Morphocompletion for #3818 ⟨a, b | abbabbaaab=b⟩

Back:⟨a, b | abbabbaaab=b⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbabbb ⇒ b
2. bbabbab ⇒ abbabbb
3. bbabbaab ⇒ aabbabbb
4. bbbbaaab ⇒ bbaaabbb
5. bbabbaaab ⇒ aaabbabbb
6. abbabbbbab ⇒ bbaabbabbb
7. bbaaabbaabbabbb ⇒ bbbbab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] bba, [3/1] abb, [3/2] bab, [3/3] bbb, [3/4] aab, [3/5] aaa, [3/6] baa
Length 4:[4/0] bbab, [4/1] abba, [4/2] babb, [4/3] bbaa, [4/4] aaab, [4/5] abbb, [4/6] bbbb
Length 5:[5/0] bbabb, [5/1] abbab, [5/2] babbb, [5/3] baaab, [5/4] bbaaa, [5/5] bbbba, [5/6] babba
Length 6:[6/0] bbabba, [6/1] bbaaab, [6/2] bbabbb, [6/3] abbabb, [6/4] abbaab, [6/5] bbbbab, [6/6] bbbbaa
Length 7:[7/0] abbabbb, [7/1] bbabbaa, [7/2] abbbbab, [7/3] bbbbaaa, [7/4] bbbaaab, [7/5] babbaab, [7/6] bbaaabb

Considering [length 3 / frequency 0] bba=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbabbaaab=b⟩.