Morphocompletion for #3802 ⟨a, b | abbaaabaab=b⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbbb ⇒ abbbab
2. bbaaabb ⇒ aabbbab
3. aabbbabb ⇒ baabbbab
4. aaabbb ⇒ baaabb
5. abbaaabab ⇒ bbaaabaab
6. abbaaabaab ⇒ b
7. bbaaababaaabb ⇒ abbb
8. bbaaababaaabab ⇒ abbab
9. bbaaabaabaaabb ⇒ aabbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa27lf:24,lp:3,rf:8,rp:2
[2/1]bb27lf:17,lp:4,ls:6,rf:13,rp:1,rs:3,lprs:2,lsrs:3
[2/2]ab26lf:21,lp:2,ls:3,rf:13,rp:3,rs:5,lsrp:1,lprs:1,lsrs:2
[2/3]ba16lf:16,rf:8,rp:2
[3/0]aab17lf:14,lp:2,ls:1,rf:6,rp:2,rs:1
[3/1]abb15lf:9,lp:2,ls:4,rf:7,rp:3,rs:1,lsrp:1
[3/2]aaa11lf:10,lp:1,rf:2
[3/3]baa11lf:11,rf:4,rp:2
[3/4]bba11lf:7,lp:4,rf:5,rp:1
[3/5]aba9lf:9,rf:1
[3/6]bab7lf:5,ls:2,rf:4,rs:4,lsrs:1,a:1
[4/0]aaab11lf:10,lp:1,rf:2
[4/1]aabb11lf:6,lp:2,ls:3,rf:4,rp:2,rs:1,lsrp:2,a:5
[4/2]bbaa10lf:6,lp:4,rf:1,rp:1
[4/3]baaa9lf:9,rf:2,rp:1
[4/4]aaba7lf:7,rf:1
[4/5]abab6lf:4,ls:2,a:1
[4/6]abaa5lf:5,rf:1
[5/0]bbaaa10lf:6,lp:4,rf:1,rp:1
[5/1]baaab9lf:9,rf:2,rp:1
[5/2]aaabb8lf:4,lp:1,ls:3,rf:1,rs:1,lprs:10,a:5
[5/3]aaaba6lf:6,rf:1
[5/4]aabab6lf:4,ls:2,a:1
[5/5]aabbb6lf:3,lp:2,ls:1,rf:3,rp:2,rs:1,re:1,a:6
[5/6]abbaa4lf:2,lp:2
[6/0]bbaaab10lf:6,lp:4,rf:1,rp:1
[6/1]aaabab6lf:4,ls:2,a:1
[6/2]baaaba6lf:6,rf:1
[6/3]baaabb6lf:3,ls:3,rf:1,rp:1,rs:1,re:1,a:5
[6/4]abbaaa4lf:2,lp:2
[6/5]aabaab3lf:2,ls:1,rf:1,rs:1
[6/6]abaaab3lf:3,a:4
[7/0]bbaaaba8lf:5,lp:3,rf:1,rp:1
[7/1]baaabab6lf:4,ls:2,a:1
[7/2]abaaabb4lf:2,ls:2,a:5
[7/3]abbaaab4lf:2,lp:2
[7/4]aaabaab3lf:2,ls:1,rf:1,rs:1
[7/5]aaababa2lf:2,a:4
[7/6]aababaa2lf:2,a:4

Considering [length 4 / frequency 0] aaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbaaabaab=b⟩.