Morphocompletion for #3889 ⟨a, b | aaaaabbba=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaabbba ⇒ ab
2. abaaabbba ⇒ aaaaabbbb
3. abaaaabbba ⇒ abb
4. abbaaabbba ⇒ abaaaabbbb
5. abbaaaabbba ⇒ abbb
6. aaaaabbaaaabbbb ⇒ abaabbba
7. abbbaaabbba ⇒ abbaaaabbbb
8. abbbaaaabbba ⇒ abbbb
9. abaaaabbaaaabbbb ⇒ abbaabbba
10. abbbbaaabbba ⇒ abbbaaaabbbb
11. abbbbaaaabbba ⇒ abbbbb
12. abbaaaabbaaaabbbb ⇒ abbbaabbba
13. abbbbbaaabbba ⇒ abbbbaaaabbbb
14. abbbbbaaaabbba ⇒ abbbbbb
15. abbbbbbaaabbba ⇒ abbbbbaaaabbbb
16. abbbbbbaaaabbba ⇒ abbbbbbb
17. abbbbbbbaaaabbba ⇒ abbbbbbbb
18. abbbbbbbbaaaabbba ⇒ abbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb89lf:86,ls:3,rf:73,rs:14
[2/1]aa61lf:59,lp:2,rf:22,rp:1
[2/2]ab53lf:37,lp:16,rf:26,rp:17,rs:1,re:1,lprp:15
[2/3]ba49lf:34,ls:15,rf:11,rs:3
[3/0]bbb55lf:52,ls:3,rf:50,rs:13
[3/1]abb47lf:34,lp:13,rf:23,rp:14,rs:1,re:1,lprp:12
[3/2]bba46lf:31,ls:15,rf:9,rs:3
[3/3]aaa40lf:38,lp:2,rf:13,rp:1
[3/4]aab21lf:21,rf:9
[3/5]baa19lf:19,rf:8,a:1
[3/6]aba6lf:3,lp:3,rf:2,rp:2,a:1
[4/0]bbba40lf:25,ls:15,rf:7,rs:3
[4/1]abbb38lf:28,lp:10,rf:20,rp:11,rs:1,re:1,lprp:9
[4/2]bbbb27lf:24,ls:3,rf:30,rs:12,a:3
[4/3]aabb21lf:21,rf:9
[4/4]aaab21lf:21,rf:6
[4/5]baaa19lf:19,rf:5,a:1
[4/6]aaaa19lf:17,lp:2,rf:7,rp:1
[5/0]abbba34lf:17,lp:2,ls:15,rf:5,rp:2,rs:3,lsrp:1
[5/1]abbbb22lf:11,lp:8,ls:3,rf:14,rp:8,rs:7,re:1,lprp:7,lprs:3,a:3
[5/2]aaabb21lf:21,rf:6
[5/3]aabbb18lf:18,rf:9
[5/4]bbaaa16lf:16,rf:4,a:2
[5/5]aaaab15lf:15,rf:6
[5/6]bbbbb13lf:13,rf:16,rs:5,a:4
[6/0]aabbba30lf:15,ls:15,rf:3,rs:3
[6/1]aaabbb18lf:18,rf:6
[6/2]aaaabb15lf:15,rf:6
[6/3]baaaab13lf:13,rf:5,a:1
[6/4]abbbbb12lf:6,lp:6,rf:6,rp:6,rs:1,re:1,lprp:5,a:4
[6/5]bbaaaa11lf:11,rf:4,a:2
[6/6]bbbaaa10lf:10,rf:3,a:3
[7/0]aaabbba30lf:15,ls:15
[7/1]baaaabb13lf:13,rf:5,a:1
[7/2]aaaabbb12lf:12,rf:6
[7/3]bbaaaab11lf:11,rf:4,a:2
[7/4]abbbbbb8lf:4,lp:4,rf:4,rp:4,rs:1,re:1,lprp:3,a:5
[7/5]bbbbaaa8lf:8,rf:2,a:4
[7/6]abbaaaa7lf:5,lp:2,rf:1,rp:1,a:2

Considering [length 4 / frequency 0] bbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaaabbba=ab⟩.