| Back: | ⟨a, b | aaaabbaaa=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | aaaabbaaa ⇒ ab |
| 2. | abaaabbaaa ⇒ abb |
| 3. | aaaabbb ⇒ abbbaaa |
| 4. | aaaabbab ⇒ ababbaaa |
| 5. | aaaabbaab ⇒ abaabbaaa |
| 6. | abbaaabbaaa ⇒ abbb |
| 7. | abaaabbb ⇒ abbbbaaa |
| 8. | abaaabbab ⇒ abbabbaaa |
| 9. | abaaabbaab ⇒ abbaabbaaa |
| 10. | abbbaaabbaaa ⇒ abbbb |
| 11. | abbaaabbb ⇒ abbbbbaaa |
| 12. | abbaaabbab ⇒ abbbabbaaa |
| 13. | abbaaabbaab ⇒ abbbaabbaaa |
| 14. | abbbbaaabbaaa ⇒ abbbbb |
| 15. | abbbaaabbb ⇒ abbbbbbaaa |
| 16. | abbbaaabbab ⇒ abbbbabbaaa |
| 17. | abbbaaabbaab ⇒ abbbbaabbaaa |
| 18. | abbbbbaaabbaaa ⇒ abbbbbb |
| 19. | abbbbaaabbb ⇒ abbbbbbbaaa |
| 20. | abbbbbbaaabbaaa ⇒ abbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 73 | lf:62,lp:4,ls:7,rf:30,rs:13,lprs:3 |
|---|---|---|---|
| [2/1] | ab | 68 | lf:44,lp:16,ls:8,rf:28,rp:20,rs:1,re:1,lprp:16,lsrp:8 |
| [2/2] | bb | 57 | lf:52,ls:5,rf:61,rs:6 |
| [2/3] | ba | 31 | lf:31,rf:21 |
| [3/0] | abb | 44 | lf:32,lp:12,rf:25,rp:17,rs:1,re:1,lprp:12 |
| [3/1] | aaa | 42 | lf:31,lp:4,ls:7,rf:13,rs:13,lprs:3 |
| [3/2] | aab | 28 | lf:24,ls:4,rf:4 |
| [3/3] | bba | 27 | lf:27,rf:19 |
| [3/4] | baa | 27 | lf:27,rf:17 |
| [3/5] | bbb | 25 | lf:20,ls:5,rf:36,rs:5,a:4 |
| [3/6] | bab | 8 | lf:4,ls:4,rf:4,a:1 |
| [4/0] | baaa | 30 | lf:23,ls:7,rf:13,rs:13 |
| [4/1] | abbb | 26 | lf:13,lp:8,ls:5,rf:14,rp:14,rs:1,re:1,lprp:8,lsrp:5,a:4 |
| [4/2] | abba | 23 | lf:19,lp:4,rf:10,rp:2 |
| [4/3] | bbaa | 23 | lf:23,rf:16 |
| [4/4] | aabb | 20 | lf:20,rf:4 |
| [4/5] | aaab | 20 | lf:20 |
| [4/6] | bbab | 8 | lf:4,ls:4,rf:3,a:1 |
| [5/0] | bbaaa | 26 | lf:19,ls:7,rf:13,rs:13 |
| [5/1] | aaabb | 20 | lf:20 |
| [5/2] | abbaa | 19 | lf:15,lp:4,rf:9,rp:1 |
| [5/3] | baaab | 16 | lf:16,a:3 |
| [5/4] | aabba | 15 | lf:15,rf:4 |
| [5/5] | aabbb | 10 | lf:5,ls:5,a:8 |
| [5/6] | abbbb | 8 | lf:4,lp:4,rf:10,rp:10,rs:1,re:1,lprp:4,a:7 |
| [6/0] | abbaaa | 22 | lf:11,lp:4,ls:7,rf:8,rs:8,lprs:2 |
| [6/1] | baaabb | 16 | lf:16,a:3 |
| [6/2] | aaabba | 15 | lf:15 |
| [6/3] | bbaaab | 12 | lf:12,a:4 |
| [6/4] | aabbaa | 11 | lf:11,rf:4 |
| [6/5] | aaabbb | 10 | lf:5,ls:5,a:8 |
| [6/6] | aabbab | 8 | lf:4,ls:4,a:1 |
| [7/0] | aabbaaa | 14 | lf:7,ls:7,rf:4,rs:4 |
| [7/1] | bbaaabb | 12 | lf:12,a:4 |
| [7/2] | baaabba | 12 | lf:12,a:3 |
| [7/3] | aaabbaa | 11 | lf:11 |
| [7/4] | baaabbb | 8 | lf:4,ls:4,a:9 |
| [7/5] | bbbaaab | 8 | lf:8,a:7 |
| [7/6] | aaabbab | 8 | lf:4,ls:4,a:1 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aaaabbaaa=ab⟩.