Morphocompletion for #3806 ⟨a, b | abbaabaaab=b

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbb ⇒ baabaab
2. aaaabbab ⇒ baabaaab
3. abbaabb ⇒ bbaabab
4. abbaabab ⇒ bbaabaab
5. abbaabaab ⇒ bbaabaaab
6. abbaabaaab ⇒ b
7. aaaabbabbb ⇒ baabaaabbb
8. aaaabbabbab ⇒ baabaaabbab
9. aaaabbaaabbb ⇒ baababaabaab
10. aaaabbaaabbab ⇒ baababaabaaab
11. bbaababaabaab ⇒ abbb
12. bbaababaabaaab ⇒ abbab
13. bbaabaabaabaab ⇒ aabbb
14. bbaabaabaabaaab ⇒ aabbab
15. bbaabaaabaabaab ⇒ aaabbb
16. bbaabaaabaabaaab ⇒ aaabbab
17. abbbbaabaab ⇒ bbaababaabb
18. abbbbaabaaab ⇒ bbaababaabab
19. baabaabaababaabaab ⇒ aaaababbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] aaa, [3/4] bba, [3/5] abb, [3/6] bab
Length 4:[4/0] baab, [4/1] aaba, [4/2] abaa, [4/3] bbaa, [4/4] aaab, [4/5] abba, [4/6] aaaa
Length 5:[5/0] baaba, [5/1] abaab, [5/2] aabaa, [5/3] bbaab, [5/4] baaab, [5/5] aaaab, [5/6] abbaa
Length 6:[6/0] aabaab, [6/1] baabaa, [6/2] bbaaba, [6/3] aaaabb, [6/4] abaaab, [6/5] abaaba, [6/6] abbaab
Length 7:[7/0] baabaab, [7/1] bbaabaa, [7/2] aabaaab, [7/3] aaaabba, [7/4] abaabaa, [7/5] aabaaba, [7/6] baabaaa

Considering [length 3 / frequency 0] aab=c.

Step 2

Rewriting system is complete. See a, b | abbaabaaab=b.