| Back: | ⟨a, b | abbbaabbba=b⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abbbab ⇒ babbba |
| 2. | abbbaabbba ⇒ b |
| 3. | abbbbbbb ⇒ bbbbbbba |
| 4. | abbbbabbba ⇒ bbbabbbaab |
| 5. | abbbaabbbb ⇒ bbbbaabbba |
| 6. | abbbbbabbba ⇒ bbbabbbaabb |
| 7. | bbbabbbaaabbba ⇒ abbbb |
| 8. | bbbabbbaaaabbba ⇒ aabbbb |
| 9. | bbbabbbaaaaabbba ⇒ aaabbbb |
| 10. | bbbabbbaababbba ⇒ abbbbb |
| 11. | bbbabbbaabaabbba ⇒ ababbbb |
| 12. | bbbabbbaaababbba ⇒ aabbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 72 | lf:64,lp:6,ls:2,rf:42,rp:4,rs:7,lsrp:2,lprs:6 |
|---|---|---|---|
| [2/1] | ba | 38 | lf:29,ls:9,rf:10,rp:1,rs:3 |
| [2/2] | ab | 33 | lf:26,lp:6,ls:1,rf:13,rp:3,rs:1,lprs:1 |
| [2/3] | aa | 16 | lf:16,rf:7,rp:3 |
| [3/0] | bbb | 44 | lf:36,lp:6,ls:2,rf:27,rp:4,rs:6,lsrp:2,lprs:6 |
| [3/1] | bba | 35 | lf:26,ls:9,rf:8,rs:3 |
| [3/2] | abb | 28 | lf:22,lp:6,rf:11,rp:2,rs:1,lprs:1 |
| [3/3] | bab | 12 | lf:11,ls:1,rf:4,rp:1,lsrp:1,a:1 |
| [3/4] | aab | 9 | lf:9,rf:6,rp:2,rs:1 |
| [3/5] | baa | 9 | lf:9,rf:3 |
| [3/6] | aaa | 7 | lf:7,rf:1,rp:1,a:3 |
| [4/0] | bbba | 41 | lf:26,lp:6,ls:9,rf:8,rp:2,rs:3,lsrp:2 |
| [4/1] | abbb | 28 | lf:22,lp:6,rf:10,rp:2 |
| [4/2] | bbbb | 10 | lf:8,ls:2,rf:13,rp:2,rs:6,lsrp:2,a:2 |
| [4/3] | babb | 10 | lf:10,rf:4,rp:1,a:1 |
| [4/4] | bbab | 10 | lf:9,ls:1,rf:2,a:1 |
| [4/5] | bbaa | 8 | lf:8,rf:3 |
| [4/6] | aabb | 6 | lf:6,rf:5,rp:2,rs:1 |
| [5/0] | abbba | 30 | lf:18,lp:3,ls:9,rf:4,rs:2,lprs:11 |
| [5/1] | bbbab | 16 | lf:9,lp:6,ls:1,rf:2,rp:2,a:1 |
| [5/2] | babbb | 10 | lf:10,rf:4,rp:1,a:1 |
| [5/3] | abbbb | 8 | lf:4,lp:3,ls:1,rf:6,rp:2,rs:4,re:1,a:2 |
| [5/4] | bbabb | 8 | lf:8,rf:2,a:3 |
| [5/5] | bbbaa | 8 | lf:8,rf:3 |
| [5/6] | aabbb | 6 | lf:6,rf:4,rp:2 |
| [6/0] | bbbabb | 14 | lf:8,lp:6,rf:2,rp:2,a:3 |
| [6/1] | babbba | 14 | lf:10,ls:4,rf:3,rp:1,rs:1,re:1,a:1 |
| [6/2] | aabbba | 10 | lf:5,ls:5,rf:1,rs:1 |
| [6/3] | abbbaa | 10 | lf:8,lp:2,rf:2 |
| [6/4] | bbabbb | 8 | lf:8,rf:2,a:3 |
| [6/5] | abbbbb | 4 | lf:2,lp:2,rf:2,rp:1,rs:2,re:1,a:6 |
| [6/6] | bbbaab | 4 | lf:4,rf:3,rs:1 |
| [7/0] | bbbabbb | 14 | lf:8,lp:6,rf:2,rp:2,a:3 |
| [7/1] | bbabbba | 10 | lf:8,ls:2,rf:2,a:3 |
| [7/2] | abbbaab | 6 | lf:4,lp:2,rf:2,rs:1 |
| [7/3] | babbbaa | 6 | lf:6,rf:2,a:3 |
| [7/4] | aaabbba | 6 | lf:3,ls:3,a:3 |
| [7/5] | ababbba | 4 | lf:2,ls:2,a:6 |
| [7/6] | baabbba | 4 | lf:2,ls:2,rf:1,rs:1 |
Considering [length 4 / frequency 0] bbba=c.
Rewriting system is complete. See ⟨a, b | abbbaabbba=b⟩.