Morphocompletion for #3928 ⟨a, b | aaaabbaaa=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaabbaaa ⇒ ab
2. abaaabbaaa ⇒ abb
3. aaaabbb ⇒ abbbaaa
4. aaaabbab ⇒ ababbaaa
5. aaaabbaab ⇒ abaabbaaa
6. abbaaabbaaa ⇒ abbb
7. abaaabbb ⇒ abbbbaaa
8. abaaabbab ⇒ abbabbaaa
9. abaaabbaab ⇒ abbaabbaaa
10. abbbaaabbaaa ⇒ abbbb
11. abbaaabbb ⇒ abbbbbaaa
12. abbaaabbab ⇒ abbbabbaaa
13. abbaaabbaab ⇒ abbbaabbaaa
14. abbbbaaabbaaa ⇒ abbbbb
15. abbbaaabbb ⇒ abbbbbbaaa
16. abbbaaabbab ⇒ abbbbabbaaa
17. abbbaaabbaab ⇒ abbbbaabbaaa
18. abbbbbaaabbaaa ⇒ abbbbbb
19. abbbbaaabbb ⇒ abbbbbbbaaa
20. abbbbbbaaabbaaa ⇒ abbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] bb, [2/3] ba
Length 3:[3/0] abb, [3/1] aaa, [3/2] aab, [3/3] bba, [3/4] baa, [3/5] bbb, [3/6] bab
Length 4:[4/0] baaa, [4/1] abbb, [4/2] abba, [4/3] bbaa, [4/4] aabb, [4/5] aaab, [4/6] bbab
Length 5:[5/0] bbaaa, [5/1] aaabb, [5/2] abbaa, [5/3] baaab, [5/4] aabba, [5/5] aabbb, [5/6] abbbb
Length 6:[6/0] abbaaa, [6/1] baaabb, [6/2] aaabba, [6/3] bbaaab, [6/4] aabbaa, [6/5] aaabbb, [6/6] aabbab
Length 7:[7/0] aabbaaa, [7/1] bbaaabb, [7/2] baaabba, [7/3] aaabbaa, [7/4] baaabbb, [7/5] bbbaaab, [7/6] aaabbab

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aaaabbaaa=ab.