Morphocompletion for #3881 ⟨a, b | aaaaabbaa=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	aaaaabbaa ⇒ ab
2.	abaaaabbaa ⇒ abb
3.	aaaaabbb ⇒ abaabbaa
4.	aaaaabbab ⇒ abaaabbaa
5.	abbaaaabbaa ⇒ abbb
6.	abaaaabbb ⇒ abbaabbaa
7.	abaaaabbab ⇒ abbaaabbaa
8.	abbbaaaabbaa ⇒ abbbb
9.	abbaaaabbb ⇒ abbbaabbaa
10.	abbaaaabbab ⇒ abbbaaabbaa
11.	abbbbaaaabbaa ⇒ abbbbb
12.	abbbaaaabbb ⇒ abbbbaabbaa
13.	abbbaaaabbab ⇒ abbbbaaabbaa
14.	abbbbbaaaabbaa ⇒ abbbbbb
15.	abbbbaaaabbb ⇒ abbbbbaabbaa
16.	abbbbaaaabbab ⇒ abbbbbaaabbaa
17.	abbbbbbaaaabbaa ⇒ abbbbbbb
18.	abbbbbaaaabbb ⇒ abbbbbbaabbaa
19.	abbbbbbbaaaabbaa ⇒ abbbbbbbb
20.	abbbbbbbbaaaabbaa ⇒ abbbbbbbbb
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] aa, [2/1] bb, [2/2] ab, [2/3] ba
Length 3:	[3/0] abb, [3/1] aaa, [3/2] bbb, [3/3] baa, [3/4] bba, [3/5] aab, [3/6] bab
Length 4:	[4/0] abbb, [4/1] bbaa, [4/2] aaaa, [4/3] aabb, [4/4] abba, [4/5] aaab, [4/6] bbbb
Length 5:	[5/0] abbaa, [5/1] aaabb, [5/2] aaaab, [5/3] baaaa, [5/4] abbbb, [5/5] aabba, [5/6] bbaaa
Length 6:	[6/0] aaaabb, [6/1] aabbaa, [6/2] baaaab, [6/3] aaabba, [6/4] bbaaaa, [6/5] aaabbb, [6/6] bbbaaa
Length 7:	[7/0] aaabbaa, [7/1] baaaabb, [7/2] bbaaaab, [7/3] aaaabba, [7/4] aaaabbb, [7/5] bbbaaaa, [7/6] aaabbab

Considering [length 3 / frequency 0] abb=c.

Reduction order:
- Left-to-right recursive path with deg(c) = deg(a) = 0, c < a; deg(b) = 1
Auxiliary generators:
1. abb=c

Rewriting system is complete. See ⟨a, b | aaaaabbaa=ab⟩.