Morphocompletion for #3806 ⟨a, b | abbaabaaab=b⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbb ⇒ baabaab
2. aaaabbab ⇒ baabaaab
3. abbaabb ⇒ bbaabab
4. abbaabab ⇒ bbaabaab
5. abbaabaab ⇒ bbaabaaab
6. abbaabaaab ⇒ b
7. aaaabbabbb ⇒ baabaaabbb
8. aaaabbabbab ⇒ baabaaabbab
9. aaaabbaaabbb ⇒ baababaabaab
10. aaaabbaaabbab ⇒ baababaabaaab
11. bbaababaabaab ⇒ abbb
12. bbaababaabaaab ⇒ abbab
13. bbaabaabaabaab ⇒ aabbb
14. bbaabaabaabaaab ⇒ aabbab
15. bbaabaaabaabaab ⇒ aaabbb
16. bbaabaaabaabaaab ⇒ aaabbab
17. abbbbaabaab ⇒ bbaababaabb
18. abbbbaabaaab ⇒ bbaababaabab
19. baabaabaababaabaab ⇒ aaaababbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab81lf:60,lp:6,ls:15,rf:41,rp:2,rs:12,lsrp:2,lprs:4,lsrs:9
[2/1]aa72lf:66,lp:6,rf:37,rp:5
[2/2]ba49lf:48,lp:1,rf:34,rp:6
[2/3]bb40lf:30,lp:6,ls:4,rf:20,rp:5,rs:6,lsrp:1,lprs:3,lsrs:1
[3/0]aab56lf:45,ls:11,rf:28,rp:2,rs:6,lsrp:2,lsrs:1
[3/1]baa40lf:39,lp:1,rf:23,rp:6
[3/2]aba28lf:28,rf:19
[3/3]aaa27lf:21,lp:6,rf:9,rp:3
[3/4]bba25lf:19,lp:6,rf:9,rp:5
[3/5]abb24lf:17,lp:6,ls:1,rf:10,rp:2,rs:1,lprs:1
[3/6]bab13lf:9,ls:4,rf:11,rs:6,lsrs:1,a:2
[4/0]baab37lf:30,lp:1,ls:6,rf:18,rp:6,rs:3
[4/1]aaba25lf:25,rf:15
[4/2]abaa24lf:24,rf:12
[4/3]bbaa20lf:14,lp:6,rf:5,rp:5
[4/4]aaab20lf:15,ls:5,rf:8,rp:2,rs:3,lsrp:1
[4/5]abba15lf:11,lp:4,rf:4,rp:1
[4/6]aaaa12lf:6,lp:6,rf:1,rp:1,a:16
[5/0]baaba24lf:23,lp:1,rf:14,rp:6
[5/1]abaab23lf:17,ls:6,rf:7,rs:3,a:1
[5/2]aabaa21lf:21,rf:8
[5/3]bbaab18lf:12,lp:6,rf:5,rp:5
[5/4]baaab14lf:9,ls:5,rf:5,rs:3
[5/5]aaaab12lf:6,lp:6,rf:1,rp:1,a:16
[5/6]abbaa10lf:6,lp:4
[6/0]aabaab20lf:14,ls:6,rf:3,rs:3,a:1
[6/1]baabaa20lf:19,lp:1,rf:8,rp:4
[6/2]bbaaba17lf:11,lp:6,rf:5,rp:5
[6/3]aaaabb12lf:6,lp:6,a:16
[6/4]abaaab12lf:7,ls:5,rf:5,rs:3
[6/5]abaaba11lf:11,rf:3,a:4
[6/6]abbaab8lf:4,lp:4
[7/0]baabaab19lf:12,lp:1,ls:6,rf:3,rp:1,rs:3,re:1,a:1
[7/1]bbaabaa12lf:8,lp:4,rf:2,rp:2
[7/2]aabaaab12lf:7,ls:5,rf:5,rs:3
[7/3]aaaabba10lf:5,lp:5,a:20
[7/4]abaabaa10lf:10,rf:2,a:4
[7/5]aabaaba8lf:8,a:8
[7/6]baabaaa7lf:7,rf:5,rp:3

Considering [length 3 / frequency 0] aab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbaabaaab=b⟩.