Morphocompletion for #3882 ⟨a, b | aaaaabbaa=ba⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaaabbaa ⇒ ba
2. aaaaabbba ⇒ baaaabbaa
3. aaaaabbaba ⇒ bba
4. aaaaabbbba ⇒ baaaabbaba
5. aaaaabbabba ⇒ bbba
6. aaaaabbbbba ⇒ baaaabbabba
7. aaaaabbabbba ⇒ bbbba
8. aaaaabbbbbba ⇒ baaaabbabbba
9. aaaaabbabbbba ⇒ bbbbba
10. aaaaabbbbbbba ⇒ baaaabbabbbba
11. aaaaabbabbbbba ⇒ bbbbbba
12. aaaaabbbbbbbba ⇒ baaaabbabbbbba
13. aaaaabbabbbbbba ⇒ bbbbbbba
14. aaaaabbbbbbbbba ⇒ baaaabbabbbbbba
15. aaaaabbabbbbbbba ⇒ bbbbbbbba
16. aaaaabbbbbbbbbba ⇒ baaaabbabbbbbbba
17. aaaaabbabbbbbbbba ⇒ bbbbbbbbba
18. aaaaabbabbbbbbbbba ⇒ bbbbbbbbbba
19. aaaaabbabbbbbbbbbba ⇒ bbbbbbbbbbba
20. aaaaabbabbbbbbbbbbba ⇒ bbbbbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb111lf:111,rf:95,rp:11
[2/1]aa102lf:81,lp:20,ls:1,rf:25,rs:1,lprs:1
[2/2]ba50lf:31,ls:19,rf:35,rp:9,rs:19,re:1,lsrp:8,lsrs:18
[2/3]ab31lf:31,rf:15
[3/0]bbb81lf:81,rf:70,rp:10,a:1
[3/1]aaa80lf:60,lp:20,rf:16
[3/2]bba48lf:30,ls:18,rf:25,rp:1,rs:17,re:1,lsrs:16
[3/3]abb30lf:30,rf:14
[3/4]aab20lf:20,rf:8
[3/5]bab11lf:11,rf:7,a:2
[3/6]aba2lf:1,ls:1,rf:1,rs:1,a:2
[4/0]bbbb64lf:64,rf:55,rp:9,a:3
[4/1]aaaa60lf:40,lp:20,rf:8
[4/2]bbba34lf:17,ls:17,rf:15,rp:1,rs:15,re:1,lsrs:14,a:1
[4/3]aabb20lf:20,rf:8
[4/4]aaab20lf:20,rf:8
[4/5]abbb17lf:17,rf:5,a:1
[4/6]abba14lf:13,ls:1,rf:9,rs:1
[5/0]bbbbb49lf:49,rf:42,rp:8,a:6
[5/1]aaaaa40lf:20,lp:20
[5/2]bbbba30lf:15,ls:15,rf:13,rp:1,rs:13,re:1,lsrs:12,a:3
[5/3]aaabb20lf:20,rf:8
[5/4]aaaab20lf:20,rf:8
[5/5]abbbb15lf:15,rf:4,a:3
[5/6]aabba12lf:12,rf:8
[6/0]aaaaab40lf:20,lp:20
[6/1]bbbbbb36lf:36,rf:31,rp:7,a:8
[6/2]bbbbba26lf:13,ls:13,rf:11,rp:1,rs:11,re:1,lsrs:10,a:6
[6/3]aaaabb20lf:20,rf:8
[6/4]abbbbb13lf:13,rf:3,a:6
[6/5]aaabba12lf:12,rf:8
[6/6]aabbab11lf:11,rf:7,a:2
[7/0]aaaaabb40lf:20,lp:20
[7/1]bbbbbbb25lf:25,rf:22,rp:6,a:10
[7/2]bbbbbba22lf:11,ls:11,rf:9,rp:1,rs:9,re:1,lsrs:8,a:8
[7/3]aaaabba12lf:12,rf:8
[7/4]abbbbbb11lf:11,rf:2,a:9
[7/5]aaabbab11lf:11,rf:7,a:2
[7/6]aabbabb10lf:10,rf:6,a:4

Considering [length 7 / frequency 0] aaaaabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaaabbaa=ba⟩.