Morphocompletion for #3805 ⟨a, b | abbaabaaab=a

Solved by morph:2/1,2/0,5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbb ⇒ abbaaba
2. aaabaaab ⇒ abaabaaa
3. abaabaaab ⇒ abbaabaaa
4. abbaabaaab ⇒ a
5. aaaabbaaabbb ⇒ abbaababaaba
6. abbaababaabaaa ⇒ aaaab
7. abbaababbaabaaa ⇒ aaaabb
8. abaabaaaaaab ⇒ aaababaabaaa
9. abbaabaaaaaab ⇒ abaababaabaaa
10. aaaababbbbaabaaa ⇒ aaaabab
11. abbaababaababbaaba ⇒ aaaababbb
...

Collecting factors up to length 7, frequency 3:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba
Length 3:[3/0] aaa, [3/1] aab, [3/2] aba
Length 4:[4/0] aaab, [4/1] aaba, [4/2] abaa
Length 5:[5/0] baaba, [5/1] abbaa, [5/2] abaaa
Length 6:[6/0] abbaab, [6/1] aabaaa, [6/2] bbaaba

Considering [length 2 / frequency 1] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cbacaac ⇒ a
3. cacaacb ⇒ a
4. aaacbb ⇒ cbaca
5. cacaaccbb ⇒ cbaccbaca
6. aaaccbbb ⇒ cbaccaccbacc
7. cbacaaa ⇒ cacaac
8. cbaccaccbaca ⇒ aaaccbb
9. cbaccbaccbaca ⇒ aaacbcbb
10. aacaac ⇒ cacaaa
11. cbaccacaac ⇒ aaacb
12. aaaccbbac ⇒ cbaccaca
13. aaacbcbbac ⇒ cbaccbaca
14. cacaacacbb ⇒ cbacacbaca
15. cbaccacaaa ⇒ aaac
16. aaacbcbbaa ⇒ cacaaccb
17. aaacbaacb ⇒ aaaccbbaa
18. aaaccbaacb ⇒ aaacccbbaa
19. cacaaaaac ⇒ aaccacaaa
20. cacaacacaac ⇒ aacaaa
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] ac, [2/1] aa, [2/2] cb, [2/3] ca, [2/4] ba
Length 3:[3/0] aac, [3/1] aaa, [3/2] aca, [3/3] cba, [3/4] cac
Length 4:[4/0] aaac, [4/1] cbac, [4/2] caca, [4/3] caac, [4/4] acaa
Length 5:[5/0] cacaa, [5/1] acaac, [5/2] cbacc, [5/3] aaacb, [5/4] cbaca

Considering [length 2 / frequency 0] ac=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cbdad ⇒ a
3. ddadb ⇒ dbdad
4. dbdadb ⇒ d
5. cdadb ⇒ a
6. dbdaddb ⇒ cbdcdad
7. ac ⇒ d
8. ddadc ⇒ dbddbdadd
9. dbdadc ⇒ ad
10. cdadc ⇒ cbddbdadd
11. dbdaddc ⇒ cbdcddbdadd
12. aa ⇒ dbdad
13. dbddbdada ⇒ ddad
14. cbddbdada ⇒ cdad
15. cbdcddbdada ⇒ dbdadd
16. adad ⇒ cddbdada
17. dbdaddad ⇒ dddbdada
18. adbdad ⇒ dbdada
19. addbdada ⇒ cdaddad
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] ad, [2/1] da, [2/2] db, [2/3] bd, [2/4] dd
Length 3:[3/0] dad, [3/1] dbd, [3/2] bda, [3/3] ada, [3/4] adb
Length 4:[4/0] dbda, [4/1] bdad, [4/2] dada, [4/3] dadc, [4/4] dadb
Length 5:[5/0] dbdad, [5/1] bdada, [5/2] ddbda, [5/3] bdadd, [5/4] addad

Considering [length 5 / frequency 1] bdada=e.

Step 4

Rewriting system is complete. See a, b | abbaabaaab=a.