Morphocompletion for #3817 ⟨a, b | abbabbaaab=a⟩

Solved by morph:2/0,3/1,4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbb ⇒ ababbaa
2. abaaabbb ⇒ abbabbaa
3. aabbaaab ⇒ ababbaaa
4. ababbaaab ⇒ abbabbaaa
5. abbabbaaab ⇒ a
6. ababbaababbaaa ⇒ aaaab
7. abbabbaababbaaa ⇒ abaaab
8. ababbaabbabbaaa ⇒ aaaabb
9. abbabbaabbabbaaa ⇒ abaaabb
10. abbabbaaaaaab ⇒ aabbaababbaaa
11. aaaababbbbabbaaa ⇒ aaaabab
12. ababbaababbababbaa ⇒ aaaababbb
...

Collecting factors up to length 7 / frequency 3:

[2/0]ab52lf:39,lp:9,ls:4,rf:21,rp:6,rs:3,lprp:4,lsrp:2,lprs:2
[2/1]aa45lf:36,lp:3,ls:6,rf:26,rp:5,rs:5,lprp:1,lsrp:4,lprs:2
[2/2]ba33lf:33,rf:15
[3/0]abb29lf:25,lp:4,rf:11,rp:2,rs:2,lprs:1
[3/1]aaa24lf:17,lp:2,ls:5,rf:13,rp:4,rs:3,lprp:1,lsrp:3
[3/2]bba23lf:23,rf:8
[4/0]abba26lf:22,lp:4,rf:8,rp:2
[4/1]bbaa16lf:15,ls:1,rf:6,rs:2
[4/2]babb16lf:16,rf:6
[5/0]abbaa16lf:15,ls:1,rf:6,rs:2
[5/1]babba15lf:15,rf:5
[5/2]bbaaa14lf:9,ls:5,rf:3,rs:3
[6/0]babbaa15lf:14,ls:1,rf:5,rs:2
[6/1]abbaaa14lf:9,ls:5,rf:3,rs:3
[6/2]ababba12lf:8,lp:4,rf:3,rp:2,a:1

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cbcbaac ⇒ a
3. ccbaacb ⇒ a
4. caacbb ⇒ cbcbaa
5. ccbaaccbb ⇒ cbcbccbaa
6. caacbcbbb ⇒ cbcbacbcbccbac
7. caacbcbbcb ⇒ cbcbacbcba
8. cbcbaaa ⇒ ccbaac
9. cbcbacbcbccbaa ⇒ caacbcbb
10. acbaac ⇒ ccbaaa
11. cbcbaccbaac ⇒ caacb
12. cbcbccbaccbaac ⇒ ccbaaccb
13. aaacb ⇒ ccbaccbaac
14. ccbaccbaaa ⇒ aaac
15. cbcbaccbaaa ⇒ caac
16. ccbaaccbaac ⇒ acbaaa
17. ccbaccbccbaccbaac ⇒ aaaccb
18. ccbaacaacb ⇒ acbaccbaac
19. acbaccbaaa ⇒ ccbaacaac
20. ccbaccbaacaac ⇒ aaccbaaa
...

Collecting factors up to length 6 / frequency 5:

[2/0]cb55lf:45,lp:6,ls:4,rf:29,rp:4,rs:3,lsrp:1,lprs:2,a:2
[2/1]ac37lf:28,lp:2,ls:7,rf:19,rp:2,rs:7,lsrp:1,lprs:1,a:2
[2/2]aa33lf:27,lp:1,ls:5,rf:22,rp:3,rs:5,lsrp:1,a:2
[2/3]cc27lf:20,lp:7,rf:12,rp:5,a:3
[2/4]ba25lf:25,rf:16,rs:1,a:2
[3/0]ccb27lf:20,lp:7,rf:12,rp:5,rs:2,lprs:1,a:3
[3/1]cba25lf:25,rf:16,rs:1,a:2
[3/2]aac24lf:17,ls:7,rf:12,rp:1,rs:6,lsrp:1,a:2
[3/3]cbc18lf:12,lp:6,rf:9,rp:4,a:2
[3/4]baa17lf:16,ls:1,rf:10,rs:2,a:2
[4/0]ccba25lf:18,lp:7,rf:10,rp:5,a:3
[4/1]baac17lf:11,ls:6,rf:5,rs:3,a:2
[4/2]cbaa17lf:16,ls:1,rf:10,rs:2,a:2
[4/3]cbcb15lf:9,lp:6,rf:7,rp:4,a:2
[4/4]accb10lf:10,rf:5,rs:2,a:6
[5/0]ccbaa18lf:13,lp:4,ls:1,rf:8,rp:4,rs:1,lprs:1,a:3
[5/1]cbaac17lf:11,ls:6,rf:5,rs:3,a:2
[5/2]cbcba10lf:5,lp:5,rf:4,rp:3,rs:1,a:2
[5/3]cbaaa8lf:4,ls:4,rf:3,rs:3,a:3
[5/4]caacb8lf:4,lp:3,ls:1,rf:2,rp:2,rs:1,re:1,a:14

Considering [length 3 / frequency 1] cba=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. db ⇒ cbc
2. cba ⇒ d
3. cbdac ⇒ a
4. ab ⇒ c
5. cdacb ⇒ a
6. ddacb ⇒ cbcdac
7. cbdad ⇒ ca
8. cbcdad ⇒ da
9. cbdcdad ⇒ cdac
10. cbcdcdad ⇒ ddac
11. aa ⇒ cdad
12. cbcdaca ⇒ ddad
13. cbdcdaca ⇒ ccdadd
14. adac ⇒ cdcdad
15. adad ⇒ cdaca
16. acdad ⇒ cdada
17. adcdad ⇒ cdacdac
18. acdaca ⇒ cdaddad
...

Collecting factors up to length 6 / frequency 5:

[2/0]ad20lf:10,lp:3,ls:7,rf:7,rs:4,lprs:1,a:5
[2/1]cb20lf:10,lp:8,ls:2,rf:2,rp:2,lsrp:1,a:2
[2/2]da14lf:14,rf:15,rp:1,rs:2,re:1,a:3
[2/3]ac13lf:9,lp:2,ls:2,rf:6,rs:4,a:3
[2/4]cd11lf:10,lp:1,rf:11,rp:7,a:6
[3/0]dad14lf:7,ls:7,rf:7,rs:4,a:5
[3/1]cda10lf:9,lp:1,rf:10,rp:6,a:6
[3/2]dac9lf:7,ls:2,rf:6,rs:4,a:3
[3/3]cbd8lf:4,lp:4,a:3
[3/4]aca6lf:3,ls:3,rf:1,rs:1,a:15
[4/0]cdad10lf:5,ls:5,rf:5,rp:3,rs:2,re:1,lsrp:10,a:6
[4/1]daca6lf:3,ls:3,rf:1,rs:1,a:15
[4/2]cbcd6lf:3,lp:3,rf:1,rp:1,a:8
[4/3]cdac5lf:4,lp:1,rf:5,rp:3,rs:3,re:1,a:6
[4/4]acda4lf:2,lp:2,rf:1,a:10
[5/0]cdaca6lf:3,ls:3,rf:1,rp:1,rs:1,re:1,a:15
[5/1]dcdad6lf:3,ls:3,rf:1,rs:1,a:6
[5/2]cbcda4lf:2,lp:2,rf:1,rp:1,a:8
[5/3]cbdcd4lf:2,lp:2,a:6
[5/4]acdac2lf:1,lp:1,rf:1,rs:1,a:17

Considering [length 4 / frequency 1] daca=e.

Step 4

Rewriting system is complete. See ⟨a, b | abbabbaaab=a⟩.