Morphocompletion for #3814 ⟨a, b | abbababaab=a

Solved by morph:6/1,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbab ⇒ abbababa
2. aabaabb ⇒ aaabbba
3. aababaab ⇒ abababaa
4. abababaab ⇒ abbababaa
5. abbababaab ⇒ a
6. aaabbaabb ⇒ aaababbba
7. aaabbbbababaa ⇒ aaab
8. aaabbbbbababaa ⇒ aaabb
9. abbabababbababa ⇒ aaabbb
10. abbabababababaa ⇒ aabaab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] abb
Length 4:[4/0] baba, [4/1] abab, [4/2] abaa, [4/3] aaab
Length 5:[5/0] ababa, [5/1] babab, [5/2] babaa, [5/3] aaabb
Length 6:[6/0] bababa, [6/1] ababaa, [6/2] abbaba, [6/3] aaabbb

Considering [length 6 / frequency 1] ababaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccb ⇒ cbc
2. cbcb ⇒ cbbc
3. cbbcb ⇒ c
4. acb ⇒ abc
5. abcb ⇒ abbc
6. abbcb ⇒ a
7. cbabaa ⇒ ababac
8. ababaa ⇒ c
9. cbbababac ⇒ cabaa
10. cbbabababc ⇒ cabaab
11. abbababac ⇒ aabaa
12. abbabababc ⇒ aabaab
13. cbcabaa ⇒ cababac
14. cbbcabaa ⇒ cbababac
15. abcabaa ⇒ aababac
16. abbcabaa ⇒ abababac
17. cbbcababac ⇒ ccabaa
18. abbcababac ⇒ acabaa
19. cbccabaa ⇒ ccababac
20. abccabaa ⇒ acababac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ab, [2/1] cb, [2/2] ba, [2/3] aa, [2/4] bc, [2/5] ac, [2/6] bb
Length 3:[3/0] aba, [3/1] baa, [3/2] bab, [3/3] abc, [3/4] abb, [3/5] cbb, [3/6] cab
Length 4:[4/0] abaa, [4/1] baba, [4/2] abab, [4/3] caba, [4/4] abac, [4/5] bcab, [4/6] abbc
Length 5:[5/0] cabaa, [5/1] ababa, [5/2] babac, [5/3] bcaba, [5/4] babab, [5/5] babaa, [5/6] abbca

Considering [length 2 / frequency 0] ab=d.

Step 3

Rewriting system is complete. See a, b | abbababaab=a.