Morphocompletion for #3882 ⟨a, b | aaaaabbaa=ba⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	aaaaabbaa ⇒ ba
2.	aaaaabbba ⇒ baaaabbaa
3.	aaaaabbaba ⇒ bba
4.	aaaaabbbba ⇒ baaaabbaba
5.	aaaaabbabba ⇒ bbba
6.	aaaaabbbbba ⇒ baaaabbabba
7.	aaaaabbabbba ⇒ bbbba
8.	aaaaabbbbbba ⇒ baaaabbabbba
9.	aaaaabbabbbba ⇒ bbbbba
10.	aaaaabbbbbbba ⇒ baaaabbabbbba
11.	aaaaabbabbbbba ⇒ bbbbbba
12.	aaaaabbbbbbbba ⇒ baaaabbabbbbba
13.	aaaaabbabbbbbba ⇒ bbbbbbba
14.	aaaaabbbbbbbbba ⇒ baaaabbabbbbbba
15.	aaaaabbabbbbbbba ⇒ bbbbbbbba
16.	aaaaabbbbbbbbbba ⇒ baaaabbabbbbbbba
17.	aaaaabbabbbbbbbba ⇒ bbbbbbbbba
18.	aaaaabbabbbbbbbbba ⇒ bbbbbbbbbba
19.	aaaaabbabbbbbbbbbba ⇒ bbbbbbbbbbba
20.	aaaaabbabbbbbbbbbbba ⇒ bbbbbbbbbbbba
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] bb, [2/1] aa, [2/2] ba, [2/3] ab
Length 3:	[3/0] bbb, [3/1] aaa, [3/2] bba, [3/3] abb, [3/4] aab, [3/5] bab, [3/6] aba
Length 4:	[4/0] bbbb, [4/1] aaaa, [4/2] bbba, [4/3] aabb, [4/4] aaab, [4/5] abbb, [4/6] abba
Length 5:	[5/0] bbbbb, [5/1] aaaaa, [5/2] bbbba, [5/3] aaabb, [5/4] aaaab, [5/5] abbbb, [5/6] aabba
Length 6:	[6/0] aaaaab, [6/1] bbbbbb, [6/2] bbbbba, [6/3] aaaabb, [6/4] abbbbb, [6/5] aaabba, [6/6] aabbab
Length 7:	[7/0] aaaaabb, [7/1] bbbbbbb, [7/2] bbbbbba, [7/3] aaaabba, [7/4] abbbbbb, [7/5] aaabbab, [7/6] aabbabb

Considering [length 7 / frequency 0] aaaaabb=c.

Reduction order:
- Left-to-right recursive path with deg(a) = 0; deg(c) = deg(b) = 1, c < b
Auxiliary generators:
1. aaaaabb=c

Rewriting system is complete. See ⟨a, b | aaaaabbaa=ba⟩.