:4,rf:1,rs:1,a:2
[3/6]bbb4lf:4,rf:13,rp:4,a:1
[4/0]aabb16lf:16,rf:5
[4/1]aaaa16lf:9,lp:7,rf:5,rp:5
[4/2]abba15lf:13,ls:2,rf:4,rs:1
[4/3]baab13lf:10,lp:3,a:1
[4/4]baaa12lf:7,lp:2,ls:3,rf:2,rs:2
[4/5]aaab11lf:11,rf:5
[4/6]bbaa10lf:10,rf:2
[5/0]aaaab16lf:9,lp:7,rf:5,rp:5
[5/1]aabba15lf:13,ls:2,rf:2
[5/2]baabb10lf:7,lp:3,a:1
[5/3]abbaa10lf:10,rf:1
[5/4]aaabb9lf:9,rf:5
[5/5]bbaab7lf:7,a:3
[5/6]bbaaa6lf:3,ls:3,rf:2,rs:2
[6/0]aaaabb12lf:7,lp:5,rf:5,rp:5
[6/1]baabba10lf:5,lp:3,ls:2,a:1
[6/2]aabbaa10lf:10
[6/3]aaabba8lf:8,rf:2
[6/4]abbaab7lf:7,a:3
[6/5]bbaaba6lf:3,ls:3,a:3
[6/6]abbaaa6lf:3,ls:3,rf:1,rs:1
[7/0]aaaabba11lf:6,lp:5,rf:2,rp:2
[7/1]aabbaab7lf:7,a:3
[7/2]aaabbaa7lf:7
[7/3]baabbaa6lf:3,lp:3,a:1
[7/4]abbaaba6lf:3,ls:3,a:3
[7/5]aabbaaa6lf:3,ls:3
[7/6]bbaabba4lf:2,ls:2,a:6

Considering [length 4 / frequency 0] aabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaabbaaa=ba⟩.