Morphocompletion for #3813 ⟨a, b | abbabaaaab=b

Solved by morph:2/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaaabbb ⇒ babaaaab
2. abbabb ⇒ bbabab
3. abbabab ⇒ bbabaab
4. abbabaab ⇒ bbabaaab
5. abbabaaab ⇒ bbabaaaab
6. abbabaaaab ⇒ b
7. bbabababaaaab ⇒ abbb
8. bbabaababaaaab ⇒ aabbb
9. bbabaaababaaaab ⇒ aaabbb
10. bbabaaaababaaaab ⇒ aaaabbb
11. abbbbabab ⇒ bbabababb
12. abbbbabaab ⇒ bbabababab
13. abbbbabaaab ⇒ bbabababaab
14. abbbbabaaaab ⇒ bbabababaaab
15. bbabababababaaaab ⇒ abbaabbb
16. bbabababaababaaaab ⇒ abbaaabbb
17. bbabaababababaaaab ⇒ aabbaabbb
18. bbabababbbabaaaab ⇒ abbbbabb
19. bbabaababbbabaaaab ⇒ aabbbbabb
20. abbbbabbbabab ⇒ bbabababbbabb
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] bab, [3/1] aba, [3/2] aab, [3/3] bba
Length 4:[4/0] baba, [4/1] bbab, [4/2] aaab, [4/3] abab
Length 5:[5/0] bbaba, [5/1] aaaab, [5/2] babaa, [5/3] babab
Length 6:[6/0] baaaab, [6/1] bbabaa, [6/2] babaaa, [6/3] bbabab

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cbcaaac ⇒ b
3. acbcc ⇒ cbcac
4. acbcac ⇒ cbcaac
5. acbcaac ⇒ b
6. accbcc ⇒ cbcccaaaccac
7. accbcac ⇒ cbcccaaaccaac
8. bbcac ⇒ cbcc
9. bbcaac ⇒ cbcac
10. bbcaaac ⇒ cbcaac
11. bbcccaaaccac ⇒ ccbcc
12. bbcccaaaccaac ⇒ ccbcac
13. bbcccaaaccaaac ⇒ ccbcaac
14. cbb ⇒ bbcccaaac
15. cbcb ⇒ bbcc
16. bbb ⇒ cbccbcaaccaaac
17. bbcb ⇒ cbccbcaac
18. bbccbcac ⇒ cbccbcc
19. bbccbcaac ⇒ cbccbcac
20. bbcccaaaccb ⇒ ccbccbcaac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ac, [2/1] bb, [2/2] cc, [2/3] cb, [2/4] bc, [2/5] aa, [2/6] ca
Length 3:[3/0] bbc, [3/1] aac, [3/2] cbc, [3/3] caa, [3/4] bcc, [3/5] cac, [3/6] bca
Length 4:[4/0] bbcc, [4/1] aaac, [4/2] bcac, [4/3] caac, [4/4] cbca, [4/5] caaa, [4/6] bbca
Length 5:[5/0] caaac, [5/1] bbccc, [5/2] cbcac, [5/3] bcaac, [5/4] ccaaa, [5/5] bbccb, [5/6] bbcaa

Considering [length 3 / frequency 0] bbc=d.

Step 3

Rewriting system is complete. See a, b | abbabaaaab=b.