Morphocompletion for #3768 ⟨a, b | abababaaab=b

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabb ⇒ baaab
2. aaababb ⇒ babaaab
3. aaabaabb ⇒ baabaaab
4. abababab ⇒ bababaab
5. abababaab ⇒ bababaaab
6. abababaaab ⇒ b
7. bababaabaaab ⇒ abb
8. bababaaabaaab ⇒ aabb
9. abababbaaab ⇒ bb
10. bababaabbaaab ⇒ abbb
11. abababbbaaab ⇒ bbb
12. abababbabaaab ⇒ babb
13. abababbbbaaab ⇒ bbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] aaa, [3/4] baa, [3/5] abb, [3/6] bba
Length 4:[4/0] abab, [4/1] aaab, [4/2] baba, [4/3] abaa, [4/4] baaa, [4/5] babb, [4/6] aabb
Length 5:[5/0] ababa, [5/1] baaab, [5/2] babab, [5/3] ababb, [5/4] babaa, [5/5] abaab, [5/6] aaaba
Length 6:[6/0] ababab, [6/1] bababa, [6/2] abaaab, [6/3] bbaaab, [6/4] ababaa, [6/5] bababb, [6/6] babaab
Length 7:[7/0] abababb, [7/1] bababaa, [7/2] abababa, [7/3] babaaab, [7/4] bbbaaab, [7/5] ababaab, [7/6] abbaaab

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See a, b | abababaaab=b.