Morphocompletion for #3881 ⟨a, b | aaaaabbaa=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaaabbaa ⇒ ab
2. abaaaabbaa ⇒ abb
3. aaaaabbb ⇒ abaabbaa
4. aaaaabbab ⇒ abaaabbaa
5. abbaaaabbaa ⇒ abbb
6. abaaaabbb ⇒ abbaabbaa
7. abaaaabbab ⇒ abbaaabbaa
8. abbbaaaabbaa ⇒ abbbb
9. abbaaaabbb ⇒ abbbaabbaa
10. abbaaaabbab ⇒ abbbaaabbaa
11. abbbbaaaabbaa ⇒ abbbbb
12. abbbaaaabbb ⇒ abbbbaabbaa
13. abbbaaaabbab ⇒ abbbbaaabbaa
14. abbbbbaaaabbaa ⇒ abbbbbb
15. abbbbaaaabbb ⇒ abbbbbaabbaa
16. abbbbaaaabbab ⇒ abbbbbaaabbaa
17. abbbbbbaaaabbaa ⇒ abbbbbbb
18. abbbbbaaaabbb ⇒ abbbbbbaabbaa
19. abbbbbbbaaaabbaa ⇒ abbbbbbbb
20. abbbbbbbbaaaabbaa ⇒ abbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa84lf:72,lp:3,ls:9,rf:27,rs:11,lprs:2
[2/1]bb76lf:70,ls:6,rf:72,rs:8
[2/2]ab64lf:42,lp:17,ls:5,rf:31,rp:20,rs:1,re:1,lprp:17,lsrp:5
[2/3]ba31lf:31,rf:22
[3/0]abb48lf:34,lp:14,rf:28,rp:17,rs:1,re:1,lprp:14
[3/1]aaa46lf:43,lp:3,rf:5
[3/2]bbb42lf:36,ls:6,rf:44,rs:7,a:3
[3/3]baa35lf:26,ls:9,rf:22,rs:11
[3/4]bba28lf:28,rf:20
[3/5]aab20lf:20,rf:11
[3/6]bab10lf:5,ls:5,a:1
[4/0]abbb34lf:17,lp:11,ls:6,rf:14,rp:14,rs:1,re:1,lprp:11,lsrp:4,a:3
[4/1]bbaa32lf:23,ls:9,rf:20,rs:11
[4/2]aaaa26lf:23,lp:3
[4/3]aabb20lf:20,rf:11
[4/4]abba20lf:17,lp:3,rf:13,rp:2
[4/5]aaab20lf:20,rf:5
[4/6]bbbb19lf:19,rf:30,rs:6,a:5
[5/0]abbaa24lf:12,lp:3,ls:9,rf:13,rp:2,rs:11,lprs:2
[5/1]aaabb20lf:20,rf:5
[5/2]aaaab20lf:20
[5/3]baaaa17lf:17,a:2
[5/4]abbbb16lf:8,lp:8,rf:11,rp:11,rs:1,re:1,lprp:8,a:5
[5/5]aabba14lf:14,rf:11
[5/6]bbaaa14lf:14,rf:4,a:3
[6/0]aaaabb20lf:20
[6/1]aabbaa18lf:9,ls:9,rf:11,rs:11
[6/2]baaaab17lf:17,a:2
[6/3]aaabba14lf:14,rf:5
[6/4]bbaaaa14lf:14,a:3
[6/5]aaabbb12lf:6,ls:6,a:6
[6/6]bbbaaa11lf:11,rf:3,a:5
[7/0]aaabbaa18lf:9,ls:9,rf:5,rs:5
[7/1]baaaabb17lf:17,a:2
[7/2]bbaaaab14lf:14,a:3
[7/3]aaaabba14lf:14
[7/4]aaaabbb12lf:6,ls:6,a:6
[7/5]bbbaaaa11lf:11,a:5
[7/6]aaabbab10lf:5,ls:5,a:1

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaaabbaa=ab⟩.