Morphocompletion for #3768 ⟨a, b | abababaaab=b⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabb ⇒ baaab
2. aaababb ⇒ babaaab
3. aaabaabb ⇒ baabaaab
4. abababab ⇒ bababaab
5. abababaab ⇒ bababaaab
6. abababaaab ⇒ b
7. bababaabaaab ⇒ abb
8. bababaaabaaab ⇒ aabb
9. abababbaaab ⇒ bb
10. bababaabbaaab ⇒ abbb
11. abababbbaaab ⇒ bbb
12. abababbabaaab ⇒ babb
13. abababbbbaaab ⇒ bbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab63lf:46,lp:7,ls:10,rf:15,rp:2,rs:5,lsrp:2,lprs:2,lsrs:2
[2/1]ba39lf:36,lp:3,rf:12,rp:6
[2/2]aa31lf:28,lp:3,rf:11,rp:1
[2/3]bb14lf:11,ls:3,rf:11,rp:3,rs:7,re:1,a:3
[3/0]aba35lf:28,lp:7,rf:6
[3/1]bab27lf:23,lp:3,ls:1,rf:6,rp:4,lsrp:1
[3/2]aab25lf:16,ls:9,rf:7,rp:1,rs:5,lsrp:1,lsrs:1
[3/3]aaa15lf:12,lp:3,rf:4
[3/4]baa13lf:13,rf:6,rp:2
[3/5]abb11lf:8,ls:3,rf:4,rp:2,rs:3,re:1,a:3
[3/6]bba5lf:5,a:10
[4/0]abab27lf:19,lp:7,ls:1,rf:2
[4/1]aaab23lf:12,lp:3,ls:8,rf:4,rs:4,lprs:12
[4/2]baba20lf:17,lp:3,rf:5,rp:3
[4/3]abaa9lf:9,rf:4
[4/4]baaa9lf:9,rf:4,rp:1
[4/5]babb6lf:5,ls:1,rf:1,rp:1,rs:1,re:1,a:10
[4/6]aabb5lf:3,ls:2,rf:1,rp:1,rs:1,re:1,a:6
[5/0]ababa20lf:13,lp:7,rf:2
[5/1]baaab17lf:9,ls:8,rf:4,rp:1,rs:4,re:1
[5/2]babab15lf:11,lp:3,ls:1,rf:2,rp:2,lsrp:1
[5/3]ababb6lf:5,ls:1,a:10
[5/4]babaa6lf:6,rf:3,rp:1
[5/5]abaab5lf:4,ls:1,rf:1,rs:1,a:1
[5/6]aaaba5lf:3,lp:2,a:6
[6/0]ababab16lf:8,lp:7,ls:1
[6/1]bababa9lf:6,lp:3,rf:2,rp:2
[6/2]abaaab9lf:5,ls:4,rf:3,rs:3
[6/3]bbaaab8lf:4,ls:4,a:10
[6/4]ababaa5lf:5,rf:2
[6/5]bababb4lf:4,a:10
[6/6]babaab4lf:3,ls:1,rf:1,rs:1,a:1
[7/0]abababb8lf:4,lp:4,a:10
[7/1]bababaa8lf:5,lp:3,rf:2,rp:2
[7/2]abababa6lf:3,lp:3
[7/3]babaaab5lf:3,ls:2,rf:2,rp:1,rs:2,re:1
[7/4]bbbaaab4lf:2,ls:2,a:17
[7/5]ababaab4lf:3,ls:1,rf:1,rs:1,a:1
[7/6]abbaaab4lf:2,ls:2,a:10

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abababaaab=b⟩.