Morphocompletion for #3762 ⟨a, b | ababaabaab=b⟩

Back:⟨a, b | ababaabaab=b⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababab ⇒ baaabb
2. aababb ⇒ baabab
3. ababaabb ⇒ babaabab
4. ababaabab ⇒ babaabaab
5. ababaabaab ⇒ b
6. baabaabaabaab ⇒ aabb
7. ababbaabab ⇒ babaabaabb
8. babaabaabaabab ⇒ ababb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] baa, [3/4] abb, [3/5] bba, [3/6] aaa
Length 4:[4/0] abab, [4/1] baab, [4/2] aaba, [4/3] abaa, [4/4] baba, [4/5] babb, [4/6] aabb
Length 5:[5/0] abaab, [5/1] baaba, [5/2] aabab, [5/3] ababa, [5/4] aabaa, [5/5] babaa, [5/6] ababb
Length 6:[6/0] aabaab, [6/1] abaaba, [6/2] baabaa, [6/3] baabab, [6/4] ababaa, [6/5] babaab, [6/6] abaabb
Length 7:[7/0] baabaab, [7/1] ababaab, [7/2] abaabaa, [7/3] abaabab, [7/4] babaaba, [7/5] aabaaba, [7/6] babaabb

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababaabaab=b⟩.