Morphocompletion for #3814 ⟨a, b | abbababaab=a⟩

Solved by morph:6/1,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbab ⇒ abbababa
2. aabaabb ⇒ aaabbba
3. aababaab ⇒ abababaa
4. abababaab ⇒ abbababaa
5. abbababaab ⇒ a
6. aaabbaabb ⇒ aaababbba
7. aaabbbbababaa ⇒ aaab
8. aaabbbbbababaa ⇒ aaabb
9. abbabababbababa ⇒ aaabbb
10. abbabababababaa ⇒ aabaab
...

Collecting factors up to length 7 / frequency 4:

[2/0]ab43lf:35,lp:4,ls:4,rf:17,rp:3,rs:2,lprp:1,lsrp:3,lprs:1
[2/1]ba30lf:29,ls:1,rf:13,rs:3
[2/2]aa27lf:18,lp:6,ls:3,rf:14,rp:6,rs:2,lprp:4,lsrp:3,lprs:1
[2/3]bb18lf:16,ls:2,rf:9,rs:2
[3/0]aba23lf:21,lp:1,ls:1,rf:9,rp:1,rs:1
[3/1]bab21lf:20,ls:1,rf:7
[3/2]aab16lf:11,lp:2,ls:3,rf:7,rp:1,rs:2
[3/3]abb15lf:10,lp:3,ls:2,rf:6,rp:2,rs:1
[4/0]baba19lf:18,ls:1,rf:6,rs:1
[4/1]abab14lf:13,lp:1,rf:5,rp:1
[4/2]abaa10lf:7,ls:3,rf:3,rs:2
[4/3]aaab8lf:4,lp:4,rf:5,rp:5,rs:1,re:1,lprp:3,lprs:1,a:10
[5/0]ababa14lf:12,lp:1,ls:1,rf:4,rp:1,rs:1
[5/1]babab11lf:11,rf:3
[5/2]babaa9lf:6,ls:3,rf:2,rs:2
[5/3]aaabb8lf:4,lp:4,rf:3,rp:3,rs:1,re:1,lprp:1,lprs:1,a:10
[6/0]bababa11lf:10,ls:1,rf:3,rs:1
[6/1]ababaa9lf:6,ls:3,rf:2,rs:2
[6/2]abbaba7lf:4,lp:3,rf:2,rp:2
[6/3]aaabbb6lf:3,lp:3,rf:2,rp:2,rs:1,re:1,a:10

Considering [length 6 / frequency 1] ababaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccb ⇒ cbc
2. cbcb ⇒ cbbc
3. cbbcb ⇒ c
4. acb ⇒ abc
5. abcb ⇒ abbc
6. abbcb ⇒ a
7. cbabaa ⇒ ababac
8. ababaa ⇒ c
9. cbbababac ⇒ cabaa
10. cbbabababc ⇒ cabaab
11. abbababac ⇒ aabaa
12. abbabababc ⇒ aabaab
13. cbcabaa ⇒ cababac
14. cbbcabaa ⇒ cbababac
15. abcabaa ⇒ aababac
16. abbcabaa ⇒ abababac
17. cbbcababac ⇒ ccabaa
18. abbcababac ⇒ acabaa
19. cbccabaa ⇒ ccababac
20. abccabaa ⇒ acababac
...

Collecting factors up to length 6 / frequency 7:

[2/0]ab40lf:31,lp:9,rf:25,rp:4,rs:2,lprp:2,lprs:1,a:1
[2/1]cb30lf:15,lp:9,ls:6,rf:3,rp:3,lprp:2,lsrp:11,a:2
[2/2]ba26lf:26,rf:22,a:1
[2/3]aa16lf:8,ls:8,rf:9,rp:3,rs:4,lsrp:1,a:1
[2/4]bc16lf:14,ls:2,rf:4,rs:4,a:2
[2/5]ac10lf:5,lp:1,ls:4,rf:9,rp:2,rs:7,lsrp:1,a:3
[2/6]bb10lf:10,rf:2,a:2
[3/0]aba22lf:21,lp:1,rf:21,rp:2,a:1
[3/1]baa16lf:8,ls:8,rf:6,rs:4,a:1
[3/2]bab14lf:14,rf:9,a:1
[3/3]abc10lf:5,lp:3,ls:2,rf:1,rp:1,rs:1,re:1,a:5
[3/4]abb10lf:5,lp:5,rf:1,rp:1,a:2
[3/5]cbb10lf:5,lp:5,rf:1,rp:1,a:4
[3/6]cab8lf:8,rf:7,rp:3,a:11
[4/0]abaa16lf:8,ls:8,rf:6,rs:4,a:1
[4/1]baba12lf:12,rf:9,a:1
[4/2]abab10lf:9,lp:1,rf:8,rp:2,a:1
[4/3]caba8lf:8,rf:7,rp:3,a:11
[4/4]abac8lf:4,ls:4,rf:7,rs:7,a:3
[4/5]bcab6lf:6,a:12
[4/6]abbc6lf:3,lp:3,rf:1,rp:1,rs:1,re:1,a:2
[5/0]cabaa12lf:6,ls:6,rf:4,rp:2,rs:3,re:1,a:11
[5/1]ababa8lf:7,lp:1,rf:8,rp:2,a:1
[5/2]babac8lf:4,ls:4,rf:7,rs:7,a:3
[5/3]bcaba6lf:6,a:12
[5/4]babab6lf:6,rf:2,a:9
[5/5]babaa4lf:2,ls:2,a:1
[5/6]abbca4lf:2,lp:2,a:12

Considering [length 2 / frequency 0] ab=d.

Step 3

Rewriting system is complete. See ⟨a, b | abbababaab=a⟩.