Morphocompletion for #3818 ⟨a, b | abbabbaaab=b⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbabbb ⇒ b
2. bbabbab ⇒ abbabbb
3. bbabbaab ⇒ aabbabbb
4. bbbbaaab ⇒ bbaaabbb
5. bbabbaaab ⇒ aaabbabbb
6. abbabbbbab ⇒ bbaabbabbb
7. bbaaabbaabbabbb ⇒ bbbbab
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb28lf:21,lp:5,ls:2,rf:19,rp:3,rs:5,lprp:2,lsrp:1,lprs:4,a:1
[2/1]ab21lf:15,lp:1,ls:5,rf:10,rp:1,rs:1,lsrp:1,a:1
[2/2]ba13lf:13,rf:7,a:1
[2/3]aa12lf:11,lp:1,rf:6,rp:2,a:1
[3/0]bba17lf:13,lp:4,rf:7,rp:2,a:1
[3/1]abb11lf:10,lp:1,rf:9,rp:1,a:1
[3/2]bab10lf:8,ls:2,rf:5,rs:1,a:1
[3/3]bbb9lf:6,lp:1,ls:2,rf:7,rp:1,rs:5,lsrp:1,lprs:1,a:1
[3/4]aab9lf:6,ls:3,rf:4,rp:1,lsrp:1,a:1
[3/5]aaa6lf:5,lp:1,rf:2,rp:1,a:1
[3/6]baa5lf:5,rf:2,a:1
[4/0]bbab13lf:8,lp:3,ls:2,rf:5,rs:1,a:1
[4/1]abba8lf:7,lp:1,rf:4,rp:1,a:1
[4/2]babb6lf:6,rf:4,a:1
[4/3]bbaa6lf:5,lp:1,rf:2,rp:2,a:1
[4/4]aaab6lf:4,ls:2,rf:2,rp:1,lsrp:1,a:1
[4/5]abbb5lf:3,ls:2,rf:5,rs:5,a:1
[4/6]bbbb3lf:2,lp:1,rf:1,rp:1,a:13
[5/0]bbabb9lf:6,lp:3,rf:4,a:1
[5/1]abbab6lf:4,lp:1,ls:1,rf:4,rp:1,lsrp:1,a:1
[5/2]babbb5lf:3,ls:2,rf:4,rs:4,a:1
[5/3]baaab5lf:3,ls:2,rf:1,a:1
[5/4]bbaaa4lf:3,lp:1,rf:1,rp:1,a:1
[5/5]bbbba3lf:2,lp:1,rf:1,rp:1,a:13
[5/6]babba3lf:3,a:1
[6/0]bbabba6lf:3,lp:3,a:1
[6/1]bbaaab6lf:3,lp:1,ls:2,rf:1,rp:1,lsrp:1,a:1
[6/2]bbabbb5lf:3,ls:2,rf:4,rs:4,a:1
[6/3]abbabb4lf:3,lp:1,rf:4,rp:1,a:1
[6/4]abbaab3lf:2,ls:1,a:3
[6/5]bbbbab2lf:1,ls:1,rf:1,rp:1,rs:1,re:1,a:13
[6/6]bbbbaa2lf:1,lp:1,a:25
[7/0]abbabbb6lf:3,lp:1,ls:2,rf:4,rp:1,rs:4,re:1,lprs:1,a:1
[7/1]bbabbaa4lf:2,lp:2,a:1
[7/2]abbbbab2lf:1,ls:1,a:13
[7/3]bbbbaaa2lf:1,lp:1,a:25
[7/4]bbbaaab2lf:1,ls:1,a:25
[7/5]babbaab2lf:1,ls:1,a:3
[7/6]bbaaabb2lf:1,lp:1,rf:1,rp:1,a:25

Considering [length 3 / frequency 0] bba=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbabbaaab=b⟩.