| Back: | ⟨a, b | aaaababba=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaaababba ⇒ ab |
| 2. | abaababba ⇒ aaaababbb |
| 3. | abaaababba ⇒ abb |
| 4. | abbaababba ⇒ abaaababbb |
| 5. | abbaaababba ⇒ abbb |
| 6. | aaaababaaababbb ⇒ abababba |
| 7. | abbbaababba ⇒ abbaaababbb |
| 8. | abbbaaababba ⇒ abbbb |
| 9. | abaaababaaababbb ⇒ abbababba |
| 10. | abbbbaababba ⇒ abbbaaababbb |
| 11. | abbbbaaababba ⇒ abbbbb |
| 12. | abbaaababaaababbb ⇒ abbbababba |
| 13. | abbbbbaababba ⇒ abbbbaaababbb |
| 14. | abbbbbaaababba ⇒ abbbbbb |
| 15. | abbbbbbaaababba ⇒ abbbbbbb |
| 16. | abbbbbbbaaababba ⇒ abbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 66 | lf:52,lp:14,rf:31,rp:15,rs:1,re:1,lprp:13 |
|---|---|---|---|
| [2/1] | ba | 62 | lf:49,ls:13,rf:18,rs:3 |
| [2/2] | bb | 54 | lf:51,ls:3,rf:50,rs:12 |
| [2/3] | aa | 37 | lf:35,lp:2,rf:11,rp:1 |
| [3/0] | abb | 38 | lf:27,lp:11,rf:20,rp:12,rs:1,re:1,lprp:10 |
| [3/1] | bba | 37 | lf:24,ls:13,rf:8,rs:3 |
| [3/2] | aba | 28 | lf:25,lp:3,rf:10,rp:2 |
| [3/3] | bbb | 27 | lf:24,ls:3,rf:30,rs:11,a:2 |
| [3/4] | bab | 19 | lf:19,rf:11 |
| [3/5] | aab | 19 | lf:19,rf:5 |
| [3/6] | aaa | 18 | lf:16,lp:2,rf:6,rp:1 |
| [4/0] | abba | 32 | lf:16,lp:3,ls:13,rf:5,rp:2,rs:3,lsrp:1,lprs:1 |
| [4/1] | abbb | 22 | lf:11,lp:8,ls:3,rf:14,rp:9,rs:6,re:1,lprp:7,lsrp:1,lprs:3,a:2 |
| [4/2] | abab | 19 | lf:19,rf:9,rp:1 |
| [4/3] | aaba | 19 | lf:19,rf:5 |
| [4/4] | babb | 16 | lf:16,rf:8 |
| [4/5] | aaab | 14 | lf:14,rf:5 |
| [4/6] | bbbb | 13 | lf:13,rf:16,rs:5,a:3 |
| [5/0] | babba | 26 | lf:13,ls:13,rf:3,rs:3 |
| [5/1] | aabab | 19 | lf:19,rf:5 |
| [5/2] | ababb | 16 | lf:16,rf:8 |
| [5/3] | aaaba | 14 | lf:14,rf:5 |
| [5/4] | abbbb | 12 | lf:6,lp:6,rf:6,rp:6,rs:1,re:1,lprp:5,a:3 |
| [5/5] | baaab | 12 | lf:12,rf:4,a:1 |
| [5/6] | bbbaa | 8 | lf:8,rf:2,a:3 |
| [6/0] | ababba | 26 | lf:13,ls:13,rf:3,rs:3 |
| [6/1] | aababb | 16 | lf:16,rf:5 |
| [6/2] | aaabab | 14 | lf:14,rf:5 |
| [6/3] | baaaba | 12 | lf:12,rf:4,a:1 |
| [6/4] | abbbbb | 8 | lf:4,lp:4,rf:4,rp:4,rs:1,re:1,lprp:3,a:6 |
| [6/5] | bbaaab | 7 | lf:7,rf:3,a:2 |
| [6/6] | abaaab | 7 | lf:5,lp:2,rf:1,rp:1,a:1 |
| [7/0] | aababba | 26 | lf:13,ls:13 |
| [7/1] | baaabab | 12 | lf:12,rf:4,a:1 |
| [7/2] | aaababb | 11 | lf:11,rf:5 |
| [7/3] | bbaaaba | 7 | lf:7,rf:3,a:2 |
| [7/4] | abaaaba | 7 | lf:5,lp:2,rf:1,rp:1,a:1 |
| [7/5] | aababbb | 6 | lf:3,ls:3,rf:5,rs:5,a:4 |
| [7/6] | bbbaaab | 5 | lf:5,rf:2,a:3 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aaaababba=ab⟩.