Morphocompletion for #3791 ⟨a, b | ababbbbaab=a

Solved by morph:7/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaabba ⇒ aaabbab
2. aabbbba ⇒ abbaabb
3. abbaabba ⇒ aaabbabb
4. ababbbba ⇒ abbbaabb
5. abbbaabba ⇒ aaabbabbb
6. aaabbabbbb ⇒ a
7. aaabbbbbaabba ⇒ aaab
8. aaabbabbabbbba ⇒ aaabb
9. aaababbbbbaabba ⇒ aaabab
10. abaabbbbbaabba ⇒ abaab
11. aaabbabbbabbbba ⇒ abaabb
12. abbaabbbbbaabba ⇒ abbaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] ab, [2/3] aa
Length 3:[3/0] bba, [3/1] abb, [3/2] bbb, [3/3] aab, [3/4] aaa, [3/5] baa, [3/6] bab
Length 4:[4/0] abba, [4/1] aabb, [4/2] bbbb, [4/3] bbba, [4/4] abbb, [4/5] aaab, [4/6] baab
Length 5:[5/0] aabba, [5/1] bbbba, [5/2] abbbb, [5/3] baabb, [5/4] aaabb, [5/5] bbaab, [5/6] babbb
Length 6:[6/0] baabba, [6/1] abbbba, [6/2] bbaabb, [6/3] babbbb, [6/4] aaabba, [6/5] bbbaab, [6/6] aabbbb
Length 7:[7/0] bbaabba, [7/1] babbbba, [7/2] aaabbab, [7/3] bbbaabb, [7/4] bbabbbb, [7/5] bbbbbaa, [7/6] abbbbba

Considering [length 7 / frequency 1] babbbba=c.

Step 2

Rewriting system is complete. See a, b | ababbbbaab=a.