| Back: | ⟨a, b | abbaababba=b⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abbaabb ⇒ bababba |
| 2. | abbaababba ⇒ b |
| 3. | abbabababba ⇒ bababbaaabb |
| 4. | abbaababbb ⇒ bbbaababba |
| 5. | bababbaaababba ⇒ abbab |
| 6. | abbaabababbab ⇒ bbabbaaababba |
| 7. | abbabbbaababba ⇒ bababbaaababbb |
| 8. | abbababbababba ⇒ bababbaaabbabb |
| 9. | bababbaaabbababba ⇒ abbababb |
| 10. | bababbaaabbbbaababba ⇒ abbabababbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ba | 50 | lf:40,lp:3,ls:7,rf:27,rp:4,rs:3,lsrp:3 |
|---|---|---|---|
| [2/1] | ab | 48 | lf:40,lp:7,ls:1,rf:27,rp:3,rs:1 |
| [2/2] | bb | 30 | lf:28,ls:2,rf:21,rp:2,rs:5,lsrp:1 |
| [2/3] | aa | 12 | lf:12,rf:9 |
| [3/0] | abb | 32 | lf:24,lp:7,ls:1,rf:16,rp:3,rs:3,lprs:2 |
| [3/1] | bba | 29 | lf:22,ls:7,rf:13,rp:1,rs:3 |
| [3/2] | bab | 28 | lf:24,lp:3,ls:1,rf:19,rp:4,rs:1,lprs:1 |
| [3/3] | aba | 15 | lf:15,rf:10 |
| [3/4] | aab | 9 | lf:9,rf:5 |
| [3/5] | baa | 9 | lf:9,rf:5 |
| [3/6] | bbb | 5 | lf:4,ls:1,rf:3,rp:1,rs:2,lsrp:1,a:2 |
| [4/0] | abba | 34 | lf:20,lp:7,ls:7,rf:11,rp:3,rs:3,lsrp:3,lprs:3 |
| [4/1] | abab | 15 | lf:15,rf:10 |
| [4/2] | babb | 14 | lf:14,rf:11,rs:2 |
| [4/3] | baba | 12 | lf:9,lp:3,rf:7,rp:4,a:1 |
| [4/4] | bbaa | 9 | lf:9,rf:5 |
| [4/5] | bbab | 7 | lf:6,ls:1,rf:5,rp:1,rs:1,lsrp:1,a:3 |
| [4/6] | baab | 6 | lf:6,rf:1 |
| [5/0] | babba | 19 | lf:12,ls:7,rf:7,rs:3 |
| [5/1] | ababb | 13 | lf:13,rf:9,rs:1 |
| [5/2] | babab | 12 | lf:9,lp:3,rf:7,rp:4,a:1 |
| [5/3] | abbaa | 11 | lf:7,lp:4,rf:4 |
| [5/4] | abbab | 10 | lf:6,lp:3,ls:1,rf:4,rp:3,rs:1,re:1,a:3 |
| [5/5] | bbaab | 6 | lf:6,rf:1 |
| [5/6] | aabab | 6 | lf:6,rf:3 |
| [6/0] | ababba | 19 | lf:12,ls:7,rf:6,rs:3 |
| [6/1] | bababb | 11 | lf:8,lp:3,rf:6,rp:4,rs:1,lprs:1,a:1 |
| [6/2] | abbaab | 8 | lf:4,lp:4 |
| [6/3] | abbaba | 6 | lf:4,lp:2,rf:2,rp:2,a:4 |
| [6/4] | aababb | 5 | lf:5,rf:3 |
| [6/5] | baabab | 5 | lf:5,rf:1 |
| [6/6] | bbaaba | 5 | lf:5,rf:1 |
| [7/0] | bababba | 14 | lf:8,lp:3,ls:3,rf:4,rp:4,rs:1,re:1,lsrp:2,a:1 |
| [7/1] | aababba | 8 | lf:4,ls:4,rf:2,rs:2 |
| [7/2] | abbabab | 6 | lf:4,lp:2,rf:2,rp:2,a:4 |
| [7/3] | abbaaba | 6 | lf:3,lp:3 |
| [7/4] | bbaabab | 5 | lf:5,rf:1 |
| [7/5] | baababb | 4 | lf:4,rf:1 |
| [7/6] | bbababb | 3 | lf:3,rf:1,rs:1,a:7 |
Considering [length 5 / frequency 0] babba=c.
Rewriting system is complete. See ⟨a, b | abbaababba=b⟩.