| Back: | ⟨a, b | ababaabaab=b⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababab ⇒ baaabb |
| 2. | aababb ⇒ baabab |
| 3. | ababaabb ⇒ babaabab |
| 4. | ababaabab ⇒ babaabaab |
| 5. | ababaabaab ⇒ b |
| 6. | baabaabaabaab ⇒ aabb |
| 7. | ababbaabab ⇒ babaabaabb |
| 8. | babaabaabaabab ⇒ ababb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 40 | lf:29,lp:5,ls:6,rf:15,rp:1,rs:3,lsrp:1,lprs:2,lsrs:1 |
|---|---|---|---|
| [2/1] | ba | 25 | lf:23,lp:2,rf:13,rp:5 |
| [2/2] | aa | 14 | lf:13,lp:1,rf:9,rp:1 |
| [2/3] | bb | 5 | lf:3,ls:2,rf:4,rs:4,a:3 |
| [3/0] | aba | 25 | lf:20,lp:5,rf:8,rp:1 |
| [3/1] | bab | 16 | lf:11,lp:1,ls:4,rf:6,rp:3,rs:2,lsrp:2 |
| [3/2] | aab | 16 | lf:13,lp:1,ls:2,rf:8,rp:1,rs:1,lsrp:1 |
| [3/3] | baa | 13 | lf:12,lp:1,rf:7,rp:2 |
| [3/4] | abb | 5 | lf:3,ls:2,rf:4,rs:4,a:3 |
| [3/5] | bba | 1 | lf:1,a:8 |
| [3/6] | aaa | 0 | rf:1,a:38 |
| [4/0] | abab | 19 | lf:10,lp:5,ls:4,rf:3,rp:1,rs:2,lsrp:1,lprs:1 |
| [4/1] | baab | 15 | lf:12,lp:1,ls:2,rf:6,rp:1,rs:1 |
| [4/2] | aaba | 11 | lf:10,lp:1,rf:4 |
| [4/3] | abaa | 10 | lf:10,rf:5 |
| [4/4] | baba | 6 | lf:5,lp:1,rf:3,rp:3 |
| [4/5] | babb | 3 | lf:2,ls:1,rf:1,rs:1,a:4 |
| [4/6] | aabb | 2 | lf:1,ls:1,rf:3,rp:1,rs:3,re:1,a:3 |
| [5/0] | abaab | 12 | lf:10,ls:2,rf:5,rs:1 |
| [5/1] | baaba | 10 | lf:9,lp:1,rf:4,rp:1 |
| [5/2] | aabab | 8 | lf:4,lp:1,ls:3,rf:2,rs:2,lprs:10,a:1 |
| [5/3] | ababa | 8 | lf:4,lp:4 |
| [5/4] | aabaa | 6 | lf:6,rf:2 |
| [5/5] | babaa | 5 | lf:4,lp:1,rf:3,rp:3 |
| [5/6] | ababb | 4 | lf:2,lp:1,ls:1,rf:1,rp:1,rs:1,re:1,a:4 |
| [6/0] | aabaab | 8 | lf:6,ls:2,rf:2,rs:1 |
| [6/1] | abaaba | 7 | lf:7,rf:3 |
| [6/2] | baabaa | 7 | lf:6,lp:1,rf:2 |
| [6/3] | baabab | 6 | lf:3,ls:3,rf:2,rp:1,rs:2,re:1,a:1 |
| [6/4] | ababaa | 6 | lf:3,lp:3 |
| [6/5] | babaab | 5 | lf:4,lp:1,rf:3,rp:3 |
| [6/6] | abaabb | 2 | lf:1,ls:1,rf:1,rs:1,a:3 |
| [7/0] | baabaab | 9 | lf:6,lp:1,ls:2,rf:2,rs:1 |
| [7/1] | ababaab | 6 | lf:3,lp:3 |
| [7/2] | abaabaa | 5 | lf:5,rf:2 |
| [7/3] | abaabab | 4 | lf:2,ls:2,rf:1,rs:1,a:1 |
| [7/4] | babaaba | 4 | lf:3,lp:1,rf:3,rp:3 |
| [7/5] | aabaaba | 4 | lf:4,a:4 |
| [7/6] | babaabb | 2 | lf:1,ls:1,a:3 |
Considering [length 3 / frequency 0] aba=c.
Rewriting system is complete. See ⟨a, b | ababaabaab=b⟩.