Morphocompletion for #3787 ⟨a, b | ababbbaaab=a

Solved by morph:4/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaabba ⇒ aaaabbab
2. aabbbaa ⇒ abaaabb
3. abbaaabba ⇒ aaaabbabb
4. ababbbaa ⇒ abbaaabb
5. aaaabbabbb ⇒ a
6. aaaabbbbaaabba ⇒ aaaab
7. aaaabbaabbabbba ⇒ aaaabb
8. abaaabbbbaaabba ⇒ abaaab
9. aaaabbabbabbbaa ⇒ aaaabb
10. aaaabbababbabbb ⇒ aabbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] bb, [2/2] ab, [2/3] ba
Length 3:[3/0] bba, [3/1] abb, [3/2] aaa, [3/3] aab, [3/4] bbb, [3/5] baa, [3/6] bab
Length 4:[4/0] abba, [4/1] aabb, [4/2] abbb, [4/3] bbaa, [4/4] aaab, [4/5] aaaa, [4/6] bbba
Length 5:[5/0] aabba, [5/1] aaabb, [5/2] aaaab, [5/3] bbbaa, [5/4] babbb, [5/5] abbab, [5/6] bbabb
Length 6:[6/0] aaabba, [6/1] aaaabb, [6/2] bbabbb, [6/3] abbbaa, [6/4] abbabb, [6/5] baaabb, [6/6] babbba
Length 7:[7/0] baaabba, [7/1] aaaabba, [7/2] abbabbb, [7/3] babbbaa, [7/4] abaaabb, [7/5] bbabbba, [7/6] bbaaabb

Considering [length 4 / frequency 2] abbb=c.

Step 2

Rewriting system is complete. See a, b | ababbbaaab=a.