Morphocompletion for #3772 ⟨a, b | abababbaab=a

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaab ⇒ abaabba
2. aaabbab ⇒ aababba
3. abaabbab ⇒ abababba
4. aabbaaab ⇒ abaaabba
5. aababbaab ⇒ abababbaa
6. abababbaab ⇒ a
7. aabbaaaab ⇒ abaaaabba
8. aababbabaabba ⇒ aaab
9. abababbabaabba ⇒ abaab
10. aababbabababba ⇒ aaabb
11. aaabbbababbaab ⇒ aaabb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aab, [3/1] bab, [3/2] bba, [3/3] aba, [3/4] abb, [3/5] baa, [3/6] aaa
Length 4:[4/0] abba, [4/1] abab, [4/2] aabb, [4/3] baab, [4/4] aaab, [4/5] bbab, [4/6] baba
Length 5:[5/0] aabba, [5/1] bbaab, [5/2] babba, [5/3] ababb, [5/4] abbab, [5/5] aabab, [5/6] abbaa
Length 6:[6/0] abbaab, [6/1] ababba, [6/2] aabbaa, [6/3] aababb, [6/4] ababab, [6/5] baabba, [6/6] abaabb
Length 7:[7/0] aababba, [7/1] abaabba, [7/2] babbaab, [7/3] abababb, [7/4] bababba, [7/5] aabbaaa, [7/6] ababbaa

Considering [length 4 / frequency 0] abba=c.

Step 2

Rewriting system is complete. See a, b | abababbaab=a.