Morphocompletion for #3817 ⟨a, b | abbabbaaab=a

Solved by morph:2/0,3/1,4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbb ⇒ ababbaa
2. abaaabbb ⇒ abbabbaa
3. aabbaaab ⇒ ababbaaa
4. ababbaaab ⇒ abbabbaaa
5. abbabbaaab ⇒ a
6. ababbaababbaaa ⇒ aaaab
7. abbabbaababbaaa ⇒ abaaab
8. ababbaabbabbaaa ⇒ aaaabb
9. abbabbaabbabbaaa ⇒ abaaabb
10. abbabbaaaaaab ⇒ aabbaababbaaa
11. aaaababbbbabbaaa ⇒ aaaabab
12. ababbaababbababbaa ⇒ aaaababbb
...

Collecting factors up to length 7, frequency 3:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba
Length 3:[3/0] abb, [3/1] aaa, [3/2] bba
Length 4:[4/0] abba, [4/1] bbaa, [4/2] babb
Length 5:[5/0] abbaa, [5/1] babba, [5/2] bbaaa
Length 6:[6/0] babbaa, [6/1] abbaaa, [6/2] ababba

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cbcbaac ⇒ a
3. ccbaacb ⇒ a
4. caacbb ⇒ cbcbaa
5. ccbaaccbb ⇒ cbcbccbaa
6. caacbcbbb ⇒ cbcbacbcbccbac
7. caacbcbbcb ⇒ cbcbacbcba
8. cbcbaaa ⇒ ccbaac
9. cbcbacbcbccbaa ⇒ caacbcbb
10. acbaac ⇒ ccbaaa
11. cbcbaccbaac ⇒ caacb
12. cbcbccbaccbaac ⇒ ccbaaccb
13. aaacb ⇒ ccbaccbaac
14. ccbaccbaaa ⇒ aaac
15. cbcbaccbaaa ⇒ caac
16. ccbaaccbaac ⇒ acbaaa
17. ccbaccbccbaccbaac ⇒ aaaccb
18. ccbaacaacb ⇒ acbaccbaac
19. acbaccbaaa ⇒ ccbaacaac
20. ccbaccbaacaac ⇒ aaccbaaa
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] cb, [2/1] ac, [2/2] aa, [2/3] cc, [2/4] ba
Length 3:[3/0] ccb, [3/1] cba, [3/2] aac, [3/3] cbc, [3/4] baa
Length 4:[4/0] ccba, [4/1] baac, [4/2] cbaa, [4/3] cbcb, [4/4] accb
Length 5:[5/0] ccbaa, [5/1] cbaac, [5/2] cbcba, [5/3] cbaaa, [5/4] caacb

Considering [length 3 / frequency 1] cba=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. db ⇒ cbc
2. cba ⇒ d
3. cbdac ⇒ a
4. ab ⇒ c
5. cdacb ⇒ a
6. ddacb ⇒ cbcdac
7. cbdad ⇒ ca
8. cbcdad ⇒ da
9. cbdcdad ⇒ cdac
10. cbcdcdad ⇒ ddac
11. aa ⇒ cdad
12. cbcdaca ⇒ ddad
13. cbdcdaca ⇒ ccdadd
14. adac ⇒ cdcdad
15. adad ⇒ cdaca
16. acdad ⇒ cdada
17. adcdad ⇒ cdacdac
18. acdaca ⇒ cdaddad
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] ad, [2/1] cb, [2/2] da, [2/3] ac, [2/4] cd
Length 3:[3/0] dad, [3/1] cda, [3/2] dac, [3/3] cbd, [3/4] aca
Length 4:[4/0] cdad, [4/1] daca, [4/2] cbcd, [4/3] cdac, [4/4] acda
Length 5:[5/0] cdaca, [5/1] dcdad, [5/2] cbcda, [5/3] cbdcd, [5/4] acdac

Considering [length 4 / frequency 1] daca=e.

Step 4

Rewriting system is complete. See a, b | abbabbaaab=a.